`@` `\text {Ans}`

`\downarrow`

`3,8 * 2x = 1/4*8/3`

`=> 3,8*2x = 2/3`

`=> 2x = 2/3 \div 3,8`

`=> 2x = 10/57`

`=> x = 10/57 \div 2`

`=> x = 5/57`

Vậy, `x = 5/57.`

Mình làm lại theo yc nhé

`3,8 \div 2x = 1/4 \div 8/3`

`=> 3,8*8/3 = 2x*1/4`

`=> 152/15 = 2x*1/4`

`=> 2x = 152/15 \div 1/4`

`=> 2x = 608/15`

`=> x = 608/15 \div 2`

`=> x = 304/15`

Vậy, `x = 304/15.`

mik đg cần gấp ah =)

<=>\(\left|\dfrac{1}{2}-2x\right|=\dfrac{5}{3}< =>\left[{}\begin{matrix}\dfrac{1}{2}-2x=\dfrac{5}{3}\\\dfrac{1}{2}-2x=\dfrac{-5}{3}\end{matrix}\right.< =>\left[{}\begin{matrix}2x=\dfrac{-7}{6}\\2x=\dfrac{13}{6}\end{matrix}\right.< =>\left[{}\begin{matrix}x=\dfrac{-7}{12}\\x=\dfrac{13}{12}\end{matrix}\right.\)

\(\left|\dfrac{1}{2}+2x\right|+\dfrac{2}{3}=\dfrac{7}{3}\)

\(\left|\dfrac{1}{2}+2x\right|=\dfrac{7}{3}-\dfrac{2}{3}=\dfrac{5}{3}\)

⇔\(\left[{}\begin{matrix}\dfrac{1}{2}+2x=\dfrac{5}{3}\\\dfrac{1}{2}+2x=-\dfrac{5}{3}\end{matrix}\right.\)

⇔ \(\left[{}\begin{matrix}x=\dfrac{7}{12}\\x=-\dfrac{13}{12}\end{matrix}\right.\)

Vậy ...

⎡⎢ ⎢⎣x=712x=−1312[x=712x=−1312

Vậy ...

bạn đã kiểm tra kĩ chưa vậy?mình đọc đề câu B mà loạn não luôn á;-;

mik kiểm tra rùi

\(\left(2x-1\right)\div\frac{10}{7}=\frac{28}{15}\div\frac{4}{3}\)

\(\Leftrightarrow\frac{2x-1}{\frac{10}{7}}=\frac{\frac{28}{15}}{\frac{4}{3}}\)

\(\Leftrightarrow\frac{4}{3}\left(2x-1\right)=\frac{10}{7}\times\frac{28}{15}\)

\(\Leftrightarrow\frac{4}{3}\left(2x-1\right)=\frac{8}{3}\)

\(\Leftrightarrow2x-1=2\)

\(\Leftrightarrow2x=3\)

\(\Leftrightarrow x=\frac{3}{2}\)

hok tốt nhé!

-48

gút gơn vs gút boi nữa:)

(-15).4-240:6+36:(-2).3

=-60-40+18.3

=-100+ 54

=-46

Toyy ko pk bét gơn đou ak :v

a, 3x - 2x < 6 <=> x < 6 

b, đk : x khác -1 ; 3 

=> x^2 - 3x = x^2 - x - 2 

<=> -2x = -2 <=> x = 1 (tm) 

mình chỉ tính vế bên thôi nhé bn tích x

\(\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{25.28}\)

\(\frac{1}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-.....+\frac{1}{25}-\frac{1}{28}\right)\)

=\(\frac{1}{3}\left(\frac{1}{4}-\frac{1}{28}\right)\)

=\(???\)

ban oi sai roi

ban oi minh cung lam giong zay nhung sai

\(a,\left|2x+\dfrac{1}{2}\right|=0\\ \Leftrightarrow2x+\dfrac{1}{2}=0\\ \Leftrightarrow2x=-\dfrac{1}{2}\\ \Leftrightarrow x=-\dfrac{1}{4}\\ b,\left|3x+\dfrac{3}{4}\right|=3\\ \Leftrightarrow\left[{}\begin{matrix}3x+\dfrac{3}{4}=3\\3x+\dfrac{3}{4}=-3\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}3x=\dfrac{9}{4}\\3x=-\dfrac{15}{4}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=-\dfrac{5}{4}\end{matrix}\right.\)