THEY WENT TO THE SEASIDE ON HOLIDAY.

HOW DID THEY COME HERE?

DID THEY COME HERE ON FOOT?

C

40:

a: =2,5*4*20,21

=20,21*10

=202,1

b: =0,25*0,4*1,25*8

=10*0,1

=1

9:

a: =>0,4y=6

=>y=6:0,4=15

b: 105:y=7,46-3,26

=>105:y=4,2

=>y=105/4,2=25

c: y+1,59=12*2,5

=>y+1,59=30

=>y=28,41

d: 3,75:y=3:4

=>3,75:y=0,75

=>y=3,75:0,75=5

a: Xét ΔAHE có 

AM là đường cao

AM là đường trung tuyến

DO đó: ΔAHE cân tại A

hay AH=AE

b: Xét ΔAKI và ΔAHI có

AK=AH

\(\widehat{KAI}=\widehat{HAI}\)

AI chung

Do đó: ΔAKI=ΔAHI

Suy ra: \(\widehat{AKI}=\widehat{AHI}=90^0\)

hay IK//AB

c: Ta có: IK=IH

mà IK<IC

nên IH<IC

1. are visiting
2. don't go
3. are not going to work
4. Does Mary have
5. meet

are visting

don't go

won't work

Does Mary have

meet

1. are visiting 

2. don't go

3. aren't going to work

4. Does Mary have

5. meet

\(\left(1\right)FeCl_2+2NaOH\to Fe\left(OH\right)_2\downarrow +2NaCl\\ \left(2\right)Fe\left(OH\right)_2\xrightarrow{t^0}FeO+H_2O\\ \left(3\right)FeO+C\to Fe+CO\uparrow \\ \left(4\right)2Fe+3Cl_2\xrightarrow[]{t^o}2FeCl_3\\ \left(5\right)FeCl_3+3NaOH\to Fe\left(OH\right)_3\downarrow +3NaCl\\ \left(6\right)2Fe\left(OH\right)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ \left(7\right)Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ \left(8\right)Fe+2HCl\to FeCl_2+H_2\)