A=\(\frac{1}{12}\)+\(\frac{1}{13}\)+\(\frac{1}{14}\)+\(\frac{1}{15}\)+\(\frac{1}{16}\)+\(\frac{1}{17}\)

A< \(\frac{1}{12}\)+\(\frac{1}{12}\)+\(\frac{1}{12}\)+\(\frac{1}{12}\)+\(\frac{1}{12}\)+\(\frac{1}{12}\)

A<6.\(\frac{1}{12}\)

A<\(\frac{1}{2}\)

Vậy A<\(\frac{1}{2}\)

b.\(\frac{53}{57}\)=1-\(\frac{4}{57}\)=1-\(\frac{40}{570}\)

\(\frac{531}{571}\)=1-\(\frac{40}{571}\)

Ta có:\(\frac{40}{570}\)>\(\frac{40}{571}\)=> 1-\(\frac{40}{570}\)<1-\(\frac{40}{571}\)=>\(\frac{53}{57}\)<\(\frac{531}{571}\)

#A=1/2

#Linh

\(A=\frac{\left(23\frac{11}{15}-26\frac{13}{20}\right)}{12^2+5^2}\cdot\frac{1-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}}{3^2.13.2-13.5}-\frac{19}{37}\)

\(A=\frac{\left(23+\frac{11}{15}-26+\frac{13}{20}\right)}{144+25}\cdot\frac{1-\frac{1}{5.6}-\frac{1}{6.7}-\frac{1}{7.8}}{9.13.2-13.5}-\frac{19}{37}\)

\(A=\frac{\left(23+26+\frac{11}{15}-\frac{13}{20}\right)}{169}\cdot\frac{1-\left(\frac{1}{5}-\frac{1}{6}\right)-\left(\frac{1}{6}-\frac{1}{7}\right)-\left(\frac{1}{7}-\frac{1}{8}\right)}{13.\left(9.2-5\right)}-\frac{19}{37}\)

\(A=\frac{49+\frac{44}{60}-\frac{39}{60}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{6}-\frac{1}{6}+\frac{1}{7}-\frac{1}{7}+\frac{1}{8}}{13.13}-\frac{19}{37}\)

\(A=\frac{49+\frac{1}{20}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{8}}{169}-\frac{19}{37}\)

\(A=\frac{49\frac{1}{20}}{169}\cdot\frac{\frac{4}{5}+\frac{5}{40}}{169}-\frac{19}{37}\)

\(A=\frac{981}{169}\cdot\frac{\frac{32}{40}+\frac{5}{40}}{169}-\frac{19}{37}\)

\(A=\frac{981}{169}\cdot\frac{\frac{37}{40}}{169}-\frac{19}{37}\)

\(A=\frac{981.\frac{37}{40}}{169^2}-\frac{19}{37}\)

\(A=\frac{\frac{36297}{40}}{28561}-\frac{19}{37}\)

\(A=\frac{907,425}{28561}-\frac{19}{37}\)

\(A=\frac{33574,725}{1056757}-\frac{542659}{1056757}\)

\(A=\frac{-509084,275}{1056757}=-0,04604282...\)

Mik chỉ làm đc thế này thôi, ôn thi học kì II tốt nha bạn!

((1+1000)-1)/5 = 200 (chia khoảng cách)

Từ 1 - 100 có 10 số có chứa số 5 mà 1000 : 100 = 10

Số chữ số 5 là :

\(\frac{\left(1+1000\right)-1}{5}=200\)

Đáp số

\(\dfrac{x}{3}-2=\dfrac{1}{15}\)

=>\(\dfrac{x}{3}=2+\dfrac{1}{15}=\dfrac{31}{15}\)

=>\(x=\dfrac{31}{15}\cdot3=\dfrac{31}{5}\)

  31/17 + (-5/13) + (-8/13) - 14/17

= ( 31/17 - 14/17 ) + (-5/13) + (-8/13)

= 17/17 + ( -13/13)

= 1 + ( -1 )

= 0

HỌC TỐT!

k nhớ

\(\frac{31}{17}\) + \(\frac{-5}{13}\) + \(\frac{-8}{13}\) - \(\frac{14}{17}\)

=(\(\frac{31}{17}\) -  \(\frac{14}{17}\) ) +( \(\frac{-5}{13}\) + \(\frac{-8}{13}\))

=1 + -1

=0

Học tốt

31/17+(-5/13)+(-8/13)-14/17

=(31/17-14/17)+(-5/13)+(-8/13)

=17//17+(-13+13)

=1+(-1)

=0

ht