Giải:
Ta có:
A=20092008+1/20092009+1
2009A=20092009+2009/20092009+1
2009A=20092009+1+2008/20092009+1
2009A=20092009+1/20092009+1 + 2008/20092009+1
2009A=1+2008/20092009+1
Tương tự:
B=20092009+1/20092010+1
2009B=1+2008/20092010+1
Vì 2008/20092009+1 > 2008/20092010+1 nên 2009A>2009B
⇒A>B
Bài 2 : So sánh
\(A=\dfrac{2008}{2009}+\dfrac{2009}{2010}+\dfrac{2010}{2011}vàB=\dfrac{2008+2009+2010}{2009+2010+2011}\)
1. \(1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{99}}+\frac{1}{2^{100}}+\frac{1}{2^{100}}\)
2. So sánh: \(\dfrac{2008}{2009}+\dfrac{2009}{2010}\) và \(\dfrac{2008+2009}{2009+2010}\)
So sánh:
A=20092008+1/20092009+1 với B=20092009+1/20092010+1.
Mk cần gấp. Hãy giúp mk nhé! Hihi...
a) Chứng tỏ rằng: 1/41+1/42+1/43+...+1/80 > 7/12
b) So sánh: A=2008/2009+2009/2010+2010/2011 VÀ B=2008+2009+2010/2009+2010+2011
thực hiện tính và so sánh A=\(\frac{2008^{2009}+1}{2009^{2009}+1}\)và B=\(\frac{2009^{2009}+1}{2009^{2010}+1}\)
2. So sánh A và B:
A= 2006/2007 - 2007/2008 + 2008/2009 - 2009/2010
B=-1/2006*2007 - 1/2008*2009
20092008 +1/20092009+1 So Sánh với 20092009+1/20092010+1
so sánh A= \(\frac{2009^{2008}+1}{2009^{2009}+1}\)và B= \(\frac{2009^{2009}+1}{2009^{2010}+1}\)
So sánh : A = \(\frac{2009^{2008}+1}{2009^{2009}+1}\)với B = \(\frac{2009^{2009}+1}{2009^{2010}+1}\)
