Bài 1:

a) \(x.\dfrac{3}{4}=\dfrac{9}{14}\)

\(\Rightarrow x=\dfrac{9}{14}:\dfrac{3}{4}\)

\(\Rightarrow x=\dfrac{6}{7}\)

b) \(x:\dfrac{5}{9}=\dfrac{3}{10}\)

\(\Rightarrow x=\dfrac{3}{10}.\dfrac{5}{9}\)

\(\Rightarrow x=\dfrac{1}{6}\)

help me

Bài 2:

a) \(\dfrac{3}{10}+\dfrac{2}{5}:\dfrac{4}{15}=\dfrac{3}{10}+\dfrac{3}{2}=\dfrac{9}{5}\)

b) \(\dfrac{4}{7}.3+\dfrac{2}{3}.2=\dfrac{12}{7}+\dfrac{4}{3}=\dfrac{64}{21}\)

đấy nhá

b) Ta có: \(\left|x\right|-\dfrac{3}{4}=\dfrac{5}{3}\)

\(\Leftrightarrow\left|x\right|=\dfrac{5}{3}+\dfrac{3}{4}=\dfrac{20}{12}+\dfrac{9}{12}=\dfrac{29}{12}\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{29}{12}\\x=-\dfrac{29}{12}\end{matrix}\right.\)

c) Ta có: \(\left|2x-\dfrac{1}{3}\right|+\dfrac{5}{6}=1\)

\(\Leftrightarrow\left|2x-\dfrac{1}{3}\right|=\dfrac{1}{6}\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-\dfrac{1}{3}=\dfrac{1}{6}\\2x-\dfrac{1}{3}=\dfrac{-1}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{1}{6}+\dfrac{1}{3}=\dfrac{1}{2}\\2x=\dfrac{1}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=\dfrac{1}{12}\end{matrix}\right.\)

a, \(x:3\dfrac{5}{6}=2\dfrac{8}{15}\) 

   \(x:\dfrac{23}{6}\)   = \(\dfrac{38}{15}\)

   \(x=\dfrac{38}{15}\times\dfrac{23}{6}\)

   \(x=\dfrac{437}{45}\)

b, \(\dfrac{12}{15}:x+\dfrac{4}{3}=3\dfrac{2}{3}\) 

 \(\dfrac{12}{15}:x+\dfrac{4}{3}=\dfrac{11}{3}\) 

\(\dfrac{12}{15}:x=\dfrac{11}{3}-\dfrac{4}{3}\) 

\(\dfrac{12}{15}:x=\dfrac{7}{3}\) 

        x= \(\dfrac{12}{15}:\dfrac{7}{3}=\dfrac{12}{35}\)

\(c)x:\dfrac{5}{4}=\dfrac{9}{5}+\dfrac{1}{2}\) 

  \(x:\dfrac{5}{4}=\dfrac{23}{10}\) 

  \(x=\dfrac{23}{10}\times\dfrac{5}{4}\) 

  \(x=\dfrac{23}{8}\)

-15 ( x - 2 ) + 7 ( 3 - x ) = 7

-15x + 30 + 21 - 7x = 7

-15x - 7x = 7 - 21 - 30

-22x = -44

   x   = ( -44 ) : ( -22)

  x    = 2

Vậy x = 2

-12 ( x - 5 ) + 7 ( 3 - x ) = 5

-12x + 60 + 21 - 7x = 5

-12x - 7x = 5 - 21 - 60

-19x = -76

x      = ( -76 ) : (-19)

x      = 4

Vậy x = 4.

# HOK TỐT #

thanks

1) \(\left(x-3\right)^2-4=0\)

\(\Leftrightarrow\left(x-3-2\right)\left(x-3+2\right)=0\)

\(\Leftrightarrow\left(x-5\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=1\end{matrix}\right.\)

2) \(x^2-2x=24\)

\(\Leftrightarrow x^2-2x-24=0\)

\(\Leftrightarrow x^2+4x-6x-24=0\)

\(\Leftrightarrow x\left(x+4\right)-6\left(x+4\right)=0\)

\(\Leftrightarrow\left(x+4\right)\left(x-6\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)

Câu 3 số xấu rồi e

alo =0 nhé anh pop pop