A,          m²-7m+12=m²-3m+12-4m=m(m-3)-4(m-3)=(m-4)(m-3)

B,           2x⁴-x³+27-54x=x³(2-x)-27(2-x)=(x³-27)(2-x)=(x-3)(x²+3x+9)(2-x)

a) m^2 -7m +12 = m^2 -3m -4m +12

=m(m -3)-4 (m- 3)

=(m-4)(m-3)

b) 2x^4-x^3 -54x+ 27

=(2m^4-x^3)- (54x - 27)

=x^3(2x-1)-27(2x-1)

=(x^3-27)(2x-1)

a,(m-4)(m-3)

b,(x-3)(2x-1)(x^2-3x+9)

đề có sai ko bn?

\(6x^3+x^2+x+1=\left(6x^3+3x^2\right)+\left(-2x^2-x\right)+\left(2x+1\right)\)

\(=3x^2.\left(2x+1\right)-x.\left(2x+1\right)+\left(2x+1\right)=\left(2x+1\right)\left(3x^2-x+1\right)\)

K sai dau
giao an truong Tran dai nghia do

\(B=x^4+3x^3-x^2+3x^3+9x^2-3x-x^2-3x+1\)

\(=\left(x^2+3x-1\right)^2\)

a) 16x²-(x²+4)²= (4x)²-(x²+4)²

                      = (4x-x²-4)(4x+x²+4)

\(\text{b) 27x^3-54x^2+36x-8=[(3x)^3-3.(3x)^2.2+3.3x.2^2-2^3}]\)

                                                      = (3x-2)³
\(\text{c) (x+y)^3 - (x-y)^3= (x+y-x+y)[(x+y)^2+(x+y)(x-y)+(x-y)^2]}\)

                                   =2y(x²+2xy+y²+x²-y²+x²-2xy+y²)

                                   = 2y(3x²+y²)

Viết đề rõ chút chứ nhìn ko ra

\(3x^4-48\)

\(=\left(3x^4-6x^3\right)+\left(6x^3-12x^2\right)+\left(12x^2-24x\right)+\left(24x-48\right)\)

\(=3x^3\left(x-2\right)+6x^2\left(x-2\right)+12x\left(x-2\right)+24\left(x-2\right)\)

\(=\left(x-2\right)\left[\left(3x^3+6x^2\right)+\left(12x+24\right)\right]\)

\(=\left(x-2\right)\left[3x^2\left(x+2\right)+12\left(x+2\right)\right]\)

\(=\left(x-2\right)\left(x+2\right)\left(3x^2+12\right)\)

\(x^4-8x\)

\(=x\left(x^3-8\right)\)

\(=x\left[\left(x^3-2x^2\right)+\left(2x^2-4x\right)+\left(4x-8\right)\right]\)

\(=x\left[x^2\left(x-2\right)+2x\left(x-2\right)+4\left(x-2\right)\right]\)

\(=x\left(x-2\right)\left(x^2+2x+4\right)\)

\(x^3-6x^2+9x\)

\(=\left(x^3-3x^2\right)-\left(3x^2-9x\right)\)

\(=x^2\left(x-3\right)-3x\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2-3x\right)\)

\(=x\left(x-3\right)\left(x-3\right)\)

\(=6x^2-2x-\left(9x-3\right)\)

\(=2x\left(3x-1\right)-3\left(3x-1\right)\)

\(=\left(2x-3\right)\left(3x-1\right)\)

6x² - 11x + 3

= 2x(3x - 1) - 3(3x - 1)

= (3x - 1)(2x - 3)

= 6x^2 - 9x - 2x + 3

= 3x(2x-3) -(2x-3)

= (2x-3).(3x-1)