Bạn chưa đăng nhập. Vui lòng đăng nhập để hỏi bài

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Vũ Phong
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Đoàn Trần Quỳnh Hương
17 tháng 1 2023 lúc 16:31

A = \(\dfrac{2008}{2009+2010+2011}+\dfrac{2009}{2009+2010+2011}+\dfrac{2010}{2009+2010+2011}\)

Ta có: 

\(\dfrac{2008}{2009}>\dfrac{2008}{2009+2010+2011}\)

\(\dfrac{2009}{2010}>\dfrac{2009}{2009+2010+2011}\)

\(\dfrac{2010}{2011}>\dfrac{2010}{2009+2010+2011}\)

Từ 3 điều trên suy ra : A < B

Trâm Vương
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Nguyễn Thanh Hằng
27 tháng 1 2021 lúc 12:36

Ta có :

\(B=\dfrac{2009^{2010}-2}{2009^{2011}-2}< 1\)

\(\Leftrightarrow B< \dfrac{2009^{2010}-2+2011}{2009^{2011}-2+2011}=\dfrac{2009^{2010}+2009}{2009^{2011}+2009}=\dfrac{2009\left(2009^{2009}+1\right)}{2009\left(2009^{2010}+1\right)}=\dfrac{2009^{2009}+1}{2009^{2010}+1}=A\)

\(\Leftrightarrow A>B\)

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Phùng Minh Quân
26 tháng 2 2018 lúc 21:07

Ta có : 

\(B=\frac{2008+2009+2010}{2009+2010+2011}=\frac{2008}{2009+2010+2011}+\frac{2009}{2009+2010+2011}+\frac{2010}{2009+2010+2011}\)

Vì : 

\(\frac{2008}{2009}>\frac{2008}{2009+2010+2011}\)

\(\frac{2009}{2010}>\frac{2009}{2009+2010+2011}\)

\(\frac{2010}{2011}>\frac{2010}{2009+2010+2011}\)

Nên \(\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}>\frac{2008}{2009+2010+2011}+\frac{2009}{2009+2010+2011}+\frac{2010}{2009+2010+2011}\)

\(\Rightarrow\)\(A>B\)

Vậy \(A>B\)

nguyen van huy
26 tháng 2 2018 lúc 21:12

Ta có: \(B=\frac{2008+2009+2010}{2009+2010+2011}\)

                  \(=\frac{2008}{2009+2010+2011}+\frac{2009}{2009+2010+2011}+\frac{2010}{2009+2010+2011}\)

Vì \(\frac{2008}{2009}>\frac{2008}{2009+2010+2011}\)

    \(\frac{2009}{2010}>\frac{2009}{2009+2010+2011}\)

   \(\frac{2010}{2011}>\frac{2010}{2009+2010+2011}\)

nên \(\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}>\frac{2008+2009+2010}{2009+2010+2011}\)

hay A > B

Vậy A > B 

Sunari maku
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Mới vô
22 tháng 4 2017 lúc 7:28

B = \(\dfrac{2009^{2009}+1}{2009^{2010}+1}\)<\(\dfrac{2009^{2009}+1+2008}{2009^{2010}+1+2008}\)=\(\dfrac{2009^{2009}+2009}{2009^{2010}+2009}\)=\(\dfrac{2009.\left(2009^{2008}+1\right)}{2009.\left(2009^{2009}+1\right)}\)=\(\dfrac{2009^{2008}+1}{2009^{2019}+1}\)= A

Vậy A > B

Nguyễn Thanh Hằng
22 tháng 4 2017 lúc 6:17

Ta có :

\(2009A=\dfrac{2009^{2009}+2009}{2009^{2009}+1}=\dfrac{2009^{2009}+1+2008}{2009^{2009}+1}=\dfrac{2009^{2009}+1}{2009^{2009}+1}+\dfrac{2008}{2009^{2009}+1}=1+\dfrac{2008}{2009^{2009}+1}\)

\(2009B=\dfrac{2009^{2010}+2009}{2009^{2010}+1}=\dfrac{2009^{2010}+1+2008}{2010^{2010}+1}=\dfrac{2009^{2010}+1}{2009^{2010}+1}+\dfrac{2008}{2009^{2010}+1}=1+\dfrac{2008}{2009^{2010}}\)

\(\)\(1+\dfrac{2008}{2009^{2009}+1}>1+\dfrac{2008}{2009^{2010}+1}\Rightarrow A>B\)

~ Học tốt ~

Vampire Princess
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Thanh Tùng DZ
26 tháng 5 2018 lúc 21:16

1.

\(1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{99}}+\frac{1}{2^{100}}+\frac{1}{2^{100}}\)

\(=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{99}}+\left(\frac{1}{2^{100}}+\frac{1}{2^{100}}\right)\)

\(=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{99}}+\frac{1}{2^{99}}\)

cứ làm như vậy ta được :

\(=1+1=2\)

Thanh Tùng DZ
26 tháng 5 2018 lúc 21:19

2. Ta có :

\(\frac{2008+2009}{2009+2010}=\frac{2008}{2009+2010}+\frac{2009}{2009+2010}\)

vì \(\frac{2008}{2009}>\frac{2008}{2009+2010}\)\(\frac{2009}{2010}>\frac{2009}{2009+2010}\)

\(\Rightarrow\frac{2008}{2009}+\frac{2009}{2010}>\frac{2008+2009}{2009+2010}\)

lưu tuấn anh
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Shizadon
26 tháng 2 2018 lúc 21:08

\(B=\dfrac{2008+2009+2010}{2009+2010+2011}=\dfrac{2008}{2009+2010+2011}+\dfrac{2009}{2009+2010+2011}+\dfrac{2010}{2009+2010+2011}\)Ta có : \(\dfrac{2008}{2009}>\dfrac{2008}{2009+2010+2011}\)

\(\dfrac{2009}{2010}>\dfrac{2009}{2009+2010+2011}\)

\(\dfrac{2010}{2011}>\dfrac{2010}{2009+2010+2011}\)\(=>\dfrac{2008}{2009}+\dfrac{2009}{2010}+\dfrac{2010}{2011}>\dfrac{2008+2009+2010}{2009+2010+2011}\)

Hay A > B

Lê Nguyễn Trí Nguyên
23 tháng 12 2018 lúc 20:03

bằng nhau bạn nhé

Lê Nguyễn Trí Nguyên
23 tháng 12 2018 lúc 20:03

lộn

Trần Mạnh Nguyên
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Trần Mạnh Nguyên
18 tháng 1 2018 lúc 21:33

Mn ngủ hết rồi hay sao mà ko giúp mk.

Nijino Yume
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zZz Cool Kid_new zZz
5 tháng 5 2019 lúc 8:35

\(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+.....+\frac{1}{80}\)

\(=\left(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+\frac{1}{44}+.....+\frac{1}{60}\right)+\left(\frac{1}{61}+\frac{1}{62}+......+\frac{1}{80}\right)\)

\(>\left(\frac{1}{60}+\frac{1}{60}+\frac{1}{60}+.....+\frac{1}{60}\right)+\left(\frac{1}{80}+\frac{1}{80}+\frac{1}{80}+.....+\frac{1}{80}\right)\)

\(=\frac{1}{3}+\frac{1}{4}\)

\(=\frac{7}{12}\)

zZz Cool Kid_new zZz
5 tháng 5 2019 lúc 8:37

\(B=\frac{2008+2009+2010}{2009+2010+2011}=\frac{2008}{2009+2010+2011}+\frac{2009}{2009+2010+2011}+\frac{2010}{2009+2010+2011}\)

\(< \frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}=A\)

Phạm Thị Minh Phượng
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Phương Thảo Nguyễn
21 tháng 9 2019 lúc 19:58
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