a ) x - ( - 18 ) = -24

x + 18 = -24

x = -24 - 18

x = -6

b ) -x - 17 + 8 = 33 - 19

-x - 17 + 8 = 14

-x - 17 = 14 - 8

-x - 17 = 6

-x =  -( 6 + 17 )

-x = - 23

c ) 15 - ( -4 + 7 ) = x - 14

15 + 4 + 7 = x - 14

27 = x - 14 

x - 14 = 27

x = 27 + 14

x = 41

d ) 9 - 25 = ( 7 - x ) - ( 25 + 7 ) 

( 7 - x ) - 32 = -16

7 - x = -16 + 32 

-7 - x = -16

x = -7 - ( - 16)

x = -7 + 16

x = 9

a)  3x – 15 = 25 – 5x 

=> 3x + 5x = 25 + 15

=> 8x = 40

=> x = 5

 b) 3x - 17 = 2x – 7     

=> 3x - 2x = -7 + 17

=> x = 10

 c) 2x – 17 =  – (3x – 18)

=> 2x - 17 = -3x + 18

=> 2x + 3x = 18 + 17

=> 5x = 35

=> x = 7

d) 3x – 14 = 2(x – 9) + 1

=> 3x - 14 = 2x - 18 + 1

=> 3x - 2x = -18 + 1 + 14

=> x = -3

f) (x – 5)² = 9          

\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

a) Ta có: \(3x-15=25-5x\)

\(\Leftrightarrow3x-15-25+5x=0\)

\(\Leftrightarrow8x-40=0\)

\(\Leftrightarrow8x=40\)

hay x=5

Vậy: x=5

b) Ta có: \(3x-17=2x-7\)

\(\Leftrightarrow3x-17-2x+7=0\)

\(\Leftrightarrow x-10=0\)

hay x=10

Vậy: x=10

c) Ta có: \(2x-17=-\left(3x-18\right)\)

\(\Leftrightarrow2x-17=-3x+18\)

\(\Leftrightarrow2x-17+3x-18=0\)

\(\Leftrightarrow5x-35=0\)

\(\Leftrightarrow5x=35\)

hay x=7

Vậy: x=7

d) Ta có: \(3x-14=2\left(x-9\right)+1\)

\(\Leftrightarrow3x-14=2x-18+1\)

\(\Leftrightarrow3x-14-2x+18-1=0\)

\(\Leftrightarrow x+3=0\)

\(\Leftrightarrow x=-3\)

Vậy: x=-3

f) Ta có: \(\left(x-5\right)^2=9\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

Vậy: \(x\in\left\{2;8\right\}\)

Bài 2. Tìm x, biết :                                

a) \(3x-15=25-5x\)

\(\Leftrightarrow8x=40\)

\(\Leftrightarrow x=5\)

Vậy x = 5

b) \(3x-17=2x-7\)

\(\Leftrightarrow x=10\)

Vậy x = 10

c) \(2x-17=-\left(3x-18\right)\)

\(\Leftrightarrow2x-17=18-3x\)

\(\Leftrightarrow5x=35\)

\(\Leftrightarrow x=7\)

Vậy x = 7

d) \(3x-14=2\left(x-9\right)+1\)

\(\Leftrightarrow3x-14=2x-18+1\)

\(\Leftrightarrow3x-14=2x-17\)

\(\Leftrightarrow x=-3\)

Vậy x = -3

e) \(\left(x-5\right)^2=9\)

\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

Vậy x = {8; 2}

a. x - (17 - 8) = 5 + (10 - 3x)

=> x - 9 = 5 + 10 - 3x

=> x + 3x = 15 + 9

=> 4x = 24

=> x = 6

b. 25 - (30 + x) = x - (27 - 8)

=> 25 - 30 - x = x - 19

=> -x -x = -19 + 30 - 25

=> -2x = -14

=> x = 7

c. (x - 12) - 15 = (20 - 7) - (18 + x)

=> x - 12 - 15 = 13 - 18 - x

=> x + x = 13 - 18 + 12 + 15

=> 2x = 22

=> x = 11

Cảm ơn nhé bạn Minh Hiền!

a) x - (17 - 8) = 5 + (10 - 3x)

x - 17 + 8 = 5 + 10 - 3x

x + 3x = 5 + 10 + 17 - 8

4x = 24

x = 24 : 4

x = 6

b) 25 - (30 + x) = x - (27 - 8)

25 - 30 - x = x - 27 + 8

-x - x = -27 + 8 - 25 + 30

-2x = -14

x = (-14) : (-2)

x = 7

c) (x - 12) - 15 = (20 - 7) - (18 + x)

x - 12 - 15 = 20 - 7 -18 - x

x + x = 20 - 7 - 18 + 12 + 15

2x = 22

x = 22 : 2

x = 11

d) 9 - 25 = (7 - x) - (25 + 7)

9 - 25 = 7 - x - 25 - 7

x = 7 - 25 - 7 - 9 +25

x = -9

a) \(x+5=20-\left(12-7\right)\)

\(\Rightarrow x+5=20-5\)

\(\Rightarrow x+5=15\)

\(\Rightarrow x=15-5\)

\(\Rightarrow x=10\)

b) \(15-\left(3+2x\right)=2^2\)

\(\Rightarrow3+2x=15-4\)

\(\Rightarrow3+2x=11\)

\(\Rightarrow2x=11-3\)

\(\Rightarrow2x=8\)

\(\Rightarrow x=\dfrac{8}{2}\)

\(\Rightarrow x=4\)

c) \(-11-\left(19-x\right)=50\)

\(\Rightarrow19-x=-11-50\)

\(\Rightarrow19-x=-61\)

\(\Rightarrow x=61+19\)

\(\Rightarrow x=80\)

d) \(159-\left(25-x\right)=43\)

\(\Rightarrow25-x=159-43\)

\(\Rightarrow25-x=116\)

\(\Rightarrow x=25-116\)

\(\Rightarrow x=-91\)

e) \(\left(79-x\right)-43=-\left(17-52\right)\)

\(\Rightarrow\left(79-x\right)-43=52-17\)

\(\Rightarrow79-x-43=35\)

\(\Rightarrow36-x=35\)

\(\Rightarrow x=1\)

f) \(\left(7+x\right)-\left(21-13\right)=32\)

\(\Rightarrow7+x-8=32\)

\(\Rightarrow x-1=32\)

\(\Rightarrow x=32+1\)

\(\Rightarrow x=33\)

g) \(-x+20=-15+8+13\)

\(\Rightarrow-x+20=6\)

\(\Rightarrow x=20-6\)

\(\Rightarrow x=14\)

h) \(-\left(-x+13-142\right)+18=55\)

\(\Rightarrow x-13+142+18=55\)

\(\Rightarrow x+147=55\)

\(\Rightarrow x=55-147\)

\(\Rightarrow x=-92\)

a: =>2^x=32

=>x=5

b: =>7x-11=25*25+200=825

=>7x=836

=>x=836/7

c: =>x(x^9-1)=0

=>x=0 hoặc x^9-1=0

=>x=0 hoặc x=1

a) \(2^x-15=17\)

\(2^x=17+15=32=2^5\)

\(\Rightarrow x=5\)

b) \(\left(7x-11\right)=25.5^2+200\)

\(7x=825+11=836\)

\(x=\dfrac{836}{7}\)

c) \(x^{10}=x\)

\(x^{10}-x=0\)

\(x\left(x^9-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

a, 11 - ( 15 + 11 ) = x - ( 25 - 9 )

11-15-11=x-25+9

-15=x-16

x=1

b, 2 - x = 17 - ( - 5 )

2-x=22

x=-20

c, x - 12 = ( - 9 ) - 15

x-12=-24

x=-12

d, 9 - 25 = ( 7 - x ) - ( 25 + 7 )

(7-x)-32=-16

7-x=16

x=-9

#H

a) -2x-17=-11                b)15-7+2x=-11+25                   c) 43-x-17=-17+25

-2x=6                              8+2x=14                                 26-x=8

x=-3                               2x=6                                       x=18

                                      x=3

d) -42|x|=-15                      e)|x-2|+13=17                                         g)-11<|x|<3

    |x| = + - 5/14                 |x-2|=4                                                   xl mk k biết làm câu này. bạn nào biết giải nốt giúp mk nha!

                                       xét 2 trường hợp x>0 và x<0.        

lần sau bạn có đăng bài dài như thế này thì bạn hãy chia ra làm 2 bài để m.n có hứng giải giúp bạn nha!

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