2*3x = 10* 312 + 8 * 274
làm nhanh hộ mk
mn ơi tính hộ mk bài tìm x với mk đang cần gấp::2 x 3X + 1=10 x 312 + 8 x 312
\(2.3^{x+1}=10.3^{12}+8.3^{12}\\ \Rightarrow2.3^{x+1}=3^{12}\left(10+8\right)\\ \Rightarrow2.3^{x+1}=3^{12}.18\\ \Rightarrow3^{x+1}=9.3^{12}\\ \Rightarrow3^{x+1}=3^{14}\\ \Rightarrow x+1=14\\ \Rightarrow x=13\)
2*3x= 10 *312+8*274
\(2.3^x=10.3^{12}+8.27^4\)
\(2.3^x=10.3^{12}+8.\left(3^3\right)^4\)
\(2.3^x=18.3^{12}\)
\(3^x=9.3^{12}=3^{14}\)
\(x=14\)
2.3ˣ = 10.3¹² + 8.27⁴
2.3ˣ = 10.3¹² + 8.(3³)⁴
2.3ˣ = 10.3¹² + 8.3¹²
2.3ˣ = 3¹².(10 + 8)
2.3ˣ = 3¹².18
3ˣ = 3¹².18 : 2
3ˣ = 3¹² . 9
3ˣ = 3¹² . 3²
3ˣ = 3¹⁴
x = 14
1) [ 462 + 2 ( 312 - x ) ] : 2 - 31 = 500
2) [ 982 - 2 ( x + 83 ) ] : 2 - 36 = 300
3) 2 . [ 3 . ( 2x - 4 ) + 10 ]+ 15 = 75
4) 3 . [ 2 . ( 3x + 9 ) - 15 ] - 9 = 69
ai nhanh mk tick !!!!!!!
1, => [ 462 + 642 - 2x ] : 2 = 531
1104 -2x = 1062
2x = 42
x =21
2, ≫ [ 982 -2x -166 ] : 2 =336
816 - 2x = 672
2x=144
x=72
tính nhanh
a) \(\dfrac{4}{9}\) x \(\dfrac{3}{5}\) + \(\dfrac{4}{9}\) x \(\dfrac{8}{5}\) - \(\dfrac{4}{9}\) x \(\dfrac{2}{10}\)
b) 312 : 13 + 325 : 13 - 247 : 13
( ghi chi tiết giúp mk ạ )
a) 4/9 x ( 3/5 + 8/5 - 2/10 )
= 4/9 x 1
=4/9
b) ( 312 + 325 - 247 ) : 13
= 390 : 13
= 30
a)4/9 x 3/5 + 4/9 x 8/5 - 4/9 x 2/10
=4/9x(3/5+8/5-2/10)
= 4/9x1
=4/9
b,312 : 13 + 325 : 13 - 247 : 13
=(312+325-247) : 13
= 390 : 3
= 130
Bài 5.Tìm x N, sao cho:
a)3636 : (12x –91) = 36
b)(x : 23 + 45) . 67 = 8911
c)[(6x –39) : 7]. 4 = 12
d)(3x –24). 73= 2. 74
e)x(x –10) = 0
f)(x+ 1). (x –2) = 0
g)(9 –x)3= 64
h)3x= 81
i)2 . 3x= 10 . 312+ 8 . 312
j)(19x + 2.52) : 14 = (13 -8)2-42
\(a,\Rightarrow12x-91=101\\ \Rightarrow12x=192\\ \Rightarrow x=16\\ b,\Rightarrow x:23+45=133\\ \Rightarrow x:23=88\\ \Rightarrow x=\dfrac{88}{23}\\ c,\Rightarrow\left(6x-39\right):7=3\\ \Rightarrow6x-39=21\\ \Rightarrow6x=60\\ \Rightarrow x=10\\ d,\Rightarrow3x-24=\dfrac{148}{73}\\ \Rightarrow3x=\dfrac{1900}{73}\\ \Rightarrow x=\dfrac{1900}{219}\\ e,\Rightarrow\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\\ f,\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\\ d,\left(9-x\right)^3=64=4^3\\ \Rightarrow9-x=4\\ \Rightarrow x=5\\ h,\Rightarrow x=27\\ i,\Rightarrow6x=312\cdot12=624\cdot6\\ \Rightarrow x=624\\ j,\Rightarrow\left(19x+104\right):14=25-42=-17\\ \Rightarrow19x+104=-238\\ \Rightarrow19x=-342\\ \Rightarrow x=-18\)
Làm nhanh hộ mk bài này nha , mk cần gấp lắm . Mk sẽ tk cho 5 bạn nhanh nhất ( đúng nhất )
Tính nhanh : 1/2 : 0,5 - 1/4 : 0,25 - 1/8 - 0,125 : 1/10 - 0,1
1/2 : 0,5 - 1/4 : 0,25 - 1/8 - 0,125 : 1/10 - 0,1 = 1/2 : 1/2 - 1/4 : 1/4 - 1/8 - 1/8 : 1/10 - 1/10 .
= 1 - 1 - 1/8 - 1/10 : ( 1/8 - 1 ) .
= 0 - 1/8 - 1/10 : ( -7/8 ) .
= -7/8 - 1/10 : ( -7/8 ) .
= -7/8 : ( 1 - 1/10 ) .
= -7/8 : 9/10 .
= -7/8 . 10/9 .
= -35/36 .
\(\frac{x^2+3x-5}{x+3}\)
Ai nhanh mk tick nhé!Nhanh hộ mk nha
Tìm X: 9(x + 1)^2-(3x-2)(3x+2)=10
Giải nhanh hộ mình!!
Ta có : 9(x + 1)2 - (3x - 2)(3x + 2) = 10
=> 9(x2 + 2x + 1) - (9x2 - 4) = 10
=> 9x2 + 18x + 9 - 9x2 + 4 = 10
=> 9x2 - 9x2 + 18x + 13 = 10
=> 18x = 10 - 13
=> 18x = -3
=> x = \(-\frac{1}{6}\)
Tìm X: 9(x + 1)^2-(3x-2)(3x+2)=10
Giải nhanh hộ mình!!
Ta có : 9(x + 1)2 - (3x - 2)(3x + 2) = 10
=> 9(x2 + 2x + 1) - (9x2 - 4) = 10
=> 9x2 + 18x + 9 - 9x2 + 4 = 10
=> 9x2 - 9x2 + 18x + 13 = 10
=> 18x = 10 - 13
=> 18x = -3
=> x = \(-\frac{1}{6}\)