Question

e, 10–[(8²–48).5+(2³.10+8)]:28

Answer 1

\(10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)

\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)

\(=10-\left[16.5+\left(80+8\right)\right]:28\)

\(=10-\left[16.5+88\right]:28\)

\(=10-\left[80+88\right]:28\)

\(=10-168:28\)

\(=10-6\)

\(=4\)

Answer 2

   10-[(8²-48).5+(2³.10+8)]:28

= 10-[(64-48).5+(8.10+8)]:28

= 10-[16.5+88]:28

= 10-[80+88]:28

= 10-168:28

= 10-6

= 4

Answer 3

   10-[(8²-48).5+(2³.10+8)]:28

= 10-[(64-48).5+(8.10+8)]:28

= 10-[16.5+88]:28

= 10-[80+88]:28

= 10-168:28

= 10-6

= 4