y x ( 26 + 327 ) = 327 x 7 + 26 x 7

y x 353 = ( 327 + 26 ) x 7

y x 353 = 353 x 7

y x 353 = 2472

y = 2471 : 353

y = 7

ko biết

\(=245\left(327-26-1\right)=245\cdot300=73500\)

\(36\cdot532+64\cdot532=532\cdot100=53200\)

36 x 532 + 64 x 532

=(36+64)x532

= 100x532

=53 200

245 x 327 - 245 x 26 - 245

=245x327-245x26-245x1

=245x(327-26-1)

=245x300

=73 500

\(x=3y\); \(y-x=26\)

từ \(y-x=26\Rightarrow x=y-26\)

thay \(x=y-26\), ta được:

\(y-26=3y\)

\(\Rightarrow2y=-26\)

\(\Rightarrow y=-13\)mà  \(x=3y\Rightarrow x=3\cdot\left(-13\right)=-39\)

vậy \(x=-39;y=-13\)

Ta có : \(\frac{x}{5}=\frac{y}{7}\Rightarrow5y=7x\Rightarrow x=\frac{5y}{7}\)

Thay \(x=\frac{5y}{7}\)vào biểu thức \(2x+y=26\);ta được: 

\(\frac{2.5y}{7}+y=26\Rightarrow10y+7y=26.7\Rightarrow17y=182\Rightarrow y=\frac{182}{17}\)

Do đó : \(x=\frac{\frac{5.182}{17}}{7}=\frac{130}{17}\)

nhìn thấy duy nhất một chữ rối!

(x+1/5)^2 =26/25-17/25

<=> (x +1/5)^2 =(3/5)^2

<=> x+1/5=3/5

=> x= 2/5

a) 
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\left(\frac{3}{5}\right)^2\)
\(x+\frac{1}{5}=\frac{3}{5}\)

\(x=\frac{3}{5}-\frac{1}{5}\)

\(x=\frac{2}{5}\)
b) 
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

\(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}=0\)
\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+4+\frac{x+329}{5}=0\)

\(\left(x+329\right). \left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+4+\frac{1}{5}\right)=0\)
\(\Rightarrow\left(x+329\right)=0\)
\(\Rightarrow x=-329\)

1.

(x + 1/5)² = 26/25 - 17/25 

(x + 1/5)² = 9/25 

Rút căn hai vế : 

|(x + 1/5)| = 3/5 

x = -4/5 
hoặc
x = 2/5

2.

(x + 2) / 327 + (x + 3) / 326 + (x + 4) / 325 + (x + 5) / 324 + (x + 349) / 5 = 0 
<=> (x + 2) / 327 +1+ (x + 3) / 326 +1+ (x + 4) / 325 +1+ (x + 5) / 324 +1+ (x + 349) / 5 -4 = 0 
<=> (x+ 329)/327 + (x+ 329)/326 + (x+ 329)/325 + (x+ 329)//324 + (x+ 329)/5 =0 
<=> (x+ 329).(1/327 + 1/ 326 + 1/325 + 1/324 +1/5) =0 
Do (1/327 + 1/ 326 + 1/325 + 1/324 +1/5) >0 nên x+ 329 =0 => x= -329 

Câu 1 chưa chắc đã đúng ( quên hết kiến thức lớp 6 rùi ) hihi

aaaaaaaa . chết rồi . cho mình sủa câu thứ nhất :

(x+1/5)² + 17/25=26/25

( x + 1/5 ) ² = 26/25 - 17/25

( x + 1/5 ) ² = 3/5²

x + 1/5 = 3/5

x = 2/5.

Sửa đề: Tìm x \(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+349}{5}=0\)

Bài giải

\(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+349}{5}=0\)

\(\Leftrightarrow\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+329+20}{5}=0\)

\(\Leftrightarrow\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+329}{5}+\dfrac{20}{5}=0\)

\(\Leftrightarrow\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+329}{5}+4=0\)

\(\Leftrightarrow\dfrac{x+2}{327}+1+\dfrac{x+3}{326}+1+\dfrac{x+4}{325}+1+\dfrac{x+5}{324}+1+\dfrac{x+329}{5}=0\)

\(\Leftrightarrow\dfrac{x+329}{327}+\dfrac{x+329}{326}+\dfrac{x+329}{325}+\dfrac{x+329}{324}+\dfrac{x+329}{5}=0\)

\(\Leftrightarrow\left(x+329\right)\left(\dfrac{1}{327}+\dfrac{1}{326}+\dfrac{1}{325}+\dfrac{1}{324}+\dfrac{1}{5}\right)=0\)

\(\Rightarrow x+329=0\). Do \(\dfrac{1}{327}+\dfrac{1}{326}+\dfrac{1}{325}+\dfrac{1}{324}+\dfrac{1}{5}\ne0\)

\(\Rightarrow x=-329\)