`@` `\text {Ans}`
`\downarrow`
`3,8 * 2x = 1/4*8/3`
`=> 3,8*2x = 2/3`
`=> 2x = 2/3 \div 3,8`
`=> 2x = 10/57`
`=> x = 10/57 \div 2`
`=> x = 5/57`
Vậy, `x = 5/57.`
Mình làm lại theo yc nhé
`3,8 \div 2x = 1/4 \div 8/3`
`=> 3,8*8/3 = 2x*1/4`
`=> 152/15 = 2x*1/4`
`=> 2x = 152/15 \div 1/4`
`=> 2x = 608/15`
`=> x = 608/15 \div 2`
`=> x = 304/15`
Vậy, `x = 304/15.`