135-5(x+4)=35)

5(4+x)=135-35

5(4+x)=100

4+x=100:5

4+x =20

x=20-4

x=16

x=

135 - 5(x + 4) = 35

        5(x + 4) = 135 - 35

        5(x + 4) = 100

           x + 4 = 100 : 5

          x + 4 = 20

               x = 20 - 4

              x = 16

135 - 5(x+4) = 35

        5(x+4) = 135 - 35

        5(x+4) = 100

           x+ 4 = 100 : 5

           x + 4 = 20

                 x = 20 - 4

                 x = 16

Vậy x = 16

Nhớ tịk cho mình nhé!

135-5(x+4)=35

      5(x+4)=1355-35=100

          x+4=100:5=20

          x    =20-4=16

ai k mình mình k lại

Ta có: 135 - 5(x + 4) = 35

\(\Rightarrow\) 5(x + 4) = 135 - 35

\(\Rightarrow\) 5(x + 4) = 100

\(\Rightarrow\) x + 4 = 100 : 5

\(\Rightarrow\) x + 4 = 20

\(\Rightarrow\) x = 20 - 4

\(\Rightarrow\) x = 16

Vậy: x = 16

135 - 5( x + 4 ) = 35

         5( x + 4 ) = 135 - 35 

         5( x + 4 ) = 100

           ( x + 4 ) = 100 : 5

             x + 4    = 20

            x = 20 - 4

            x = 16

                                          KL : x = 16

Thực hiện phép tính:

\(\left(-17\right)+5+8+17+\left(-3\right)\)

\(=\left[\left(-17\right)+17\right]+\left[5+8+\left(-3\right)\right]\)

\(=0+10\)

\(=10\)

35 : 7 = 5

= 5

\(\left(-\dfrac{1}{2}\right)-\left(-\dfrac{3}{5}\right)+\left(-\dfrac{1}{9}\right)+\dfrac{1}{127}-\dfrac{7}{18}+\dfrac{4}{35}-\left(-\dfrac{2}{7}\right)\)

\(=\left[-\dfrac{1}{2}-\dfrac{1}{9}-\dfrac{7}{18}\right]+\left[\dfrac{3}{5}+\dfrac{4}{35}+\dfrac{2}{7}\right]+\dfrac{1}{127}\)

\(=-\dfrac{18}{18}+\dfrac{35}{35}+\dfrac{1}{127}\)

\(=-1+1+\dfrac{1}{127}\)

\(=\dfrac{1}{127}\)

giúp tớ với ah tớ cần gấp

a: =-3/24-40/24

=-43/24

b: \(=\dfrac{6}{54}\cdot\dfrac{49}{35}=\dfrac{1}{9}\cdot\dfrac{7}{5}=\dfrac{7}{45}\)

c: \(=\dfrac{6}{5}+\dfrac{4}{3}=\dfrac{18+20}{15}=\dfrac{38}{15}\)

d: \(=\dfrac{31}{17}-\dfrac{14}{17}-\dfrac{5}{13}-\dfrac{8}{13}=1-1=0\)

=(1/5+3/5+4/5+2/5)

=10/5=2

\(=\dfrac{1}{5}+\dfrac{2}{5}+\dfrac{3}{5}+\dfrac{4}{5}=\dfrac{10}{5}=2\)

=1/5+2/5+51/85+4/5

=7/5+51/85

=119/85+51/85

=170/85=2