`@` `\text {Ans}`

`\downarrow`

`(7x - 11)^2 = 2^5 * 5^2 + 100?`

`=> (7x - 11)^2 = 32*25 + 100`

`=> (7x - 11)^2 = 800 + 100`

`=> (7x - 11)^2 = 900`

`=> (7x - 11)^2 = (+-30)^2`

`=>`\(\left[{}\begin{matrix}7x-11=30\\7x-11=-30\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}7x=41\\7x=-19\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=\dfrac{41}{7}\\x=-\dfrac{19}{7}\end{matrix}\right.\)

Vậy, `x \in`\(\left\{\dfrac{41}{7};-\dfrac{19}{7}\right\}\)

sorry 

(7x - 11 ) ³= 3²  + 100 . 100 + 1

(7x - 11 ) ³  = 1000

(7x - 11 ) ³ = 10³

=> 7x + 11 = 10 

=> 7x  = 10 + 11 = 21 

=> x  = 21 : 1 = 3

(7x - 11 ) ³ = 3² + 100 . 100 + 1

(7x - 11 ) ³ =

(7x - 11 ) ³ = 1000

(7x - 11 ) ³ = 10³

=> 7x + 11 = 10 

=> 7x  = 10 + 11 = 21 

=> 7x  = 21 : 1 = 3

ai k mình , mình k lại cho

Đầu bài sai.

Sửa : 

\(\left(7x-11\right)^3=10000\)

\(\Rightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

Tìm x ; e và N luôn !

 (7x-11)³=32*25+100

\(\Leftrightarrow\)(7x-11)³ = 900

\(\Leftrightarrow\)7x-11 = \(\sqrt[3]{900}\)

\(\Leftrightarrow\)x = \(\frac{\sqrt[3]{900}+11}{7}\)

Các bn giúp mình nhanh đk ko. Cảm ơn các bạn nhiều nha.

bạn cứ chia ra trường hợp là đc

a: =>-140x+1050-132+84x=100

=>-56x=100+132-1050=-818

=>x=409/28

b: \(\Leftrightarrow82-287x-15x+60=20\)

=>-302x+142=20

=>-302x=-122

=>x=61/151

c: =>165x-66+12x-32=15

=>177x=113

=>x=113/177

d: =>140-16x-77+22x=19

=>6x+63=19

=>6x=-44

=>x=-22/3

a,

7x – 8 = 713

7x = 713 + 8

7x = 721

x = 721 : 7

x = 103.

b,

2448:[119-(x-6)]=24

119-(x-6)= 2448 : 24

119-(x-6)= 102

x-6= 119-102

x-6= 17

x=17+6

x=23

c,

2016 - 100.( x +11 ) = 2^7 : 2^3
2016 - 100.(x+11) = 2^4
2016 - 100.(x+11)=16
100.(x+11) = 2016-16
100.(x+11)=2000
x+11=2000:100
x+11=20
x = 20-11
x = 9

1) \(2^x-15=17\)

\(\Leftrightarrow2^x=32=2^5\)

\(\Rightarrow x=5\)

2) \(\left(7x-11\right)^3=25\cdot5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=825\)

\(\Leftrightarrow7x-11=\sqrt[3]{825}\)

\(\Leftrightarrow7x=11+\sqrt[3]{825}\)

\(\Rightarrow x=\frac{11+\sqrt[3]{825}}{7}\)

3) \(\left(x+1\right)^{100}-3\left(x+1\right)^{99}=0\)

\(\Leftrightarrow\left(x+1\right)^{99}\left(x-2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)^{99}=0\\x-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=2\end{cases}}\)

4) \(4x+5\left(x+3\right)=105\)

\(\Leftrightarrow9x+15=105\)

\(\Leftrightarrow9x=90\)

\(\Rightarrow x=10\)

5) \(5\cdot\left(x-2\right)+10\left(x+3\right)=170\)

\(\Leftrightarrow5\left[x-2+2\left(x+3\right)\right]=170\)

\(\Leftrightarrow3x+4=34\)

\(\Leftrightarrow3x=30\)

\(\Rightarrow x=10\)

cảm ơn bạn nhá NGUYỄN MINH ĐĂNG