D=\(2\dfrac{1}{3}-30\%+0,125-6,5\)
Những câu hỏi liên quan
1, A= \(\dfrac{-3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
2, B= \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{3}\)
3, C= \(\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
4, D= \(6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(1,A=-\dfrac{3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
\(A=-\dfrac{3}{4}.\left(0,125-\dfrac{3}{2}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=-\dfrac{3}{4}.\left(-\dfrac{11}{8}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}:\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}.\dfrac{16}{33}-\dfrac{1}{4}\)
\(A=\dfrac{1}{2}-\dfrac{1}{4}\)
\(A=\dfrac{2}{4}-\dfrac{1}{4}\)
\(A=\dfrac{1}{4}\)
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\(D=6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(D=\dfrac{77}{12}:\dfrac{13}{4}+\dfrac{45}{4}.\dfrac{2}{15}\)
\(D=\dfrac{77}{39}+\dfrac{3}{2}\)
\(D=\dfrac{271}{78}\)
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\(C=\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\left(\dfrac{9}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\dfrac{33}{20}.\dfrac{10}{11}\)
\(C=\dfrac{5}{2}-\dfrac{3}{2}\)
\(C=1\)
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a) dfrac{5}{7}+dfrac{3}{4}.dfrac{-11}{2}b) (dfrac{12}{17}+dfrac{19}{7}) - (dfrac{-5}{17}-dfrac{3}{7})c) (0,125)^{12}.(-8)^{12}-dfrac{45^3}{15^3}d) 5dfrac{2}{7}.(-dfrac{1}{3})-2dfrac{2}{7}.(-dfrac{1}{3})e) dfrac{9^2.9^3}{3^9}
Đọc tiếp
a) \(\dfrac{5}{7}\)+\(\dfrac{3}{4}\).\(\dfrac{-11}{2}\)
b) (\(\dfrac{12}{17}\)+\(\dfrac{19}{7}\)) - (\(\dfrac{-5}{17}\)-\(\dfrac{3}{7}\))
c) (0,125)\(^{12}\).(-8)\(^{12}\)-\(\dfrac{45^3}{15^3}\)
d) \(5\dfrac{2}{7}\).(\(-\dfrac{1}{3}\))-\(2\dfrac{2}{7}\).(\(-\dfrac{1}{3}\))
e) \(\dfrac{9^2.9^3}{3^9}\)
\(a,=\dfrac{5}{7}-\dfrac{33}{8}=-\dfrac{191}{56}\\ b,=\left(\dfrac{12}{17}+\dfrac{5}{17}\right)+\left(\dfrac{19}{7}+\dfrac{3}{7}\right)=1+3=4\\ c,=\left(0,125\cdot8\right)^{12}-\left(\dfrac{45}{15}\right)^3=1-3^3=-26\\ d,=\left(-\dfrac{1}{3}\right)\left(5\dfrac{2}{7}-2\dfrac{2}{7}\right)=-\dfrac{1}{3}\cdot3=-1\\ e,=\dfrac{3^4\cdot3^6}{3^9}=3\)
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tính bằng cách thuận tiện nhất:
6,5*7+6,5:0,2+6,5:0,125
tính bằng cách thuận tiện nhất:
6,5 x 7+ 6,5 : 0,2 + 6,5 : 0,125
= 6,5 x 7+ 6,5/0,2 + 6,5/0,125
= 45,5 + 32,5 + 52
= (45,5 + 32,5) + 52
= 130
Chúc bạn học tốt!
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1. a) dfrac{5}{3} . dfrac{11}{7} - dfrac{5}{7} . dfrac{5}{3}b) (0,125)^{16}. (-8)^{16}c) dfrac{9^2.9^3}{3^9}d) dfrac{9}{24} - dfrac{7}{41} + dfrac{15}{24} + 0,75 - dfrac{34}{41}e) 5dfrac{2}{7} . ( -dfrac{1}{3}) - 2dfrac{2}{7} . (-dfrac{1}{3})2. a) dfrac{3}{4} + dfrac{2}{3}x dfrac{1}{2}b) (2x - 1)^2 25c) | x + 5 | - 6 9
Đọc tiếp
1. a) \(\dfrac{5}{3}\) . \(\dfrac{11}{7}\) - \(\dfrac{5}{7}\) . \(\dfrac{5}{3}\)
b) (0,125)\(^{16}\). (-8)\(^{16}\)
c) \(\dfrac{9^2.9^3}{3^9}\)
d) \(\dfrac{9}{24}\) - \(\dfrac{7}{41}\) + \(\dfrac{15}{24}\) + 0,75 - \(\dfrac{34}{41}\)
e) \(5\dfrac{2}{7}\) . ( \(-\dfrac{1}{3}\)) - \(2\dfrac{2}{7}\) . (\(-\dfrac{1}{3}\))
2. a) \(\dfrac{3}{4}\) + \(\dfrac{2}{3}x\) = \(\dfrac{1}{2}\)
b) (2x - 1)\(^2\) = 25
c) | x + 5 | - 6 = 9
1.
a)10/7
b) 1
c) 3
d) 3/4
e) -1
2.
a)-3/8
b)x= 3 và x=-2
c)x=10 và x=-20
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\(\dfrac{0,125-\dfrac{1}{5}+\dfrac{1}{7}}{0,375-\dfrac{3}{5}+\dfrac{3}{7}}+\dfrac{\dfrac{1}{2}+\dfrac{1}{3}-0,2}{\dfrac{3}{4}+0,5-\dfrac{3}{10}}\)
`=(0,125-1/5+1/7)/(3(0,125-1/5+1/7))+(2(1/4+1/6-0,1))/(3(1/4+1/6-0,1))`
`=1/3+2/3=3/3=1`
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Biết y : 0,125 + 2 x y = 6,5 vậy y là:
y : 0,125 + 2 x y = 6,5
y x 8 + 2 x y = 6,5
y x (8 + 2) = 6,5
y x 10 = 6,5
y = 6,5 : 10
y = 0,65
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2\(\dfrac{1}{6}\)\(+\dfrac{5}{6}:3-0,125\times\left(-2\right)^2\)
\(2\dfrac{1}{6}+\dfrac{5}{6}:3-0,125\times\left(-2\right)^2\)
\(=\dfrac{13}{6}+\dfrac{5}{18}-0,125\times4\)
\(=\dfrac{22}{9}-0,5\)
\(=\dfrac{35}{18}\)
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c) (0,125 + 40% − \(\dfrac{3}{40}\)) : [ 11\(\dfrac{3}{7}\) + 8\(\dfrac{1}{2}\) − ( \(\dfrac{13}{12}\) − 5\(\dfrac{4}{7}\))]
\(\left(0,125+40\%-\dfrac{3}{40}\right):\left[11\dfrac{3}{7}+8\dfrac{1}{2}-\left(\dfrac{13}{12}-5\dfrac{4}{7}\right)\right]\)
\(=\left(\dfrac{1}{8}+\dfrac{2}{5}-\dfrac{3}{40}\right):\left[\dfrac{80}{7}+\dfrac{17}{2}-\left(\dfrac{13}{12}-\dfrac{39}{7}\right)\right]\)
\(=\dfrac{9}{20}:\dfrac{293}{12}\)
\(=\dfrac{27}{1465}\)
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Xem thêm câu trả lời
1) (-6,5).5,7+5,7.(-3,5)
2) \(\left(1-\dfrac{2}{5}\right)^2\) + \(\dfrac{3}{5}\) + \(\dfrac{-7}{10}\)
chỗ \(\dfrac{3}{5}\) là \(\left|\dfrac{-3}{5}\right|\)
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1: \(=5.7\left(-6.5-3.5\right)=-10\cdot5.7=-57\)
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