(x+5)(4x+3)=31(x+5)
(x-5)(4x+3)=31(x-5)
\(\left(x-5\right)\left(4x+3\right)=31\left(x-5\right)\\ \Leftrightarrow\left(x-5\right)\left(4x+3\right)-31\left(x-5\right)=0\\ \Leftrightarrow\left(x-5\right)\left(4x+3-31\right)\\ \Leftrightarrow\left(x-5\right)\left(4x-28\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=7\end{matrix}\right.\)
Câu 1: giải phương trình sau: a, 3x + 25 = 0 b, (x - 5)(4x + 3) = 31(x - 5) c, 3/x+3 - 1/x-1 = 5x-33/(x+3).(x-1)
a: =>3x=-25
=>x=-25/3
b: =>(x-5)(4x+3-31)=0
=>(4x-28)(x-5)=0
=>x=5 hoặc x=7
c: =>3x-3-x-3=5x-33
=>2x-6=5x-33
=>-3x=-27
=>x=9(nhận)
a) -2(2x + 5) - ( 31 - 4x ) = -(2016 -x)
b) 3.(5 - 2x ) - 5(3-x) + 5 = -(3-2x)
các bạn giải lời giải ra giùm mình nha
a, <=> -4x-10-31+4x=-2016+x
<=> -10-31=-2016+x
<=> -41=-2016+x
<=> x=1975
Tìm x, biết
a) -x²+324=0
b) 16x²-5=0
c) √4x²-√4x+√1=3
d) √x+√3>=5
e) √x+9<=31
a: =>(18-x)(18+x)=0
=>x=18 hoặc x=-18
b: =>16x2=5
=>x2=5/16
hay \(x=\pm\dfrac{\sqrt{5}}{4}\)
d: =>x+căn 3>=25
=>x>=25-căn 3
a) 4x^5-3=125
b) 31+45:x=46
c) 72-x:7=59
d) 3^x=81
e) x^5=32
f) (x-1)^4=625
TIM x
a) 4x^5-3=125
b) 31+45:x=46
c) 72-x:7=59
d) 3^x=81
e) x^5=32
f) (x-1)^4=625
a)4x5=125+3
4x5=128
x5=128:4
x5=32
x5=25
Vậy x=2
Tìm x biết
(2x-3)(6x-4)-(3x+1)(5x-5)=31
(2x-3)(4x-5)-(8x+1)(x-2)=12
Giúp mk với
a: \(\left(2x-3\right)\left(6x-4\right)-\left(3x+1\right)\left(5x-5\right)=31\)
\(\Leftrightarrow12x^2-8x-18x+12-\left(15x^2-15x+5x-5\right)=31\)
\(\Leftrightarrow12x^2-20x+12-15x^2+10x+5-31=0\)
\(\Leftrightarrow-3x^2-10x-14=0\)
\(\Leftrightarrow3x^2+10x+14=0\)
\(\text{Δ}=10^2-4\cdot3\cdot14=100-168=-68< 0\)
Do đó: Phương trình vô nghiệm
b: \(\left(2x-3\right)\left(4x-5\right)-\left(8x+1\right)\left(x-2\right)=12\)
\(\Leftrightarrow8x^2-10x-12x+15-\left(8x^2-16x+x-2\right)=12\)
\(\Leftrightarrow8x^2-22x+15-8x^2+15x+2=12\)
=>-7x+17=12
=>-7x=-5
hay x=5/7
Tính giá trị của biểu thức
a) A=x3-30x2-31+1 tại x=31
b) B=x5-15x4+16x3-29x2+13x tại x=14
c) C=x14-10x13+10x12-10x11+...+10x2-10x+10 tại x=9
d) D=7x(x-5)+3(x-2) tại x=0
e) E=5-4x(x-2)+4x2 tại x=4
f) F=4x2-2x+3x(x-5) tại x=-1
g) G=(5x-7)(7x+3)-(7x+2)(5x-4) tại x=-3
h) H=(-5x+4)(3x-2)+(-2x+3)(x-2) tại x=-2
Mấy bài kia phá tung tóe rồi rút gọn hết sức xong thay x vào, làm câu c thôi nhé:
c) \(C=x^{14}-10x^{13}+10x^{12}-10x^{11}+...+10x^2-10x+10\)
riêng câu này ta thay x = 9 vào luôn, vậy ta có:
\(C=9^{14}-10\cdot9^{13}+10\cdot9^{12}-10\cdot9^{11}+...+10\cdot9^2-10\cdot9+10\)
\(=9^{14}-\left(9+1\right)\cdot9^{13}+\left(9+1\right)\cdot9^{12}-\left(9+1\right)\cdot9^{11}+...+\left(9+1\right)\cdot9^2-\left(9+1\right)\cdot9+10\)
\(=9^{14}-9^{14}-9^{13}+9^{13}+9^{12}-9^{12}-9^{11}+...+9^3+9^2-9^2-9+10\)
\(=-9+10\)
\(=1\)
Tìm x biết
(X + 3)2 - x . ( x - 5) = 31
( 4x + 3) . (x - 2) - ( 2x-1)2 = 50
( 3x + 5 ).(3x - 5) - 9x(x + 20 = 18
\(\left(x+3\right)^2-x\left(x-5\right)=31\)
\(\Leftrightarrow x^2+6x+9-x^2+5x=31\)
\(\Leftrightarrow11x=22\)
\(\Leftrightarrow x=2\)
\(\left(4x+3\right)\left(x-2\right)-\left(2x-1\right)^2=50\)
\(\Leftrightarrow4x^2-8x+3x-6-4x^2+4x-1=50\)
\(\Leftrightarrow-x=56\Leftrightarrow x=-56\)
\(\left(3x+5\right)\left(3x-5\right)-9x\left(x+20\right)=18\)
\(\Leftrightarrow9x^2-25-9x^2-180x=18\)
\(\Leftrightarrow-180x=43\)
\(\Leftrightarrow x=-\dfrac{43}{180}\)
a ) \(\left(x+3\right)^2-x\left(x-5\right)=31\)
\(\Leftrightarrow x^2+6x+9-x^2+5x=31\)
\(\Leftrightarrow11x+9=31\)
\(\Leftrightarrow11x=22\)
\(\Leftrightarrow x=2\)
Vậy \(x=2\)
b ) \(\left(4x+3\right)\left(x-2\right)-\left(2x-1\right)^2=50\)
\(\Leftrightarrow4x^2+3x-8x-6-\left(4x^2-4x+1\right)=50\)
\(\Leftrightarrow4x^2-5x-6-4x^2+4x-1=50\)
\(\Leftrightarrow\left(4x^2-4x^2\right)-\left(5x-4x\right)-\left(6+1\right)=50\)
\(\Leftrightarrow-x-7=50\)
\(\Leftrightarrow-x=57\)
\(\Leftrightarrow x=-57\)
Vậy \(x=-57\)
c ) \(\left(3x+5\right)\left(3x-5\right)-9x\left(x+20\right)=18\)
\(\Leftrightarrow9x^2-25-9x^2-180x=18\)
\(\Leftrightarrow-25-180x=18\)
\(\Leftrightarrow180x=-43\)
\(\Leftrightarrow x=-\dfrac{43}{180}\)
Vậy \(x=-\dfrac{43}{180}\)