=>7x-11=\(\sqrt[3]{100}\)
=>\(7x=\sqrt[3]{100}+11\)
=>\(x=\dfrac{\sqrt[3]{100}+11}{7}\)
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=>7x-11=\(\sqrt[3]{100}\)
=>\(7x=\sqrt[3]{100}+11\)
=>\(x=\dfrac{\sqrt[3]{100}+11}{7}\)
(7x-11)^3=2^5.5^2+100
Tìm x e N
( 7x - 11 ) \(^3\)= 3\(^2\)+ 100 . 100 + 1
Tìm x biết (7x-11)^3=3.(7x-11)^2
Tìm x e N
( 7x - 11 ) \(^3\)= 2\(^5\). 5\(^2\)+ 100
tìm x,biết
2 mũ x-15=17
(7x-11) mũ 3=25 nhân 5 mũ 2+200
(x +1) mũ 100-3 nhân (x+1) mũ 99=0
4x+5 nhân (x+3)=105
5 nhân(x-2)+10 (x+3)=170
\(\text{Bài 2 : Tìm }x\in N\text{ , biết : }\)
a, \(\left(7x-11\right)^3=2^5\cdot5^2+100\)
b, \(3^{x+3}-234=3^x\)
Tim x biet
A, 2x +23x = 625
B, (2^2+4^2) x + 2^4 ×5 ×x =100
C, (3x + 1)^2 = 6^2 + 8^2
D, (7x -11)^3 = 7^2 × 5^2 - 15^2
E, (2x- 1)^4 = 3× (3^2+4^3+2)
tìm x biết (7x- 11).(7x- 11).(7x- 11)=2.2.2.2.2.5.5+20
help mình nha
(7x - 11)3= 10000