\(\left(\frac{3x}{7}+1\right)\div\left(-4\right)=\frac{-1}{28}\)

                       \(\frac{3x}{7}+1=\frac{-1}{28}\times\left(-4\right)\)

                        \(\frac{3x}{7}+1=\frac{1}{7}\)

                                     \(\frac{3x}{7}=\frac{1}{7}-1\)

                                    \(\frac{3x}{7}=\frac{-6}{7}\)

                                     \(3x=\frac{-6}{7}\times7\) 

                                       \(3x=-6\)

                                          \(x=-2\)

Vậy x = -2

tớ ko bít đúng hay sai đâu nha

\(\Leftrightarrow\)\(-\frac{1}{28}\cdot\left(-4\right)\)=\(\frac{3x}{7}+1\)

\(\Leftrightarrow\frac{1}{7}=\frac{3x}{7}+1\)

\(\Leftrightarrow\frac{1}{7}-1=3x:7\)

\(\Leftrightarrow3x:7=-\frac{6}{7}\)

\(\Leftrightarrow3x=\frac{-6}{7}.7\)

\(\Leftrightarrow x=-6:3\)

\(\Leftrightarrow x=-2\)

âm 2 nha bạn

a) ta có :x²+2x+2=(x+1)²+1>0,với mọi x

x²+2x+3=(x+1)²+2>0,với mọi x

ĐKXĐ:x\(\in\)R.Đặt x²+2x+2=a (a>0),ta có:\(\dfrac{a-1}{a}+\dfrac{a}{a+1}=\dfrac{7}{6}\)

<=>\(\dfrac{6\left(a-1\right)\left(a+1\right)}{6a\left(a+1\right)}+\dfrac{6a^2}{6a\left(a+1\right)}=\dfrac{7a\left(a+1\right)}{6a\left(a+1\right)}\)

=>6(a²-1)+6a²=7a²+7a<=>6a²-6+6a²=7a²+7a<=>12a²-7a²-7a-6=0

<=>5a²-7a-6=0<=>(a-2)(5a+3)=0<=>a-2=0(vì a>0,nên 5a+3>0)

<=>a=2=>x²+2x+2=2<=>x(x+2)=0<=>\(|^{x=0}_{x+2=0< =>x=-2}\)

Vậy tặp nghiệm của PT là S\(=\left\{0;-2\right\}\)

\(\frac{11}{4}:\frac{3}{2}:\left|4x-\frac{1}{3}\right|=\frac{7}{2}\)

\(\Leftrightarrow\frac{3}{2}:\left|4x-\frac{1}{3}\right|=\frac{11}{4}:\frac{7}{2}\)

\(\Leftrightarrow\frac{3}{2}:\left|4x-\frac{1}{3}\right|=\frac{11}{14}\)

\(\Leftrightarrow\left|4x-\frac{1}{3}\right|=\frac{3}{2}:\frac{11}{14}\)

\(\Leftrightarrow\left|4x-\frac{1}{3}\right|=\frac{21}{11}\)

\(\Leftrightarrow\orbr{\begin{cases}4x-\frac{1}{3}=\frac{21}{11}\\4x-\frac{1}{3}=-\frac{21}{11}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{37}{66}\\x=-\frac{13}{33}\end{cases}}\)

Bài dưới tương tự

Bấm máy tính:

E = \(\frac{4}{3}+\frac{1}{4}+\frac{3}{5}:\frac{4}{5}\)

E = \(\frac{4}{3}+\frac{1}{4}+\frac{3}{4}\)

E = \(\frac{7}{3}\)

Vậy E = \(\frac{7}{3}\)

ta có:4/5:(4/5*5/4)/16/25-1/25+(27/25-2/25):4/7/(59/9-13/4)*36/17+6/5*1/2

       =4/5:3/5+7/4:7+3/5

        =4/3+1/4+3/5

         =3/2+3/5=21/10

\(E=\frac{0,8:\left(\frac{4}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{2}{17}}+\left(1,2.0,5\right):\frac{4}{5}\)

\(E=\frac{\frac{4}{5}:\frac{4}{5}:1,25}{\frac{16}{25}-\frac{1}{25}}+\frac{\left(\frac{27}{25}-\frac{2}{25}\right).\frac{7}{4}}{\left(\frac{59}{9}-\frac{13}{4}\right).\frac{36}{17}}+\frac{6}{5}.\frac{1}{2}.\frac{5}{4}\)

\(E=\frac{1:\frac{5}{4}}{\frac{3}{5}}+\frac{1.\frac{7}{4}}{\frac{119}{36}.\frac{36}{17}}+\frac{3}{4}\)

\(E=\frac{4}{5}.\frac{5}{3}+\frac{\frac{7}{4}}{7}+\frac{3}{4}\)

\(E=\frac{4}{3}+\frac{7}{4}.\frac{1}{7}+\frac{3}{4}\)

\(E=\frac{4}{3}+\frac{1}{4}+\frac{3}{4}\)

\(E=\frac{4}{3}+1=\frac{7}{3}\)