2010 - 2000 : [ 486 - 2 ( 72 - 6 ) ]
a) 2011 + 5[300 – (17 – 7)2]
b) 695 – [200 + (11 – 1)2]
c) 129 – 5[29 – (6 – 1)2]
2010 – 2000 : [486 – 2(72 – 6)]
a: \(=2011+5\cdot\left[300-10^2\right]\)
\(=2011+5\cdot200\)
=1011
b: \(=695-\left[200+10^2\right]\)
=695-300
=395
a) =2011+5.200
=3011
b)=695-300
=395
c)1=29-5.4
=109
d)=2010-2000:400
=2010-5
=2005
a) 47 – [(45.24 – 52.12):14] e) 10 – [(82 – 48).5 + (23.1 + 8) -12] : 28
b) 2010 – 2000 : [486 – 2(72 – 6)] g) 128 – [68 + 8(37 – 35)2] : 4
c) 568 – {5[143 – (4 – 1)2] + 10} : 10
d) 307 – [(180 – 160) : 22 + 9] : 2 h) 205 – [1200 – (42 – 2.3)3] : 40
giúp
helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp
2010-2000:[486-2(7 mũ 2-6)]
\(2010-2000:\left[486-2\left(7^2-6\right)\right]\)
\(=2010-2000:\left[486-2\left(49-6\right)\right]\)
\(=2010-2000:\left(486-2\cdot43\right)\)
\(=2010-2000:\left(486-86\right)\)
\(=2010-2000:400\)
\(=2010-5\)
\(=2005\)
`2010-2000:[486-2(7^2-6)]`
`=2010-2000:[486-2.(49-6)]`
`=2010-2000:(486-2.43)`
`=2010-2000:(486-86)`
`=2010-2000:400`
`=2010-5=2005`
2010 - 2000:[486 - 2(7^2 -6)
=2010-2000:[486 -2(49 -6) ]
=2010 - 2000 :[486 - 2.43]
=2010 - 2000 : [486 - 86 ]
=2010 - 2000 : 400
= 2010 - 5
=2005
2010-2000:(ngoặc vuông)486-2(7^2-6)
\(2010-2000:\left[486-2\left(7^2-6\right)\right]\)
=2010-2000:[486-2*43]
=2010-2000:400
=2010-5=2005
rồi câu cuối là có ngoặc vuông nha các bn
\(2010-2000:\left[486-2\left(7^2-6\right)\right]\)
\(=2010-2000:\left[486-2\cdot\left(49-6\right)\right]\)
\(=2010-2000:\left[486-2\cdot43\right]\)
\(=2010-2000:\left(486-86\right)\)
\(=2010-2000:400\)
\(=2010-5\)
\(=2005\)
2026-2000:[486-2.( 72-6)]
\(=2026-2000:\left[486-2\left(49-6\right)\right]\)
\(=2026-2000:\left[486-2\cdot43\right]\)
\(=2026-2000:\left[486-86\right]\)
\(=2026-2000:400\)
\(=2026-5\)
\(=2021\)
=2026-2000:[486-2.(49-6)]
=2026-2000:[486-2.43]
=2026-2000:[486-86]
=2026-2000:400
=2026-5
=2021
= 2026 − 2000 : [ 486 − 2 ( 49 − 6 ) ] = 2026 − 2000 : [ 486 − 2 ⋅ 43 ] = 2026 − 2000 : [ 486 − 86 ] = 2026 − 2000 : 400 = 2026 − 5 = 2021
2010 - 2000 : [486 - 2 (72 - 6 ) ]
\(2010-2000:\left[486-2\left(7^2-6\right)\right]\)
\(=2010-2000:\left[486-2\left(49-6\right)\right]\)
\(=2010-2000:\left[486-2.43\right]\)
\(=2010-2000:\left[486-86\right]\)
\(=2010-2000:400\)
\(=2010-5\)
\(=2005\)
2012 - 2000 : [ 486 - 2(7^2-6)]
=2012 - 2000 : [486 - 2(49-6)]
=2012 -2000 : [486-2*43]
=2012 - 2000 :[486-86]
=2012-2000:100
=2012 - 20
=1992
2010 - 2000 : [ 486 - 2( 49 - 6 ) ]
2010 - 2000 : [ 486 - 2 . 43 ]
2010 - 2000 : [ 486 - 86 ]
2010 -2000 : 400
2010 - 5
2005
\(2010-2000:\orbr{\begin{cases}\\\end{cases}486}-2\left(49-6\right)\)
2010-2000:[486-2.43]
=2010-2000:[486-86]
=2010-2000:400
=2010-5
=2005
nhơ tk mk bạn nhé
=2010-2000:[486-86]
=2010-2000:400=2010-5=2005
k nha
2010 - 2000 : [486 - 2(49 - 6)]
= 2010 - 2000 : [486 - 2 . 43]
= 2010 - 2000 : [486 - 86]
= 2010 - 2000 : 400
= 2010 - 5
= 2005
Chúc bạn học tốt! Nhớ k cho mình nhé.
2010-2000 : \(\orbr{\begin{cases}\\\end{cases}486}-2\)(7 mũ 2 . 6 )
Cách 1 :
2010 - 2000/486 - 2(7^2 x 6)
= 5/51
Cách 2 :
2010 - 2000/486 - 2 ( 7^2 x 6 )
= 2029 , 607 843 137 25
k cho mk nha
2010-2000:[486-2.(7^2-6)]
500-{5.[409-(2^3:3-21)^2]+10^3}.15
giúp mk nếu đúng mk sẽ tick
\(2010-2000:\left[486-2.\left(7^2-6\right)\right]\)
\(=2010-2000:\left[486-2.\left(49-6\right)\right]\)
\(=2010-2000:\left[486-2.43\right]\)
\(=2010-2000:\left[486-86\right]\)
\(=2010-2000:400\)
\(=2010-5\)
\(=2005\)
\(500-\left\{5.\left[409-\left(2^3:3-21\right)^2\right]+10^3\right\}.15\)
\(=500-\left\{5.\left[409-\left(8:3-21\right)^2\right]+10^3\right\}.15\)
\(=500-\left\{5.\left[409-\left(\frac{8}{3}-21\right)^2\right]+10^3\right\}.15\)
\(=500-\left\{5.\left[409-\frac{-55}{3}\right]+1000\right\}.15\)
\(=500-\left\{5.\left(\frac{1282}{3}\right)+1000\right\}.15\)
\(=500-\left\{\frac{6410}{3}+1000\right\}.15\)
\(=500-\frac{9410}{3}.15\)
\(=500-47050\)
\(=-46550\)