d: \(\dfrac{5}{16}-\dfrac{5}{24}=\dfrac{5\cdot3}{48}-\dfrac{5\cdot2}{48}=\dfrac{5}{48}\)

e: \(-\dfrac{24}{17}-\left(-\dfrac{7}{17}-\dfrac{1}{16}\right)\)

\(=-\dfrac{24}{17}+\dfrac{7}{17}+\dfrac{1}{16}=-1+\dfrac{1}{16}\)

\(=-\dfrac{15}{16}\)

f: \(\dfrac{-11}{6}+\dfrac{2}{5}+\dfrac{-1}{6}\)

\(=\left(-\dfrac{11}{6}-\dfrac{1}{6}\right)+\dfrac{2}{5}\)

\(=-2+\dfrac{2}{5}=\dfrac{-8}{5}\)

mình xin nhầm đề là:   A = \(1*2*3+2*4*6+4*8*12+8*16*24 \over2*3*4+4*6*8+8*12*16+16*24*32\)

\(\dfrac{1}{5}+\dfrac{4}{11}+\dfrac{4}{5}+\dfrac{7}{11}=\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=\dfrac{5}{5}+\dfrac{11}{11}=1+1=2\)

\(\dfrac{5}{6}+\dfrac{8}{24}+\dfrac{1}{6}+\dfrac{16}{24}=\dfrac{5}{6}+\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{2}{3}=\left(\dfrac{5}{6}+\dfrac{1}{6}\right)+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)=\dfrac{6}{6}+\dfrac{3}{3}=1+1=2\)

( 1/5+4/5)+ (4/11+7/11)

= 1+1=2

( 5/6+1/6)+ (8/24+16/24)

=1+1=2

a)\(=\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=1+1=2\)

b)\(=\left(\dfrac{5}{6}+\dfrac{1}{6}\right)+\left(\dfrac{8}{24}+\dfrac{16}{24}\right)=1+1=2\)

1) -39 +14+26+39

=   39-39 + 40

=40

2)  -54 +16 +(-6)+54

=54-54  +10

=10

3) 45 +23+(-35)+(-23)

=  45-35 +23 -23

=10+0

=10

4) 45  .17 - 5.9.7

=45.17 -45.7

=45.( 17-7)

=45 .10

=450

5) 24 ( 16-5) -16(24-5)

=24.16 -24.5 -16 .24 +16 .5

= 24.16 -16.24 +5 (16-24)

=0  +5 .(-8)

=-40

Chúc hok tốt!

1. ( - 39 ) + 14 + 26 + 39 

= [ ( - 39 ) + 39 ] + ( 14 + 26 )
= 0 + 40 

= 40

2. ( - 54 ) + 16 + ( - 6 ) + 54

= [ ( - 54 ) + 54 ] + [ 16 + ( - 6 ) ]

= 0 + 10

= 10

3. 45 + 23 + ( - 35 ) + ( - 23 )

= [ 45 + ( - 35 ) ] + [ 23 + ( - 23 ) ] 

= 10 + 0 

= 10

4. 45 . 17 - 5 . 9 . 7

= 45 . 17 - 45 . 7 

= 45 . ( 17 - 7 )
= 45 . 10

= 450

5. 24 . ( 16 - 5 ) - 16 . ( 24 - 5 )

= 24 . 11 - 16. 19

= 264 - 304

= 264 + ( - 304 )

= - ( 304 - 364 ) 

= - 40

Chúc bạn học tốt ! 

1. (-39)+14+26+39

\(=\left[\left(-39\right)+39\right]+\left(14+26\right)\)

\(=0+40\)

\(=40\)

2. (-54)+16+(-6)+54

\(=\left[\left(-54\right)+54+\left[16+\left(-6\right)\right]\right]\)

\(=0+10\)

\(=10\)

3. 45+23+(-35)+(-23)

\(=\left(45+\left(-35\right)\right)+\left(23+\left(-23\right)\right)\)

\(=10+0\)

\(=10\)

4. 45.17-5.9.7

\(=45.17-45.7\)

\(=45.\left(17-7\right)\)

\(=45.10\)

\(=450\)

5. 24.(16-5)-16.(24-5)

\(=24.16-24.5-16.24+16.5\)

\(=24.\left(16-16\right)+5.\left(-24+16\right)\)

\(=24.0+5.\left(-8\right)\)

\(=0+\left(-40\right)\)

\(=-40\)

1 + 1/3 + 1/6+1/12+1/24+1/48+1/96
= 2/3 – 1/3 + 1/3 – 1/6+1/6- 1/12+1/12- 1/24+1/24-
1/48+1/48-1/96
=2/3_1/96

= 63/96
= 21/32

chúc cậu hc tốt ạ

Bài 1: 

1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)

\(=-12-18\)

=-30

2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)

\(=36-2020+2019-136-27\)

\(=1-100-27\)

\(=-126\)

3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)

\(=144-97-244+197\)

\(=-100+100=0\)

4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)

\(=-24\cdot13+24\cdot3\)

\(=24\cdot\left(-13+3\right)\)

\(=24\cdot\left(-10\right)=-240\)

5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)

\(=54+55+56+57+58-64-65-66-67-68\)

\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)

\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)

=-50

6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)

\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)

\(=-24\cdot5+16\cdot5\)

\(=5\cdot\left(-24+16\right)\)

\(=-5\cdot8=-40\)

7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)

\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)

\(=47\cdot50-23\cdot50\)

\(=50\cdot\left(47-23\right)\)

\(=50\cdot24=1200\)

8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)

\(=-31\cdot\left(47+52+1\right)\)

\(=-31\cdot100=-3100\)

Bài 2: 

1) Ta có: \(-17-\left(2x-5\right)=-6\)

\(\Leftrightarrow-17-2x+5+6=0\)

\(\Leftrightarrow-2x-6=0\)

\(\Leftrightarrow-2x=6\)

hay x=-3

Vậy: x=-3

2) Ta có: \(10-2\left(4-3x\right)=-4\)

\(\Leftrightarrow10-8+6x+4=0\)

\(\Leftrightarrow6x+6=0\)

\(\Leftrightarrow6x=-6\)

hay x=-1

Vậy: x=-1

3) Ta có: \(-12+3\left(-x+7\right)=-18\)

\(\Leftrightarrow-12-3x+21+18=0\)

\(\Leftrightarrow-3x+27=0\)

\(\Leftrightarrow-3x=-27\)

hay x=9

Vậy: x=9

4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)

\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)

\(\Leftrightarrow-2x-3=-3\)

\(\Leftrightarrow-2x=0\)

hay x=0

Vậy: x=0

5) Ta có: x(x+3)=0

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-3\right\}\)

6) Ta có: (x-2)(x+4)=0

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)

Vậy: \(x\in\left\{2;-4\right\}\)

7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-1;3\right\}\)

Bài 1: 

1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)

=−12−18=−12−18

=-30

2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27

=36−2020+2019−136−27=36−2020+2019−136−27

=1−100−27=1−100−27

=−126

Tớ chcs cậu học thật giỏi nha !

mấy cái này dễ mà ? em quy đồng lên là dc..

\(12/28 + 7/28 = 21/28 = 3/4\)

\(16/24 - 4/24 = 12/24 = 1/2\)

`a, 7/24 - 1/6 = 7/24 - 4/24 = 3/24=1/8`

`b, 21/16 : 7/5 = 21/16 xx 5/7 = 15/16`

a,7/24-1/6

=7/24-4/24

=3/24=1/8

b,21/16:7/5

=21/16.5/7

=15/16

a, = 1/8