a) \(27\cdot75+25\cdot27-150\cdot2023^0\)

\(=27\cdot\left(75+25\right)-150\cdot1\)

\(=27\cdot100-150\)
\(=2700-150\)

\(=2550\)

b) \(3^x+3^{x+1}+16\cdot4=2^2\cdot5^2\)

\(\Rightarrow3^x+3^x\cdot3=100-64\)

\(\Rightarrow3^x\cdot\left(1+3\right)=36\)

\(\Rightarrow3^x\cdot4=36\)

\(\Rightarrow3^x=36:4\)

\(\Rightarrow3^x=9\)

\(\Rightarrow3^x=3^2\)

\(\Rightarrow x=2\)

a) 27.75 + 25.27 - 150.2023⁰

= 27.(75 + 25) - 150.1

= 27.100 - 150

= 2700 - 150

= 2550

b) 3ˣ + 3ˣ⁺¹ + 16.4 = 2².5²

3ˣ.(1 + 3) + 64 = 4.25

3ˣ.4 + 64 = 100

3ˣ.4 = 100 - 64

3ˣ.4 = 36

3ˣ = 36 : 4

3ˣ = 9

3ˣ = 3²

x = 2

a)39 . 213 + 87 . 39

=39 . (213 + 87 )

=39 .      300

=      11700

b)27 . 75 + 25 . 27 - 150

=27 . (75 + 25) - 150

=27 .     100    - 150

=     2700        - 150

=           2550

a) Ta có: \(39.213+87.39=39.\left(213+87\right)\)

                                                 \(=39.300\)

                                                 \(=11700\)

b) Ta có: \(27.75+25.27-150=27.\left(75+25\right)-150\)

                                                              \(=27.100-150\)

                                                              \(=2700-150\)

                                                              \(=2550\)

a) 39 . 213 + 87 .39

=39( 213+87)

=39 . 300

=39.3.100

=117 . 100

=11700

b) 27 . 75 + 25 . 27 -150

=27(75 + 25 ) - 150

=27 . 100 - 150

=2700 - 150 

=2550

\(12x-33=3^2.3^3\)

\(\Rightarrow12x-33=3^5\)

\(\Rightarrow12x-33=243\)

\(\Rightarrow12x=243+33\)

\(\Rightarrow12x=276\)

    \(\Rightarrow x=276:12\)

    \(\Rightarrow x=23\)

tíc mình nha

2,  27.75+25.27-150

=27.(75+25) - 150

=27.100 -15.10

=27.10.10 - 15.10

=10.(27.10 -15)

=10.(270-15)

=10.255

=2550

1,   \(12x-33=\)\(^{3^2.3^3}\)

\(12x-33=9.27\)

\(12x-33=243\)

12x=243+33

12x=276

x=276 : 12

x=23

a) `123 - 27 + 27 + 13 - 123`

`= (123 - 123) + (27 - 27) + 13`

`= 0 + 0 + 13`

`= 13`

`---`

b) `175 + 25 + 13 + 15 - 175 - 25`

`= (175-175)+(25-25)+25+13`

`=0+0+25+13`

`=28`

`---`

c) \(53\times39+47\times39+53\times21+47\times21\)

\(=\text{[}\left(53+47\right)\times39]+\left[\left(53+47\right)\times21\right]\)

\(=\left(100\times39\right)+\left(100\times21\right)\)

\(=3900+2100\)

`=6000`

`---`

d) \(49\times35+49\times16-49\times61\)

`=` \(49\times\left(35+16-61\right)\)

`=` \(49\times\left(-10\right)\)

`=-490`

a) 42x99-21x176-35x12

=4158-3696-420

=42

b){[213^0+(999-998)^324]x2-12x5}-4^9:4^6

={[1+1^324]x2-60}-4^3

={[1+1]x2-60}-64

={2x2-60}-64

={4-60}-64

=-56-64

=-120

c)|-27|+(-25)-(-13)

=27+(-25)+13

=2+13

=15

27 . 75 + 25 . 27 - 150

= 27 . ( 75 + 25 ) - 150

= 27 . 100 - 150

= 2700 - 150

= 2550

ý lộn sory nhá 27 mà mk làm 25

27.75+25.27-150

=27.( 75 + 25 ) -150

=27.100 - 150

=2700-150

=2550

#Chúc bạn học tốt.Tick cho mk nhé!

Bài 1: Thực hiện các phép tính sau:

\(a)\)Chưa rỏ đề

\(b)\)\(5025\div5-25\div5\)

\(=\)\(1005-5\)

\(=\)\(1000\)

\(c)\)\(218-180\div2\div9\)

\(=\)\(218-10\)

\(=\)\(208\)

\(d)\)\(\left(328-8\right)\div32\)

\(=\)\(320\div32\)

\(=\)\(10\)

Bài 1:

a) ( Tôi không nhìn rõ đầu bài )

b) 5025  :  5  -  25  :  5

=  ( 5025  -  25 )  :  5

=        5000   :   5

=       1000

c)   218  -  180  :  2  :  9

=     218   -    180  :  (  2  .  9 )

=      218    -    180   :  18

=       218    -    10

=       208

d)   (  328  -  8  )  :  32

=      320   :   32

=     10 

Bài 2: Thực hiện phép tính:

\(a)\)\(27.75+25.27-150\)

\(=\)\(27.\left(75+25\right)-150\)

\(=\)\(27.100-150\)

\(=\)\(2700-150\)

\(=\)\(2550\)

\(b)\)\(12\div\left\{400\div\left[500-\left(125+25.7\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-\left(125+175\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-300\right]\right\}\)

\(=\)\(12\div\left\{400\div200\right\}\)

\(=\)\(12\div2\)

\(=\)\(6\)

\(c)\)\(13.17-256\div16+14\div7-1\)

\(=\)\(221-16+2-1\)

\(=\)\(206\)

\(d)\)\(18\div3+182+3.\left(51\div17\right)\)

\(=\)\(6+182+3.3\)

\(=\)\(6+182+9\)

\(=\)\(197\)