a, 27³ : 3⁵  =  ( 3³)³ : 3⁵ = 3⁹ : 3⁵ = 3⁴

b, 7² . 343 . 49³⁰ = 7². 7³.(7²)³  = 7¹¹

c, 625 : 5³ = 5⁴ : 5³ =  5

d, 1 000 000 : 10³ = 10⁶ . 10³ = 10³

e, 11⁵ : 121= 11⁵ : 11² = 11³

f, 8⁷ : 64 :8 = 8⁷ : 8² : 8¹ = 8⁴

i, 1024 . 16 : 2⁶  = 2¹⁰ . 2³ : 2⁶ = 2⁷

B2:

 số chính phương là:

4 ; 121 ; 196 ; 225.

Bài 2 :

Số chính phương là :

\(4=2^2\)

\(121=11^2\)

\(196=14^2\)

\(225=25^2\)

Bài 1:

a) 8² . 2² = 64 . 4 = 256

b) 2⁵. 4 = 2⁵. 2²= 2⁵⁺² = 2⁷

c) 9⁴. 243 = 9⁴. 3⁵=(3²)⁴.3⁵=3⁸.3⁵=3⁸⁺⁵=3¹³

Bài 1 :

\(a.8^2.2^2=\left(8.2\right)^2=16^2\)

\(b.2^5.4=2^5.2^2=2^7\)

\(c.9^4.243=\left(3^2\right)^4.3^5=3^8.3^5=3^{13}\)

Bài 2:

a. ( đề sai =.= )

\(b.12.\left(x-1\right):3=43+2^3\)

\(\Leftrightarrow12.\left(x-1\right)=43+2^3.3\)

\(\Leftrightarrow12.\left(x-1\right)=67\)

\(\Leftrightarrow x-1=\frac{67}{12}\)

\(\Leftrightarrow x=\frac{79}{12}\)

Ta có:

5^x+5^x-2=650\(\Rightarrow\)5^x.(1+5²)=650\(\Rightarrow\)5^x.26=650\(\Rightarrow\)5^x=25\(\Rightarrow\)x=2

2.5^2x-1-1=249\(\Rightarrow\)2.5^2x-1=250\(\Rightarrow\)5^2x-1=125=5³\(\Rightarrow\)2x-1=3\(\Rightarrow\)x=2

3.8^x-1=48\(\Rightarrow\)8^x-1=16(loại)

16^x-5-5=251\(\Rightarrow\)16^x-5=256=16²\(\Rightarrow\)x-5=2\(\Rightarrow\)x=7

Ta có : 5^x - 5^{x - 2} = 650

=> 5^x(1 + 5²) = 650

=> 5^x . 26 = 650

=> 5^x = 25

=> 5^x = 5² 

=> x = 2

\(25\cdot5^3\cdot\dfrac{1}{625}\cdot5^3=5^8\cdot\dfrac{1}{5^4}=5^4\)

                       a) \(2^5:8^4=2^5:\left(2^3\right)^4=2^5:2^{12}=2^{-7}=\frac{1}{2^7}\)\(=\left(\frac{1}{2}\right)^7\)

                     b) \(25^6:125^3=\left(5^2\right)^6:\left(5^3\right)^3=5^{12}:5^9=5^3\)

                     c) \(625^2:25^7=\left(5^4\right)^2:\left(5^2\right)^7=5^8:5^{14}=5^{-6}=\frac{1}{5^6}=\left(\frac{1}{5}\right)^6\)

                  d) \(12^3.3^3=\left(12.3\right)^3=36^3\)

                 e) \(32^2:2^4=\left(2^5\right)^2:2^4=2^{10}:2^4=2^6\)

               g) \(64.2:2^5=2^6.2:2^5=2^7:2^5=2^2\)

                Mk làm hộ bn rùi đó nhớ ủng hộ mk nha ^_^

a) (1 phần 2 ) mũ 7

b) 5 mũ 3

c) (1 phần 5 ) mũ 6

d) 36 mũ 3

e) 2 mũ 6

g) 2 mũ 2

3^6 . 9^5

= 3^6. \(^{\left(3^2\right)^5}\)

= 3^6. 3^10

=\(^{3^{6+10}}\)

= 3^16

k nhé ( dấu " ^"  là đấu mũ)

3^6 x 9^5 = 3^6 x ( 3^2)^5 = 3^6 x 3^10 = 3^16

3^6.9^5=3^6.(3²)^5=3^6.3^10=3¹⁰⁺⁶=3¹⁶

\(0,001=\frac{1}{1000}=\frac{1}{10^3}=10^{-3}\)

\(0,0001=\frac{1}{10000}=\frac{1}{10^4}=10^{-4}\)

\(0,00015=\frac{3}{20000}=\frac{3}{2}\times\frac{1}{10000}=\frac{3}{2}\times\frac{1}{10^4}=\frac{3}{2}\times10^{-4}\)

\(5^{-a}=\frac{1}{5^a}\)

\(3,5\times10^{-5}=3,5\times\frac{1}{10^5}\)

\(\left(\frac{2}{3}\right)^{-2}==\frac{1}{\left(\frac{2}{3}\right)^2}=\left(\frac{3}{2}\right)^2\)

\(10^{-3}=\frac{1}{10^3}=\frac{1}{1000}\)

\(x^4\cdot x^7\cdot...\cdot x^{100}\)

\(=x^{4+7+...+100}\)

\(=x^{52\cdot33}=x^{1716}\)

\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}\)

Ta có : \(x^1\cdot x^2=x^{1+2}=x^3\)

Tương tự : \(x^1\cdot x^2\cdot x^3=x^{1+2+3}=x^6\)

Áp dụng vào bài toán :

\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}=x^{1+2+3+...+2006}\)

\(\Rightarrow x^{1+2+3+...+2006}=x^{2013021}\)

Sửa câu a : \(x^{1+2+3+...+2006}=x^{2033136}\)