Tính tổng:
A=1/6+1/12+1/20+...+1/870.
Tính tổng:a)3+3/5+3/25+3/125+3/625
b)M=4/3.7+4/7.11+4/11.15+...+8/95.99
c)N=1/2+1/6+1/12+1/20+...+1/90
Ta có : \(M=\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+.....+\frac{4}{95.99}\)
\(=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+......+\frac{1}{95}-\frac{1}{99}\)
\(=\frac{1}{3}-\frac{1}{99}\)
\(=\frac{32}{99}\)
Tính tổng:
a) 1 + (-2) + 3 + (-4) + 5 + (-6) + … + 19 + (-20)
Tính tổng:A=1-5/6+7/12-9/20+11/30-13/42+15/56-17/72+19/90=?
Chúc may mắn!
Câu 1: Tính tổng:
A= 1-1/2+1-1/6+1-1/12+1-1/12+1-1/20+1-1/30+1-1/42+1-1/56+1-1/72+1-1/89
Câu 2: Tính:
B= 1/7 + 1/91 + 1/247 + 1/475 + 1/775 + 1/1147
Câu 3: Tính:
C= 1/3+1/6+1/10+1/15+.....+1/45
Câu 4: Tính:
D= 1/1.2.3+1/2.3.4+1/3.4.5+.....+1/18+19+20
Câu 5: Tính:
A=1/999 - 1/199.198 - 1/198.197 - 1/197.196-......-1/3.2-1/2.1
Mọi người giúp mình gấp với. Mình cảm ơn nhiều.
1)Tính tổng:a)3+3/5+3/25+3/125+3/625
b)M=4/3.7+4/7.11+4/11.15+...+8/95.99
c)N=1/2+1/6+1/12+1/20+...+1/90
2)Cho K=1+1/3+1/1/6+1/10+...+1/45 so sánh K với 2
Ta có ; K = \(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+.....+\frac{1}{45}\)
\(=1+\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+....+\frac{2}{90}\)
\(=1+\left(\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+.....+\frac{2}{9.10}\right)\)
\(=1+2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+.....+\frac{1}{9.10}\right)\)
\(=1+2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=1+2\left(\frac{1}{2}-\frac{1}{10}\right)\)
\(=1+1-\frac{1}{5}\)(nhân phá ngoặc)
\(=2-\frac{1}{5}\)< 2
Vậy K = \(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+.....+\frac{1}{45}\)< 2
TÍNH TỔNG:
A=\(\frac{1}{6}\)+\(\frac{1}{12}\)+\(\frac{1}{20}\)+.......+\(\frac{1}{870}\)
Ta có:
\(A=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{870}\)
\(=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+....+\frac{1}{29.30}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-.....+\frac{1}{29}-\frac{1}{30}\)
\(=\frac{1}{2}-\frac{1}{30}=\frac{15}{30}-\frac{1}{30}=\frac{14}{30}=\frac{7}{15}\)
Vậy \(A=\frac{7}{15}\)
\(A=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{870}\)
\(A=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{29.30}\)
\(A=\frac{1}{2}-\frac{1}{30}\)
\(A=\frac{7}{15}\)
A= 1/6 + 1/12 + 1/20 + ... + 1/870
= 1/2.3 + 1/3.4 + 1/4.5 + ... + 1/29.30
= 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/29 - 1/30
= 1/1 -1/30
=30/30 -1/30
A =29/30.
Tính tổng:a, E=1+3+6+...+4950
b, D=2+6+12+...+9900
a)E=1+3+6+...+4950
2E=1.2+3.2+6.2+...+4950.2
2E=2+6+12+...+9900
Ta có: Xét D=1.2+3.2+6.2+...+4950.2
3D=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
3D=99.100.101
D=333300
Thay D vào E ta được 2E=333300 => E=166650
b)B=1+3+6+12+...+9900
2B=1.2+3.2+6.2+12.2+...+9900.2
2B=2+6+12+24+...+19800
Ta có xét A=1.2+3.2+6.2+12.2+...+9900.2
3A=1.2.3+3.2.6-1.2.3+...100.2.3
3A=98.100.102
A=33320
ta thay A vào B; 2B=33320=>B=16660
1 phần 2+1 phần 6+1 phần 12+1 phần 20+1 phần 30+1 phần 42+1 phần 56+...+1 phần 756+1 phần 812+1 phần 870
A = \(\dfrac{1}{2}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{12}\) + \(\dfrac{1}{20}\)+...+ \(\dfrac{1}{812}\) + \(\dfrac{1}{870}\)
A = \(\dfrac{1}{1.2}\) + \(\dfrac{1}{2.3}\) + \(\dfrac{1}{3.4}\) + \(\dfrac{1}{4.5}\)+...+ \(\dfrac{1}{28\times29}\)+ \(\dfrac{1}{29\times30}\)
A = \(\dfrac{1}{1}\) - \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\) +...+\(\dfrac{1}{28}\)-\(\dfrac{1}{29}\)+ \(\dfrac{1}{29}\) - \(\dfrac{1}{30}\)
A = 1 - \(\dfrac{1}{30}\)
A = \(\dfrac{29}{30}\)
B=1+3+6+10+15+.........+435
C=1/2+1/6+1/12+1/20+1/30+.........1/870
D=3/4+5/36+7/144+9/400
E=3+4+6+9+13+18+...........+2019
\(C=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{870}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{29.30}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{29}-\frac{1}{30}\)
\(=1-\frac{1}{30}\)
\(=\frac{29}{30}\)