102 - [(8 ^ 2 - 48) . 0.5 + (2 ^ 2 .10 + 8)] / (2 ^ 5)
.Thực hiện phép tính
a) 47 – [(45.24 – 5 2 .12):14]
b) 50 – [(20 – 2 3 ) : 2 + 34]
c) 102 – [60 : (56 : 54 – 3.5)]
d) 50 – [(50 – 2 3 .5):2 + 3]
e) 10 – [(82 – 48).5 + (23 .10 + 8)] : 28
f) 8697 – [37 : 35 + 2(13 – 3)]
g) 2011 + 5[300 – (17 – 7)2 ]
h) 695 – [200 + (11 – 1)2 ]
k) 2345 – 1000 : [19 – 2(21 – 18)2 ]
l) 128 – [68 + 8(37 – 35)2 ] : 4
m) 568 – {5[143 – (4 – 1)2 ] + 10} : 10
n) 107 – {38 + [7.32 – 24 : 6+(9 – 7)3 ]}:15
o) 307 – [(180 – 160) : 22 + 9] : 2
p) 205 – [1200 – (42 – 2.3)3 ] : 40
q) 177 :[2.(42 – 9) + 32 (15 – 10)]
r) [(25 – 2 2 .3) + (32 .4 + 16)]: 5
i) 129 – 5[29 – (6 – 1)2 ]
j) 2010 – 2000 : [486 – 2(72 – 6)]
s) 125(28 + 72) – 25(32 .4 + 64)
t) 500 – {5[409 – (23 .3 – 21)2 ] + 103 } : 15
Sao bạn bỏ một khoảng trống giữa các số 5 2 với 2 3v?
1. [ ( -2 ). 3 + 9 ]. ( -5 ) - ( -6 ). 8
2. ( 135 - 35 ). ( -47 ) + 53. ( -48 - 52 )
3. 0 - 1 + 2 - 3 + 4 - 5 + 6 - 7 + ... + 2004 - 2005
4. 1 - 3 + 5 - 7 + 9 - 11 + ... + 2005 - 2007
5.1 + 2 + 3 - 4 - 5 - 6 + 7 + 8 + 9 - 10 - 11 - 12 + ... + 97 + 98 + 99 - 100 - 101 - 102
a.205-{102-[48-(16-14)mux3]}
b.{[10-2.3).5]+2-2.6}:2+(4+5)mũ2
c.(2 mũ3. 9 mũ 4+9 mũ3.45):(9 mũ 2.10-9 mũ 2)
d.18.[(3 mũ 4.24+3 mũ 4.4-27.3 mũ 4)-71.1 mũ 20]-8
10-[(8 mũ 2-48).5+(2 mũ 3.10+8)]:28
Ta có: \(10-\left[\left(8^2-48\right)\cdot5+\left(2^3\cdot10+8\right)\right]:28\)
\(=10-\left[16\cdot5+\left(8\cdot10+8\right)\right]:28\)
\(=10-\left(80+80+8\right):28\)
\(=10-168:28\)
\(=10-6=4\)
\(10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+\left(80+8\right)\right]:28\)
\(=10-\left[16.5+88\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6=4\)
1 / Tìm chữ số tận cùng của : 8 ^ 102 , 2 ^ 102
2/ Chứng tỏ 8 ^ 102 - 2 ^ 102 chia hết cho 10
e, 10–[(8²–48).5+(2³.10+8)]:28
\(10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+\left(80+8\right)\right]:28\)
\(=10-\left[16.5+88\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6\)
\(=4\)
10-[(82-48).5+(23.10+8)]:28
= 10-[(64-48).5+(8.10+8)]:28
= 10-[16.5+88]:28
= 10-[80+88]:28
= 10-168:28
= 10-6
= 4
10-[(82-48).5+(23.10+8)]:28
= 10-[(64-48).5+(8.10+8)]:28
= 10-[16.5+88]:28
= 10-[80+88]:28
= 10-168:28
= 10-6
= 4
10 - [ ( 82 - 48 ) x 5 + ( 23 x 10 + 8 ) ] : 28
10 - [ ( 82 - 48 ) x 5 + ( 23 x 10 + 8 ) ] : 28
= 10 - [ ( 64 - 48 ) x 5 + ( 8 x 10 + 8 ) ] :28
=10 - [ 16 x 5 + 88 ] :28
=10 - 168 : 28
=10 - 6 = 4
Ý kiến của mình ạ <333
= 10 - [( 64 - 48 ) . 5 + ( 8 . 10 + 8 ) ] : 28
= 10 - [16 . 5 + ( 80 + 8 ) ] : 28
= 10 - [80 + 88] :28
= 10 - 168 : 28
= 10 - 6
= 4
Tính tổng của dãy số:
a) 2+3+4+5+7+8+9+10+11+..........+81
b)2+3+4+5+6+7+8+9+10+11+......+101+102
a)1/3-1/3*(2-3/5)
b)1/9-5/15+8/9-10/15+0.5
a) \(\dfrac{1}{3}-\dfrac{1}{3}\times\left(2-\dfrac{3}{5}\right)\\ =\dfrac{1}{3}-\dfrac{1}{3}\times\dfrac{7}{5}\\ =\dfrac{1}{3}-\dfrac{7}{15}\\ =\dfrac{5}{15}-\dfrac{7}{15}\\ =-\dfrac{2}{15}\)
b) \(\dfrac{1}{9}-\dfrac{5}{15}+\dfrac{8}{9}-\dfrac{10}{15}+0,5\\ =\left(\dfrac{1}{9}+\dfrac{8}{9}\right)-\left(\dfrac{5}{15}+\dfrac{10}{15}\right)+0,5\\ =\dfrac{9}{9}-\dfrac{15}{15}+0,5\\ =1-1+0,5\\ =0,5\)