tính:
\(\frac{\left(\frac{13}{24}.1,4-2,5.\frac{7}{180}\right):2\frac{7}{18}+4\frac{1}{2}.0,1}{70,5-528.7\frac{1}{2}}\)
Giúp mình giải bài toán này nhé Cảm ơn các bạn rất nhiều
\(\frac{\left(\frac{13}{84}×1,4-2,5×\frac{7}{180}\right)\div2\frac{7}{18}+4\frac{1}{2}×0,1}{70,5-528\div7\frac{1}{2}}\)
thực hiện các phép tính sau
a) \(\frac{\left(\frac{13}{84}.1,4-2,5.\frac{7}{180}\right):2\frac{7}{18}+4\frac{1}{2}.0,1}{70,5-528:7\frac{1}{2}}\)
cần gấp !!!!!!!!!!!!!
Giúp mình giải bài toán về với nhé Cảm ơn các bạn rất nhiều( nhớ giải đầy đủ giúp mình nhé)
\(\frac{\left(\frac{13}{84}×1,4-2,5×\frac{7}{180}\right)\div2\frac{7}{18}+4\frac{1}{2}×0,1}{70,5-528\div7\frac{1}{2}}\)
\(\frac{\left(5\frac{4}{45}-4\frac{1}{15}\right)×30}{1\frac{1}{3}}-\frac{4,25\div0,85+1\div0,5}{\left(5,36-4,06\right)\div3-6,5}\)
Rút gọn biểu thức sau:
P=\(\frac{\left(\frac{13}{84}\times1,4-2,5\times\frac{7}{180}\right)\div2\frac{7}{18}+4\frac{1}{2}\times0,1}{70,7-528:\frac{7}{1}}\)
A=\(\frac{\left(\frac{13}{84}.\frac{1}{4}-\frac{2}{5}.\frac{7}{180}\right):2\frac{7}{18}+4\frac{1}{2}.0.1}{70.5-528:7\frac{1}{2}}\)
tính: L =\(\dfrac{\left(\dfrac{13}{84}.1,4-2,5.\dfrac{7}{180}\right):2\dfrac{7}{18}+4\dfrac{1}{2}.0,1}{70,5-528:7\dfrac{1}{2}}\)
\(=\dfrac{\left(\dfrac{13}{84}\cdot\dfrac{7}{5}-\dfrac{5}{2}\cdot\dfrac{7}{180}\right):\dfrac{43}{18}+\dfrac{9}{2}\cdot\dfrac{1}{10}}{70.5-528:7.5}\)
\(=\dfrac{\left(\dfrac{13}{60}-\dfrac{7}{72}\right)\cdot\dfrac{18}{43}+\dfrac{9}{20}}{0.1}\)
\(=10\cdot\left[\dfrac{43}{360}\cdot\dfrac{18}{43}+\dfrac{9}{20}\right]\)
\(=10\cdot\left[\dfrac{1}{20}+\dfrac{9}{20}\right]=10\cdot\dfrac{10}{20}=5\)
tính giá trị biểu thức
\(A=\frac{-378.132+189.64}{15+18+21+......+45+48}\)
\(B=1,4.\frac{15}{14}-\left(\frac{4}{5}+\frac{2}{5}\right):2\frac{1}{5}-\frac{\frac{73}{77}+\frac{73}{165}+\frac{73}{285}}{\frac{25}{24}+\frac{15}{180}+\frac{20}{285}}\)
\(C=\frac{7+\frac{7}{12}-\frac{7}{144}+\frac{7}{60}}{5+\frac{6}{12}-\frac{5}{144}}.\frac{\frac{3}{4}-\frac{3}{16}+\frac{3}{64}-\frac{3}{256}}{1-\frac{1}{4}+\frac{1}{16}-\frac{1}{34}}-\frac{1}{20}\)
Thực hiện phép tính:
a) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
b)\(-12:\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
c)\(\frac{7}{23}.\left[\left(\frac{-8}{6}\right)-\frac{45}{18}\right]\)
d)\(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
e)\(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(0,8-\frac{3}{4}\right)^2\)
a) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
= \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+\frac{1}{2}-\frac{36}{41}\)
= \(\frac{1}{2}-\left\{\frac{11}{24}+\frac{13}{24}\right\}-\left\{\frac{5}{41}+\frac{36}{41}\right\}\)
=\(\frac{1}{2}-\frac{24}{24}-\frac{41}{41}\)
=\(\frac{1}{2}-1-1\)
=\(\frac{-3}{2}\)
b) \(-12:\left\{\frac{3}{4}-\frac{5}{6}\right\}^2\)
= \(-12:\left\{\frac{9}{12}-\frac{10}{12}\right\}^2\)
= \(-12:\left\{\frac{-1}{12}\right\}^2\)
= \(-12:\frac{1}{144}\)
= \(-12.144\)
= -1728
c) \(\frac{7}{23}.\left[\left(\frac{-8}{6}\right)-\frac{45}{18}\right]\)
= \(\frac{7}{23}.\left[\left(\frac{-24}{18}\right)-\frac{45}{18}\right]\)
= \(\frac{7}{23}.\left(\frac{-23}{6}\right)\)
= \(\frac{-7}{6}\)
d) \(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
= \(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}.\frac{7}{5}\)
= \(\left\{23\frac{1}{4}-13\frac{1}{4}\right\}.\frac{7}{5}\)
= \(10.\frac{7}{5}\)
= 14
e) (1+23−14).(0,8−34)2
= (1+23−14).(\(\frac{4}{5}\)−34)2
= \(\left(\frac{12}{12}+\frac{8}{12}-\frac{3}{12}\right).\left(\frac{16}{20}-\frac{15}{20}\right)^2\)
= \(\frac{17}{12}.\left(\frac{1}{20}\right)^2\)
= \(\frac{17}{20}.\frac{1}{400}\)
= \(\frac{17}{8000}\)
Tính giá trị của biểu thức sau: P = \(\left(\frac{13}{84}\times1\frac{2}{5}-2\frac{1}{2}\times\frac{7}{180}\right)\div2\frac{7}{18}+4\frac{1}{2}\)\(\times\frac{1}{10}\)
P = \(\left(\frac{13}{84}\times1\frac{2}{5}-2\frac{1}{2}\times\frac{7}{180}\right):2\frac{7}{18}+4\frac{1}{2}\times\frac{1}{10}\)
P = ( 13/84 x 7/5 - 5/2 x 7/180 ) : 43/18 + 9/2 x 1/10
P = ( 13/60 - 7/72 ) : 43/18 + 9/20
P = 43/360 : 43/18 + 9/20
P = 43/360 x 18/43 + 9/20
P = 1/20 + 9/20
P = 1/2
Bạn bấm phân số và hỗn số như nào vậy!Chỉ cách giúp mình với.