\(\dfrac{-33}{88}=\dfrac{-3}{8};11.8-\dfrac{11.3}{17-6}=88-\dfrac{33}{11}=88-3=85.\)

a) \(\dfrac{11\cdot8-11\cdot3}{17-6}\)

\(=\dfrac{11\cdot\left(8-3\right)}{11}=5\)

b) \(\dfrac{24-12\cdot13}{12+4\cdot9}\)

\(=\dfrac{12\cdot\left(2-13\right)}{12\left(1+3\right)}=\dfrac{-11}{4}\)

giúp em với 

\(=\dfrac{11\cdot\left(-5\right)}{11}=-5\)

RÚT GỌN VỀ PHÂN SỐ TỐI GIẢN

câu a) \(\dfrac{-147}{252}=\dfrac{-7}{12}\)

câu b) \(\dfrac{765}{900}=\dfrac{17}{20}\)

câu c) \(\dfrac{11\cdot3-11\cdot8}{17-6}=\dfrac{-5}{1}\)

câu d) \(\dfrac{3^5\times2^4}{8\times3^6}=\dfrac{2}{3}\)

câu e) \(\dfrac{84\cdot45}{49\cdot54}=\dfrac{10}{7}\)

a) 5

b)  − 11 4

c)  2 3

d)  1 100

e) 5

f) 1

\(\frac{3.7.8.13}{14\cdot15\cdot26}=\frac{3\cdot7\cdot8\cdot13}{2\cdot7\cdot3\cdot5\cdot2\cdot13}=\frac{8}{5\cdot2\cdot2}=\frac{8}{20}=\frac{2}{5}\)

\(\frac{3.7.8.13}{14.15.26}=\frac{3.7.2^3.13}{2.7.3.5.13.2}=\frac{1.7.2.1}{1.1.1.5.1.1}=\frac{14}{5}\)

\(\frac{11.8-11.3}{17-6}=\frac{11.\left(8-3\right)}{11}=\frac{11.5}{11}=\frac{1.5}{1}=\frac{5}{1}=5\)

\(\frac{-17.13+17.2}{11.2-11.9}=\frac{-17.13+\left(-17\right).2}{11.\left(2-9\right)}=\frac{-17.\left(-13+2\right)}{11.\left(-7\right)}=\frac{-17.\left(-11\right)}{11.\left(-7\right)}=\frac{-17.\left(-1\right)}{-1.\left(-7\right)}=\frac{17}{7}\)

\(\frac{7}{9.10^2-2.10^2}=\frac{7}{100\left(9-2\right)}=\frac{7}{100.7}=\frac{7}{700}=\frac{1}{100}\)

mình làm được tới đó thôi, hihi. 

Co ai biết lam con thu 5 ko, giúp minh voi. Dang mai minh nộp bai roi

a)  5

b)  − 11 4

\(\frac{17}{34}=\frac{1}{2}\), \(\frac{60}{70}=\frac{6}{7}\),\(\frac{126}{255}=\frac{42}{85}\),\(\frac{24}{72}=\frac{1}{3}\), \(\frac{105}{30}=\frac{7}{2}\), \(\frac{78}{56}=\frac{39}{28}\)

\(\frac{1}{2},\frac{6}{7},\frac{42}{85},\frac{1}{3},\frac{7}{2},\frac{39}{28}\)

k mk mk kb

17/34 = 1/2 ; 60/70 = 6/7 ; 126/255 = 42/85 ; 24/72 = 1/3 ; 105/30 = 7/2 ; 78/56 = 39/28