a, \(\frac{3}{4}x-\frac{1}{5}=\frac{7}{4}x+\frac{11}{5}\)

\(\Rightarrow\frac{3}{4}x-\frac{7}{4}x=\frac{11}{5}+\frac{1}{5}\)

\(\Rightarrow-x=\frac{12}{5}\Rightarrow x=-\frac{12}{5}\)

Vậy ... 

b, \(\frac{x+1}{2}=\frac{8}{x+1}\)

\(\Rightarrow\left(x+1\right)^2=16\)

\(\Rightarrow x+1=4\)hoặc \(x+1=-4\)

\(\Rightarrow x=3\) hoặc  \(x=-5\)

Vậy ..

3/4x-7/4x=1/5+11/5

(3/4-7/4).x=12/5

-1.x=12/5

x=12/5:-1

x=-12/5

vậy x=-12/5

a,\(\frac{3}{4}x-\frac{1}{5}=\frac{7}{4}x+\frac{11}{5}\)

\(< =>\frac{3x}{4}-\frac{7x}{4}=\frac{11}{5}+\frac{1}{5}=\frac{12}{5}\)

\(< =>-\frac{4x}{4}=\frac{12}{5}< =>-x=\frac{12}{5}\)

\(< =>x=-\frac{12}{5}\)

b, \(x+\frac{1}{2}=\frac{8}{x}+1\left(đk:x\ne0\right)\)

\(< =>x-\frac{8}{x}=1-\frac{1}{2}=\frac{1}{2}\)

\(< =>\frac{x^2-8}{x}=\frac{1}{2}\)

\(< =>2x^2-16=x\)

\(< =>2x^2-x+16=0\)

\(\Delta=\left(-1\right)^2-4.2.16 < 0\)

Vô nghiệm  :V bài này sai đề

= 175 - 95 :(18.1+1)

= 175-95 :19

= 175-5

170

9^0+!^9?????????

OK!

=170

4 + 4^3 + 4^5 + 4^7 + ... + 4^23

= ( 4 + 4^3 ) + ( 4^5 + 4^7 ) +.....+ ( 4^22 + 4^23)

=4( 1+16 ) + 4^5( 1+16 ) +....+ 4^22( 1+ 16 )

=4 x 17 + 4^5 x 17+....+ 4^22 x 17 chia hết cho 68

Câu 2:

1+3+3^2+3^3+....+3^2000

=( 1+3 +3^2 ) + ( 3^3 + 3^4 + 3^5 ) +.....+ ( 3^ 1998 + 3^1999 + 3^2000)

=1( 1+ 3 + 9 ) + 3^3 + ( 1+ 3 + 9 ) +......+ 3^1998+( 1+ 3 + 9 )

= 1 x 13+ 3^3 x 13 +......+ 3^1998 x 13 chia hết cho 13

k mk nha lần sau mk k lại

Câu 1 nha : 4+4^3+4^5+4^7+....+4^23 = (4+4^3)+(4^5+4^7)+....+(4^21+4^23)

= 68 + 4^4.(4+4^3)+....+4^20.(4+4^3) = 68 + 4^4.68 + .... + 4^20.68

=68.(1+4^4+....+4^20) chia hết cho 68

Câu 2 nha 1+3+3^2+...+3^2000 = (1+3+3^2)+(3^3+3^4+3^5)+....+(3^1998+3^1999+3^2000)

= 13 + 3^3.(1+3+3^2)+....+3^1998.(1+3+3^2) = 13+3^3.13+....+3^1998.13

=13.(1+3^3+....+3^1998) chia hết cho 13

cảm ơn 2 bạn nhiều

a)        \(\left(\frac{2x}{3}-3\right):\left(-10\right)=\frac{2}{5}\)

   <=>   \(\frac{2x}{3}-3=\frac{2}{5}.\left(-10\right)\)

   <=>   \(\frac{2x}{3}-3=-4\)

   <=>    \(\frac{2x}{3}=-4+3=-1\)

   <=>     \(2x=-1.3=-3\)

   <=> \(x=\frac{-3}{2}\)

Vậy \(x=\frac{-3}{2}\)

b) \(1,5x-2\frac{1}{3}x=1,5-\frac{2}{3}\)

\(x.\left(1,5-2\frac{1}{3}\right)=\frac{5}{6}\)

\(x.\left(\frac{-5}{6}\right)=\frac{5}{6}\)

\(x=\frac{5}{6}:\left(\frac{-5}{6}\right)=\frac{5}{6}.\left(\frac{-6}{5}\right)=-1\)

Vậy \(x=-1\)

Nếu đúng thì cho mình nhé, chúc bạn học tốt !

kết quả phép tính này =0 nha bạn

k mik nha.

\(\dfrac{7}{12}< \dfrac{x}{24}< \dfrac{2}{3}\) 

→ \(\dfrac{7}{12}=\dfrac{7x2}{12x2}=\dfrac{14}{24}\)

→ \(\dfrac{2}{3}=\dfrac{2x8}{3x8}=\dfrac{16}{24}\)
⇒ x\(=\)15

\(\Leftrightarrow14< x< 16\)

hay x=15

x=15

k nhé

please

3/5 x = 5/6

x = 5/6 : 3/5

x = 25/18

\(\dfrac{3}{5}:x=\dfrac{1}{3}+\dfrac{1}{2}\)

\(\dfrac{3}{5}:x=\dfrac{5}{6}\)

\(x=\dfrac{3}{5}:\dfrac{5}{6}\)

\(x=\dfrac{18}{25}\)

3/5:*=1/3+1/2

3/5:*=5/6

*=5/6:3/5

*=25/18