Ta có :
Gọi A=1.2+2.3+3.4+4.5+...+49.50
\Rightarrow A=1.2+2.3+3.4+4.5+...+49.50
\Rightarrow 3.A=3.(1.2+2.3+3.4+4.5+...+49.50)
\Rightarrow 3.A=1.2.3+2.3.3+3.3.4+3.4.5+...+3.49.50
\Rightarrow 3.A=1.2.(3-0)+2.3.(3-0)+(3-0).3.4+(3-0).4.5+...+(3-0).49.50
\Rightarrow 3.A=1.2.3-0+2.3.3-0+3.3.4-0+3.4.5-0+...+3.49.50-0
\Rightarrow 3.A=1.2.3-0+2.3.4-1.2.3+5.3.4-2.3.4+...+49.50.51-48.49.50
\Rightarrow 3.A=49.50.51
\Rightarrow A=$\frac{\mathrm{49.50.51}}{3}$
\Rightarrow A=$\frac{\mathrm{49.50.17.3}}{3}$
\Rightarrow A=49.50.17
\Rightarrow A=41650
Đáp số : A=41650

=330

ủng hộ mk nhé

330 là kết quả đúng đó bạn!

\(330\)nha bạn

\(\frac{2021}{1\cdot2}+\frac{2021}{2\cdot3}+...+\frac{2021}{9\cdot10}=2021\cdot\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+...+\frac{1}{9\cdot10}\right)\)

\(=2021\cdot\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)=2021\cdot\left(1-\frac{1}{10}\right)\)

\(=2021\cdot\frac{9}{10}=\frac{18189}{10}\)

Ta có : \(\frac{2021}{1.2}+\frac{2021}{2.3}+\frac{2021}{3.4}+...+\frac{2021}{9.10}=2021\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\right)\)

\(=2021\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=2021\left(1-\frac{1}{10}\right)=2021.\frac{9}{10}=1818,9\)

330 nha

=1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+............+1/9+1/10

=1-1/10

=10/10-1/10

=9/10

Bài làm:

  \(\frac{1}{1\times2}+\frac{1}{2\times3}\)\(+\frac{1}{3\times4}+\frac{1}{4\times5}\)\(+...\frac{1}{9\times10}\)

\(=\frac{1}{1}-\frac{1}{2}\)\(+\frac{1}{2}-\frac{1}{3}\)\(+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}\)\(-\frac{1}{5}\)\(+...\frac{1}{9}-\frac{1}{10}\)

\(=\)\(\frac{1}{1}-\frac{1}{10}\)

\(=\frac{9}{10}\)

E = \(\frac{5}{1.2}+\frac{13}{2.3}+\frac{25}{3.4}+..........+\frac{181}{9.10}\)

E = \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...........+\frac{181}{9.10}\)

E = \(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+........+\frac{1}{9}-\frac{1}{10}\)

E = \(\frac{1}{1}-\frac{1}{10}\)

E = \(\frac{9}{10}\)

A  = 1 x 2 + 2 x 3 + ....... + 10 x 11

3A = 1 x 2 x 3 + 2 x 3 x 3 + ..........+ 10 x 11 x 3

3A = 1 x 2 x (3-0) + 2 x 3 x (4-1) + .......... + 10 x 11 x (12 -9)

3A = 1 x 2 x 3 + 2 x 3 x 4 - 1 x 2 x 3 + ........... + 10 x 11 x 12 - 9 x 10 x 11

3A = (1 x 2 x 3 - 1 x 2 x 3) + ( 2 x 3 x 4 - 2 x 3 x 4) +............ + 10 x 11 x 12

3A = 10 x 11 x 12 = 1320

A = 1320 : 3 = 440

Gọi biểu thức trên là A, ta có :

A= 1x2 + 2x3 + 3x4 + 4x5 + ...+ 99x100

A x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3

A x 3 = 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)

A x 3 = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.

A x 3 = 99x100x101 A = 99x100x101 : 3 A = 333300

 

Gọi phép tính là: \(A\)

Ta có:

\(A=\dfrac{2}{1\times2}+\dfrac{2}{2\times3}+\dfrac{2}{3\times4}+...+\dfrac{2}{9\times10}\\ A\div2=\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+...+\dfrac{1}{9\times10}\\ A\div2=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\\ A\div2=\dfrac{9}{10}\\ A=\dfrac{18}{10}=\dfrac{9}{5}\)

\(=2\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{9\cdot10}\right)\)

\(=2\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)=2\cdot\dfrac{9}{10}=\dfrac{9}{5}\)

Đặt phép tính  là A

\(A=\dfrac{2}{1.2}+\dfrac{2}{2.3}+\dfrac{2}{3.4}+\dfrac{2}{4.5}+\dfrac{2}{5.6}+\dfrac{2}{6.7}+\dfrac{2}{7.8}+\dfrac{2}{8.9}+\dfrac{2}{9.10}\)

\(2A=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+.....+\dfrac{1}{9}-\dfrac{1}{10}\)

\(2A=1-\dfrac{1}{10}\)

\(2A=\dfrac{9}{10}\)

\(A=\dfrac{9}{5}\)