\(1.2+2.3+3.4+4.5+...+9.10\)
Đặt A = \(1.2+2.3+3.4+4.5+...+9.10\)
\(3.A\) = \(1.2.3+2.3.3+3.4.3+4.5.3+...+9.10.3\)
=> \(3.A\) = \(1.2.3+2.3.4+3.4.5+4.5.6+...+9.10.11\)
Ta có: \(3.A=9.10.11\)
=>: \(A=\frac{9.10.11}{3}=330\)
=> A = 330
\(1.2+2.3+4.5+...+9.10\)
Dat A=1.2+2.3+3.4+4.5+...+9.10
3.A=1.2.3+2.3.3+3.4.3+4.5.3+...+9.10.3
3A=1.2.3+2.3.4+3.4.5+4.5.6+...+9.10.11
Ta co:3A=9.10.11
A=9.10.11:3
A=330
Vay A=330
trả lời
=330
chúc bn
hc tốt