`(x-3)/13+(x-3)/14=(x-3)/15+(x-3)/16`

`=>(x-3).(1/13+1/14-1/15-1/16)=0`

`=>x-3=0` 

`=>x=3`
 

\(\dfrac{x-3}{13}+\dfrac{x-3}{14}=\dfrac{x-3}{15}+\dfrac{x-3}{16}\)

\(\Leftrightarrow\dfrac{x-3}{13}+\dfrac{x-3}{14}-\dfrac{x-3}{15}-\dfrac{x-3}{16}=0\)

\(\Leftrightarrow\left(x-3\right).\left(\dfrac{1}{13}+\dfrac{1}{14}-\dfrac{1}{15}-\dfrac{1}{16}\right)=0\)

\(\Leftrightarrow x-3=0\)( Vì \(\dfrac{1}{13}+\dfrac{1}{14}-\dfrac{1}{15}-\dfrac{1}{16}>0\))

\(\Leftrightarrow x-3=0\Rightarrow x=3\)

\(\dfrac{x-3}{13}+\dfrac{x-3}{14}=\dfrac{x-3}{15}+\dfrac{x-3}{16}\)

\(\Leftrightarrow\dfrac{1680.\left(x-3\right)+1560.\left(x-3\right)-1456.\left(x-3\right)-1365.\left(x-3\right)}{21840}=0\)

\(\Leftrightarrow\left(x-3\right).\left(1680+1560-1456-1365\right)=0\)

\(\Leftrightarrow\left(x-3\right).419=0\)

\(\Leftrightarrow419x=1257\)

\(\Leftrightarrow x=3\)

Lời giải:

\(\frac{x-3}{13}+\frac{x-3}{14}=\frac{x-3}{15}+\frac{x-3}{16}\)

\((x-3)\left(\frac{1}{13}+\frac{1}{14}\right)=(x-3)\left(\frac{1}{15}+\frac{1}{16}\right)\)

\((x-3)\left[\left(\frac{1}{13}+\frac{1}{14}\right)-\left(\frac{1}{15}+\frac{1}{16}\right)\right]=0\)

Ta thấy:

\(\frac{1}{13}>\frac{1}{15}; \frac{1}{14}>\frac{1}{16}\Rightarrow \frac{1}{13}+\frac{1}{14}> \frac{1}{15}+\frac{1}{16}\)

Do đó biểu thức trong ngoặc vuông lớn hơn $0$ hay khác $0$

$\Rightarrow x-3=0$

$\Leftrightarrow x=3$

:))) khó quá

x-3/13+x-3/14=x-3/15+x-3/16

<=> x-3/13+x-3/14-x-3/15-x-3/16=0

<=> (x-3).(1/13+1/14-1/15-1/16)

<=> (x-3)=0 ( Vì 1/13+1/14-1/15-1/16>0)

<=> x-3=0 => x=3

Vậy x=3

\(\dfrac{x-3}{13}+\dfrac{x-3}{14}=\dfrac{x-3}{15}+\dfrac{x-3}{16}\)

\(\Leftrightarrow x-3=0\)

hay x=3

Bạn viết như này ai hiểu

Viết lại đề lại sách nháp đi

\(\Rightarrow\frac{\left(\frac{518}{19}-\frac{342}{13}\right).\left(\frac{253}{236}-\frac{3}{318}\right)}{\left(\frac{3}{4}+x\right)\frac{27}{33}}\)=\(\frac{\frac{1}{3}.\frac{3}{36}+\frac{1}{3}.\frac{3}{14.17}}{\frac{1}{2}.\frac{2}{13.15}+\frac{1}{2}.\frac{2}{14.16}}\)

\(\frac{\frac{236}{2247}.\frac{247}{236}}{\left(\frac{3}{4}+x\right)\frac{27}{33}}\)=\(\frac{\frac{1}{3}.\left(\frac{1}{13}-\frac{1}{16}+\frac{1}{14}-\frac{1}{17}\right)}{\frac{1}{2}\left(\frac{1}{13}+\frac{1}{14}-\frac{1}{16}-\frac{1}{17}\right)}\)

\(\frac{1}{\left(\frac{3}{4}+x\right)\frac{27}{33}}\)=\(\frac{\frac{1}{3}}{\frac{1}{2}}\)

đến đây tự làm nhé cứ ra 13/12 là được

Bạn ơi bạn làm đc bao nhiêu thì làm phụ mình nhé 

bài1

a, 

5 - 7 + 3 +(-8)

= -2 + 3 + ( - 8)

=     1    + (-8)= -7

a; - (-5) - (+7) + (+3) + (-8)

  = 5 - 7 + 3  - 8

= (5 + 3 - 8) - 7

= (8 - 8) - 7

= 0 - 7

= - 7