a,/2X+3/+2x/4-x/
b,4x/Xx5/+2x/2X+4/=12
1. a. 4x-20=0
b. 2x+x+12=0
c. x-5=3-x
d. 7-3x=9-x
2.
a. 7+2x=22-3x
b. 8x-3=5x+12
c. x-12+4x=25+2x-1
d. x+2x+3x-19=3x+5
e. 7-(2x+4)=-(x+4)
f. (x-1)-(2x-1)=9-x
Tìm x biết :
a, 4.(18 - 5x) - 12.(3x - 7) = 15.(2x - 16) - 6(x + 14)
b, 5.(3x + 5) - 4.(2x - 3) = 5x + 3.(2x + 12) + 1
c, 2.(5x - 8) - 3.(4x - 5) = 4.(3x - 4) + 11
d, (3x + 2)(2x + 9) - (x + 2)(6x + 1) = (x + 1) - (x - 6)
e, (8x - 3)(3x + 2) - (4x + 7)(x + 4)= (2x + 1)(5x - 1) - 33
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
b, 5(3x + 5) - 4(2x - 3) = 5x + 3(2x + 12) + 1
=> 15x + 25 - 8x + 12 = 5x + 6x + 36 + 1
=> (15x - 8x) + (25 + 12) = 11x + 37
=> 7x + 37 = 11x + 37
=> 11x - 7x = 0
=> x = 0
Tìm x biết:
a) 4(18-5x) - 12(3x-7) = 15(2x-16) - 6(x+14)
b) 5(3x+5) - 4(2x-3) = 5x+3(2x+12)+1
c)2(5x-8) - 3(4x-5) = 4(3x-4) + 11
d) 5x-3 {4x-2 [4x-3(5x-2)]}=182
3,26 + 4/5 =?
làm nhanh lên giúp mình nhé
3,26+4/5=3,26+0,8=3,34
K cho mình cái
\(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Leftrightarrow10x-16-12x+15=12x+16+11\)
\(\Leftrightarrow-2x-1=12x+27\Leftrightarrow-14x-28=0\Leftrightarrow x=-2\)
Tìm x:
1/ 4.(18-5x)-12.(3x-7)=15.(2x-16)-6.(x+14) 2/5.(3x+5)-4(2x-3)=5x+3.(2x+12)+1 3/2.(5x-8)-3(4x-5)=4(3x-4)+11 4/5x-3.{4x-2.[4x-3(5x-2)]}=182a, \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)
\(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow-20x-36x-30x+6x=-240-84-72-84\)
\(\Rightarrow-80x=-480\Rightarrow x=6\)
b, \(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x+12\right)+1\)
\(\Rightarrow15x+25-8x+12=5x+6x+36+1\)
\(\Rightarrow15x-8x-5x-6x=36+1-25-12\)
\(\Rightarrow-4x=0\Rightarrow x=0\)
c, \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow10x-12x-12x=-16+11+16-15\)
\(\Rightarrow-14x=-4\Rightarrow x=\dfrac{2}{7}\)
d, \(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(\Rightarrow5x-3\left[4x-2\left(4x-15x+6\right)\right]=182\)
\(\Rightarrow5x-3\left(4x-8x+30x-12\right)=182\)
\(\Rightarrow5x-12x+24x-90x+36=182\)
\(\Rightarrow-73x=182-36\)
\(\Rightarrow-73x=146\Rightarrow x=-2\)
Chúc bạn học tốt!!!
Tìm x:
a) 4(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
b) 5(3x + 5) - 4(2x - 3) = 5x + 3(2x + 12) + 1
c) 2(5x - 8) - 3(4x - 5) = 4(3x - 4) +11
d) 5x - 3{4x - 2[4x - 3(5x - 2)]} = 182
a, \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)
\(\Leftrightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Leftrightarrow156-56x=24x-324\)
\(\Leftrightarrow-80x+480=0\Leftrightarrow x=-6\)
b, \(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x-12\right)+1\)
\(\Leftrightarrow15x+25-8x+12=5x+6x-36+1\)
\(\Leftrightarrow7x+37=11x-35\)
\(\Leftrightarrow-4x+72=0\Leftrightarrow x=18\)
c, \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Leftrightarrow10x-16-12x+15=12x-16+11\)
\(\Leftrightarrow-2x-1=12x-5\)
\(\Leftrightarrow-14x+4=0\Leftrightarrow x=\frac{2}{7}\)
d, \(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(\Leftrightarrow5x-3\left[4x-15x+6\right]=182\)
\(\Leftrightarrow5x-3\left(-11x+6\right)=182\)
\(\Leftrightarrow5x+33x-18-182=0\)
\(\Leftrightarrow38x-200=0\Leftrightarrow x=\frac{100}{19}\)
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Giải các phương trình sau :
a) 2x+7 /3 + x-2 /4. = -2
b) x-1 /4. + 2x+1 /3. = x
c) 2x-1 /2 + 4x+3 /5 = 3x
d) x+1 /4. +. 3x-2 /12. = 2x+3 /15
a) \(\dfrac{2x+7}{3}+\dfrac{x-2}{4}=-2\)
\(\Leftrightarrow\dfrac{4\left(2x+7\right)}{12}+\dfrac{3\left(x-2\right)}{12}=\dfrac{-24}{12}\)
\(\Leftrightarrow8x+28+3x-6=-24\)
\(\Leftrightarrow11x=-46\)
\(\Leftrightarrow x=\dfrac{-46}{11}\)
Vậy S={-46/11}
b) \(\dfrac{x-1}{4}+\dfrac{2x+1}{3}=x\)
\(\Leftrightarrow\dfrac{3\left(x-1\right)}{12}+\dfrac{4\left(2x+1\right)}{12}=\dfrac{12x}{12}\)
\(\Leftrightarrow3x-3+8x+4=12x\)
\(\Leftrightarrow-x=-1\)
\(\Leftrightarrow x=1\)
Vậy S={1}
c) \(\dfrac{2x-1}{2}+\dfrac{4x+3}{5}=3x\)
\(\Leftrightarrow\dfrac{5\left(2x-1\right)}{10}+\dfrac{2\left(4x+3\right)}{10}=\dfrac{30x}{10}\)
\(\Leftrightarrow10x-5+8x+6=30x\)
\(\Leftrightarrow-12x=-1\)
\(\Leftrightarrow x=\dfrac{1}{12}\)
Vậy S={1/12}
d). \(\dfrac{x+1}{4}+\dfrac{3x-2}{12}=\dfrac{2x+3}{15}\)
\(\Leftrightarrow\dfrac{15\left(x+1\right)}{60}+\dfrac{5\left(3x-2\right)}{60}=\dfrac{4\left(2x+3\right)}{60}\)
\(\Leftrightarrow15x+15+15x-10=8x+12\)
\(\Leftrightarrow22x=7\)
\(\Leftrightarrow x=\dfrac{7}{22}\)
Vậy S={7/22}
2x ^3 -5x^2+4x-1) : (2x+1)
(x63 -2x+4) ; (x+2)
(6x^3 - 19x^2+23x-12):(2x-3)
(x^4 - 2 x ^3 - 1+ 2 x ):(x^2 - 1)
(6x^3 - 5x^2 + 4x -1 ) : (2x^2-x+1)
(x^4 -5x^2+4):(x^2-3x+2)
d: \(\dfrac{x^4-2x^3+2x-1}{x^2-1}\)
\(=\dfrac{\left(x^2-1\right)\left(x^2+1\right)-2x\left(x^2-1\right)}{x^2-1}\)
\(=x^2-2x+1\)
\(=\left(x-1\right)^2\)
Bài 1: tìm x
(3x + 2)² = 2x .(2x +3) +4
Bài 2: cho A, B và Q là các đa thức ( B ≠ 0) Tìm Q
(1)A= 8 - x³ - 2x + x²; B = 2-x và A= B .Q
(2) A= 2x³ - 3x² + 3x - 9 ; B= 2x-3 và A= B .Q
(3) A = 3x⁴ +2x³ - 4x² - 6x - 15 ; B= x² - 3 và A= B .Q
(4) A= 8x³ - 18x² + 5x - m chia hết cho đa thứcB = 2x - 3
(5) A= 3x³ - 10x² + 17x - 12
B= 3x - 4
(6) A= 2x³ - x² + 5x - 12
B= 2x - 3
(7) A= 8x³ - 1 ; B= 2x - 1
(8) 3x⁴ + 2x³ - 4x² - 6x - 15
B= x² - 3
(9) A= x⁴ - 4x³ - x² + 24x - 30
B= x² - 6
(10) A=x⁴ - 3x³ + 8x² - 15x + 15 B= x² - 6
(11) A= 3x² - 10x² + 17x - 12
B= 3x - 4
(12) A= 2x³ + 9x² + 9x - 7
B= 2x - 1
(13) A= 2x³ + x² + 3 - x
B= 2x + 3
Giúp mk nha
phân tích đa thức thành nhân tử
a) 4x (a-b) +6xy(b-a)
b) (6x+3) - ( 2x-5) (2x+1)
c) 4 ( x-3)^2 +2x (3-x)
d) x^4 +2x^2 -4x-4
e) 2x (x+y) -x -y
g)( 3x-1 )^2 - (x+3)^2
a) \(4x\left(a-b\right)+6xy\left(b-a\right)\)
\(=4x\left(a-b\right)-6xy\left(a-b\right)\)
\(=\left(4x-6xy\right)\left(a-b\right)\)
\(=2x\left(2-3y\right)\left(a-b\right)\)
b) \(\left(6x+3\right)-\left(2x-5\right)\left(2x+1\right)\)
\(=3\left(2x+1\right)-\left(2x-5\right)\left(2x+1\right)\)
\(=\left(3-2x+5\right)\left(2x+1\right)\)
\(=\left(8-2x\right)\left(2x+1\right)\)
\(=2\left(4-x\right)\left(2x+1\right)\)
g: \(\left(3x-1\right)^2-\left(x+3\right)^2\)
\(=\left(3x-1-x-3\right)\left(3x-1+x+3\right)\)
\(=\left(2x-4\right)\left(4x+2\right)\)
\(=4\left(x-2\right)\left(2x+1\right)\)