mik tick cho

3/11 x 2 = 6/11

6/11 : 3/11 = 2

6/11 : 2 = 3/11

2/3 x 11 = 22/3

4/2 x 7 = 14

8/7 : 2/7 = 4

8/7 : 4 = 2/7

2/7 x 4 = 8/7

bài 1: 

\(2\dfrac{3}{4}:1\dfrac{1}{3}=\dfrac{11}{4}:\dfrac{4}{3}=\dfrac{33}{16}\)

Các bài toán này bn bấm máy thì sẽ ra nha.

Bài 7 có quy tắc tính trong ngoặc trước, ngoài ngoặc sau.

7b bn nhóm 2/3 +1/18 lại vào một chỗ và để cho chúng dấu ngoặc

tíc mình nha

= 4x4/3x7+ 4x4/7x11+ 4x4/11x15 = 4x(4/3x7 + 4/7x11+4/11x15) =4x(1/3-1/7+1/7-1/11+1/11-1/15) =4x(1/3-1/15)=4x4/15= 16/15.

= 4x4/3x7+ 4x4/7x11+ 4x4/11x15

= 4x(4/3x7 + 4/7x11+4/11x15)
=4x(1/3-1/7+1/7-1/11+1/11-1/15)
=4x(1/3-1/15)=4x4/15= 16/15.

a, \(\dfrac{38}{7}\) + ( \(\dfrac{16}{7}\) - \(\dfrac{5}{3}\))

= \(\dfrac{38}{7}\) + \(\dfrac{16}{7}\) - \(\dfrac{5}{3}\)

= \(\dfrac{54}{7}\) - \(\dfrac{5}{3}\)

= \(\dfrac{162}{21}\) - \(\dfrac{35}{21}\)

= \(\dfrac{127}{21}\)

b, \(\dfrac{29}{9}\) - ( \(\dfrac{14}{9}\) + \(\dfrac{11}{9}\) )

= \(\dfrac{29-14-11}{9}\)

= \(\dfrac{4}{9}\)

c, ( \(\dfrac{2}{7}\) + \(\dfrac{3}{8}\) + \(\dfrac{12}{7}\) + \(\dfrac{5}{8}\) ) - \(\dfrac{19}{63}\)

= ( \(\dfrac{2+12}{7}\) + \(\dfrac{3+5}{8}\)) - \(\dfrac{19}{63}\)

= \(\left(1+2\right)\) - \(\dfrac{19}{63}\)

= \(3-\dfrac{19}{63}\)

= \(\dfrac{189}{63}\) - \(\dfrac{19}{63}\)

= \(\dfrac{170}{63}\)

d, \(\dfrac{3}{7}\) . \(\dfrac{4}{9}\) + \(\dfrac{4}{9}\) . \(\dfrac{4}{7}\) - \(\dfrac{4}{9}\)

= \(\dfrac{4}{9}\) . ( \(\dfrac{3}{7}\) + \(\dfrac{3}{7}\) ) - \(\dfrac{4}{9}\)

= \(\dfrac{4}{9}\) . \(1-\dfrac{4}{9}\)

= \(\dfrac{4}{9}\) - \(\dfrac{4}{9}\)

= 0

chú ý dấu chấm là dấu nhân

4) \(\left(\dfrac{3}{7}\right)^2\cdot\left(-7\right)^4\)

\(=\left(\dfrac{3}{7}\right)^2\cdot\left[\left(-7\right)^2\right]^2\)

\(=\left(\dfrac{3}{7}\right)^2\cdot49^2\)

\(=\left(\dfrac{3}{7}\cdot49\right)^2\)

\(=\left(\dfrac{147}{7}\right)^2\)

\(=21^2\)

\(=441\)

5) \(\left(-11\right)^{12}\cdot\left(\dfrac{4}{11}\right)^6\)

\(=\left[\left(-11\right)^2\right]^6\cdot\left(\dfrac{4}{11}\right)^6\)

\(=121^6\cdot\left(\dfrac{4}{11}\right)^6\)

\(=\left(121\cdot\dfrac{4}{11}\right)^6\)

\(=44^6\)

6) \(6^8\cdot\left(\dfrac{5}{7}\right)^7\)

\(=6^8\cdot\dfrac{5^7}{6^7}\)

\(=\dfrac{6^8\cdot5^7}{6^7}\)

\(=6\cdot5^7\)

\(=469750\)

\(\left(\dfrac{3}{7}\right)^2\cdot\left(-7\right)^4=\dfrac{9}{49}\cdot49^2=9\cdot49=441\)

\(\left(-11\right)^{12}\cdot\left(\dfrac{4}{11}\right)^4=11^{12}\cdot\dfrac{4^4}{11^4}=11^8\cdot4^4=54875873536\) 

\(\left(-6\right)^8\cdot\left(\dfrac{5}{6}\right)^7=6^8\cdot\dfrac{5^7}{6^7}=6\cdot5^7=469750\)

a: Dấu hiệu là thời gian giải bài

Số các giá trị là 10

b: 

Mốt là 7 và 8

c: Phần lớn làm xong trong 7 hoặc 8 phút