x^2+6xy+9y^2-3x-9y+2

=( x^2+6xy+9y^2)-3(x+3y)+9/4 -1/4

=(x+3y)^2-3(x+3y)+(3/2)^2- 1/4

=(x+3y+3/2)^2-(1/2)^2

=(x+3y+3/2+1/2)(x+3y+3/2-1/2)=(x+3y+2)(x+3y+1)

\(x^4+6x^3+13x^2+12x+4\)

\(=x^4+x^3+5x^3+5x^2+8x^2+8x+4x+4\)

\(=x^3\left(x+1\right)+5x^2\left(x+1\right)+8x\left(x+1\right)+4\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3+5x^2+8x+4\right)\)

\(=\left(x+1\right)\left(x^3+x^2+4x^2+4x+4x+4\right)\)

\(=\left(x+1\right)\left[x^2\left(x+1\right)+4x\left(x+1\right)+4\left(x+1\right)\right]\)

\(=\left(x+1\right)^2\left(x+2\right)^2\)

x²-6xy+9y²-36 =(x²-6xy+9y²)-36 =(x-3y)²-6² =(x-3y+6)(x-3y-6)

a: \(3x^2-6xy+8x-16y\)

\(=\left(3x^2-6xy\right)+\left(8x-16y\right)\)

\(=3x\left(x-2y\right)+8\left(x-2y\right)\)

\(=\left(x-2y\right)\left(3x+8\right)\)

h: \(9y^2-4x^2+4x-1\)

\(=9y^2-\left(4x^2-4x+1\right)\)

\(=\left(3y\right)^2-\left(2x-1\right)^2\)

\(=\left(3y-2x+1\right)\left(3y+2x-1\right)\)

=[x²-6xy+(3y)²-49]

=[(x-3y)²-7²]

=(x-3y-7)*(x+3y+7)

= x^2 - 6xy + 9y^2 - 49

= x^2 - 6xy + ( 3y )^2 - 49

= (x - 3y)^2 - 7^2

= (x - 3y -7)( x-3y +7) tk cho mk nha

\(x^2-49-6xy+9y^2\)

\(=\left(x^2-6xy+9y^2\right)-7^2\)

\(=\left(x-3y\right)^2-7^2\)

\(=\left(x-3y-7\right)\left(x-3y+7\right)\)

k mk nha ^_^

a) 3x² - 7x + 4

= 3x² - 3x - 4x + 4

= 3x( x - 1 ) - 4( x - 1 )

= ( x - 1 )( 3x - 4 )

b) x² - 6xy + 9y² = ( x - 3y )²

c) x² - 8x - 9

= x² - 9x + x - 9

= x( x - 9 ) + ( x - 9 )

= ( x - 9 )( x + 1 )

a) 3x² - 7x + 4

= 3x² - 4x - 3x + 4

= (3x² - 4x) - (3x - 4)

= x.(3x - 4) - (3x - 4)

= (3x - 4).(x - 1)

b) x² - 6xy + 9y²

= x² - 2.x.3y + (3y)²

= (x - 3y)²

c) x² - 8x - 9

= x² - 9x + x - 9

= (x² - 9x) + (x - 9)

= x.(x - 9) + (x - 9)

= (x - 9).(x + 1)

a. \(x^2-y^2=\left(x-y\right)\left(x+y\right)\)

b. \(x^2-6xy+9y^2-36=\left(x-3y\right)^2-6^2=\left(x-3y-6\right)\left(x-3y+6\right)\)

a: \(x^2-y^2=\left(x-y\right)\left(x+y\right)\)

b: \(x^2-6xy+9y^2-36=\left(x-3y\right)^2-6^2=\left(x-3y-6\right)\left(x-3y+6\right)\)

a) Ta có: \(x^2y^2-x^2+6xy-9y^2\)

\(=x^2y^2-\left(x^2-6xy+y^2\right)\)

\(=\left(xy\right)^2-\left(x-3y\right)^2\)

\(=\left(xy-x+3y\right)\left(xy+x-3y\right)\)

b) Ta có: \(9-x^2+2xy-y^2\)

\(=9-\left(x^2-2xy+y^2\right)\)

\(=9-\left(x-y\right)^2\)

\(=\left(9-x+y\right)\left(9+x-y\right)\)

Câu 1: 3x² - 6xy + 3y² - 12z²

= 3(x² - 2xy + y² - 4z²)

= 3[(x² -2xy+y²)- (2z)²]

= 3[(x-y)² - (2z)²]

=3(x-y-2z)(x-y +2z)

Câu 2: x² - 6xy - 25z²+ 9y²

= x² - 2x.3y + (3y)² - (5z)²

= (x-3y)² - (5z)²

= (x-3y-5z)(x-3y+5z)