56+98*0+89*7*98*52*58+245
50. √(98-16√3)
51. √(2-√3)
52. √(4+√15)
53. √(5-√21)
54. √(6-√35)
55. √(2+√3)
56. √(4-√15)
57. √(8-√55)
58. √(7+√33)
59. √(6+√35)
60. √(7-3√5)
50) \(\sqrt{98-16\sqrt{3}}=4\sqrt{6}-\sqrt{2}\)
51) \(\sqrt{2-\sqrt{3}}=\dfrac{\sqrt{4-2\sqrt{3}}}{\sqrt{2}}=\dfrac{\sqrt{3}-1}{\sqrt{2}}=\dfrac{\sqrt{6}-\sqrt{2}}{2}\)
52) \(\sqrt{4+\sqrt{15}}=\dfrac{\sqrt{8+2\sqrt{15}}}{\sqrt{2}}=\dfrac{\sqrt{5}+\sqrt{3}}{\sqrt{2}}=\dfrac{\sqrt{10}+\sqrt{6}}{2}\)
53) \(\sqrt{5-\sqrt{21}}=\dfrac{\sqrt{10-2\sqrt{21}}}{\sqrt{2}}=\dfrac{\sqrt{14}-\sqrt{6}}{2}\)
54) \(\sqrt{6-\sqrt{35}}=\dfrac{\sqrt{12-2\sqrt{35}}}{\sqrt{2}}=\dfrac{\sqrt{14}-\sqrt{10}}{2}\)
55) \(\sqrt{2+\sqrt{3}}=\dfrac{\sqrt{4+2\sqrt{3}}}{\sqrt{2}}=\dfrac{\sqrt{6}+\sqrt{2}}{2}\)
56) \(\sqrt{4-\sqrt{15}}=\dfrac{\sqrt{8-2\sqrt{15}}}{\sqrt{2}}=\dfrac{\sqrt{10}-\sqrt{6}}{2}\)
Hihi
98+56+89+44:3+2:(6/6):0+9=?
8799 * 98 - 8799 * 56 -8799 * 58
8799 x 98 - 8799 x 56 - 8799 x 58
= 8799 x (98-56-58)
Mà mình thấy đề kì hình như lớp 4 chưa học số âm, bạn coi lại đề vế cuối - hay + nhé
8799 x 98 - 8799 x 56 - 8799 x 58
= 8799 x (98-56-58)
98+56+254+4589+595+54+58+558+56+585=......
98+56+254+4589+595+54+58+558+56+585=6845
nha
Dũng Bùi Mạnh98+56+254+4589+595+54+58+558+56+585=6903
56 - 36 - 16 =
98 - 38 - 18 =
77 - 27 - 7 =
82 - 52 - 2 =
56 - 36 -16 = 4
98-38-18=42
77-27-7=43
82-52-2 = 28
56-36-16=4
98-38-18=42
77-27-7=43
82-52-2=28
+89+98+56=
ai nhanh nhat minh tk cho
89 + 98 + 56 = 243
tk giúp mk nha ạ!
35+67+67+98+27+89+38+19+56+19+17=?
35 + 67 + 67 + 98 + 27 + 89 + 38 + 19 + 56 + 19 + 17 = 532
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tính
34+7 89+11 56+9
53-8 78-71 98-9
34 + 7 = 41
89 + 11 =100
56 + 9 = 65
53 - 8 = 45
78 - 71 = 7
98 - 9 =89
k cho mình nhé