Ta có : 9(x + 1)² - (3x - 2)(3x + 2) = 10

=> 9(x² + 2x + 1) - (9x² - 4) = 10

=> 9x² + 18x + 9 - 9x² + 4 = 10

=> 9x² - 9x² + 18x + 13 = 10

=> 18x = 10 - 13

=> 18x = -3 

=> x = \(-\frac{1}{6}\)

tự tính nhẩm bằng 1

\(( 7x-19)-(5x-12)=3x-(9-2x)-1\)

\(<=> 7x-19-5x+12=3x-9+2x-1\)

\(<=> 2x-7=5x-10\)

\(<=> 2x-5x=-10+7\)

\(<=> -3x = -3\)

\(<=> x=3\)

trình bày ra được không

A)    \(x-\dfrac{2}{3}=\dfrac{4}{5}\\ x=\dfrac{4}{5}+\dfrac{2}{3}\)

           \(x=\dfrac{22}{15}\)

b)\(\dfrac{7}{9}-x=\dfrac{1}{3}\\ x=\dfrac{7}{9}-\dfrac{1}{3}\\ x=\dfrac{4}{9}\)

C)\(x:\dfrac{2}{3}=\dfrac{9}{8}\\ x=\dfrac{9}{8}x\dfrac{2}{3}\\ x=\dfrac{3}{4}\)

a: \(\Leftrightarrow\left(2-x\right)\left(x-3\right)+\left(x-1\right)\left(x+3\right)=-4x\)

\(\Leftrightarrow2x-6-x^2+3x+x^2+3x-x-3=-4x\)

=>7x-9=-4x

=>11x=9

hay x=9/11

b: \(\Leftrightarrow\left(5-x\right)\left(x-4\right)+\left(x+2\right)\left(x+4\right)=-3x\)

\(\Leftrightarrow5x-20-x^2+4x+x^2+6x+8=-3x\)

=>15x-12=-3x

=>18x=12

hay x=2/3

a: \(\Rightarrow10x^2+9x-\left(10x^2+15x-2x-3\right)=8\)

\(\Leftrightarrow10x^2+9x-10x^2-13x+3=8\)

=>-4x=5

hay x=-5/4

b: \(\Leftrightarrow21x-15x^2-35+25x+15x^2-10x+6x-4-2=0\)

=>42x=41

hay x=41/42

`a)(10x+9)x-(5x-1)(2x+3)=8`

`<=>10x^2+9x-10x^2-15x+2x+3=8`

`<=>-4x=5`

`<=>x=-5/4`     Vậy `S={-5/4}`

`b)(3x-5)(7-5x)+(5x+2)(3x-2)-2=0`

`<=>21x-15x^2-35+25x+15x^2-10x+6x-4-2=0`

`<=>42x=41`

`<=>x=41/42`       Vậy `S={41/42}`

a: 

=>-4x=5

hay x=-5/4

b: 

=>42x=41

hay x=41/42

<=>55 - 3x = 25

<=>-3x = 25 - 55
<=>-3x = -30
<=>x=10

55 - 3x = (-5)²

55 - 3x = 25

3x = 55 - 25

3x = 30

x = 30 : 3

x = 10

Vậy x = 10

55 - 3x = (-5)²

55 - 3x = 25

3x = 55 - 25

3x = 30

x = 30 : 3

x = 10