Viết PTHH hoàn thành sơ đò chuỗi phản ứng sau
Al(OH)\(_{ }\)\(_3\) \(\underrightarrow{\left(1\right)}\) Al\(_2\)O\(_3\)\(\underrightarrow{\left(2\right)}\) Al\(_2\)(SO\(_4\))\(_3\)\(\underrightarrow{\left(3\right)}\) BaSO\(_4\)
Viết PTHH hoàn thành chuỗi chuyển hóa sau:
\(a.Na\underrightarrow{\left(1\right)}NaOH\underrightarrow{\left(2\right)}Al\left(OH\right)_3\underrightarrow{\left(3\right)}Al_2O_3\underrightarrow{\left(4\right)}Al\underrightarrow{\left(5\right)}Al_2\left(SO_4\right)_3\underrightarrow{\left(6\right)}BaSO_4\)
(1) 2Na+2H2O--->2NaOH+H2
(2) 3NaOH+Al(NO3)3--->Al(OH)3+3NaNO3
(3) 2Al(OH)3--->Al2O3+3H2O
(4) 2Al2O3-đpnc---> 4Al+3O2
(5) 2Al+3H2SO4--->Al2(SO4)3+3H2
(6) Al2(SO4)3+3BaCl2--->3BaSO4+2AlCl3
(1) 2Na+2H2O->2NaOH+H2
(2) 3NaOH+AlCl3->Al(OH)3+3NaCl
(3) 2Al(OH)3->Al2O3+3H2O
(4) 2Al2O3-điện phân nóng chảy->4Al+3O2
(5) 2Al+3H2SO4->Al2(SO4)3+3H2
(6) Al2(SO4)3+3BaCl2->3BaSO4+2AlCl3
Viết ptpư theo sơ đồ biến hóa sau:
a) \(Al_2\left(SO_4\right)_3\underrightarrow{\left(1\right)}AlCl_3\underrightarrow{\left(2\right)}Al\left(NO_3\right)_3\underrightarrow{\left(3\right)}Al\left(OH\right)_3\underrightarrow{\left(4\right)}Al_2O_3\underrightarrow{\left(5\right)}Al\)
1) Al\(_2\)(SO\(_4\))\(_3\)+3BaCl\(_2\)→2AlCl\(_3\)+3BaSO\(_4\)↓
2)AlCl\(_3\)+3AgNO\(_3\)→Al(NO\(_3\))\(_3\)+3AgCl↓
3)Al(NO\(_3\))\(_3\)+3NaOH→Al(OH)\(_3\)+3NaNO\(_3\)
4)2Al(OH)\(_3\)\(\underrightarrow{to}\)Al2O3+3H2O
5)2Al2O3\(\xrightarrow[criolit]{đpnc}\)4Al+3O2
Hoàn thành PTHH sau:
Mg+O\(_2\)\(\underrightarrow{t^o}\)
Fe+O\(_2\)\(\underrightarrow{t^o}\)
Zn+O\(_2\)\(\underrightarrow{t^o}\)
S+O\(_2\)\(\underrightarrow{t^o}\)
P+O\(_2\)\(\underrightarrow{t^o}\)
?+?\(\underrightarrow{t^o}\)H\(_3\)PO\(_4\)
?+?\(\underrightarrow{t^o}\)HNO\(_3\)
Mg+HCl\(\underrightarrow{t^o}\)
?+HCl\(\underrightarrow{t^o}\)ZnCl\(_2\)
?+H\(_2\)O\(\underrightarrow{t^o}\)NaOH
?+?\(\underrightarrow{t^o}\)Ba(OH)\(_2\)
Giúp tớ đi =)
\(2Mg+O_2\rightarrow\left(t^o\right)2MgO\)
\(3Fe+2O_2\rightarrow\left(t^o\right)Fe_3O_4\)
\(2Zn+O_2\rightarrow\left(t^o\right)2ZnO\)
\(S+O_2\rightarrow\left(t^o\right)SO_2\)
\(4P+5O_2\rightarrow\left(t^o\right)2P_2O_5\)
\(P_2O_5+3H_2O\rightarrow2H_3PO_4\)
\(N_2O_5+H_2O\rightarrow2HNO_3\)
\(Mg+2HCl\rightarrow MgCl_2+H_2\)
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(Na_2O+H_2O\rightarrow2NaOH\)
\(BaO+H_2O\rightarrow Ba\left(OH\right)_2\)
Câu 1 ) A / Mg(NO3) \(\underrightarrow{\left(1\right)}\) Mg(OH)2 \(\underrightarrow{\left(2\right)}\) MgCl2\(\underrightarrow{\left(3\right)}\) KCl \(\underrightarrow{\left(4\right)}\) KNO3
B/ \(Na\underrightarrow{\left(1\right)}Na_2O\underrightarrow{\left(2\right)}NaOH\underrightarrow{\left(3\right)}Na_2SO_4\underrightarrow{\left(4\right)}NaCl\underrightarrow{\left(5\right)}NaNO_3\underrightarrow{\left(6\right)}NaCl\underrightarrow{\left(7\right)}NaOH\)
C/\(Mg\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgCl_2\underrightarrow{\left(3\right)}Mg\left(NO_3\right)_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgSO_4\underrightarrow{\left(6\right)}MgCO_3\)
D/\(CuSO_4\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuO\underrightarrow{\left(3\right)}CuCl_2\underrightarrow{\left(4\right)}Cu\left(OH\right)_2\underrightarrow{\left(5\right)}CuSO_4\)
E/\(CuCl_2\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuSO_4\underrightarrow{\left(3\right)}Cu\underrightarrow{\left(4\right)}CuO\)
F/ \(Cu\left(OH\right)_2\underrightarrow{\left(1\right)}CuO\underrightarrow{\left(2\right)}CuCl_2\underrightarrow{\left(3\right)}Cu\left(NO_3\right)_2\underrightarrow{\left(4\right)}NaNO_3\)
G/\(Fe_2O_3\underrightarrow{\left(1\right)}FeCl_3\underrightarrow{\left(2\right)}Fe\left(OH\right)_3\underrightarrow{\left(3\right)}Fe_2O_3\underrightarrow{\left(4\right)}Fe_2\left(SO_4\right)_3\)
H/ \(ZnCl_2\underrightarrow{\left(1\right)}Zn\left(OH\right)_2\underrightarrow{\left(2\right)}ZnCl_2\underrightarrow{\left(3\right)}NaCl\underrightarrow{\left(4\right)}NaNO_3\)
M/\(CuO\underrightarrow{\left(1\right)}CuCl_2\underrightarrow{\left(2\right)}Cu\left(OH\right)_2\underrightarrow{\left(3\right)}CuO\underrightarrow{\left(4\right)}CuSO_4\)
N/\(Fe\left(OH\right)_2\underrightarrow{\left(1\right)}FeO\underrightarrow{\left(2\right)}FeCl_2\underrightarrow{\left(3\right)}Fe\left(ỌH_2\right)\underrightarrow{\left(4\right)}FeSO_4\underrightarrow{\left(5\right)}FeCl_2\underrightarrow{\left(6\right)}Fe\left(NO_3\right)_2\)
Z/ \(Mg\left(OH\right)_2\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgSO_4\underrightarrow{\left(3\right)}MgCl_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgCl_2\underrightarrow{\left(6\right)}Mg\left(NO_3\right)_2\)
X/\(Al\left(OH\right)_3\underrightarrow{\left(1\right)}Al_2O_3\underrightarrow{\left(2\right)}AlCl_3\underrightarrow{\left(3\right)}Al\underrightarrow{\left(4\right)}Al_2\left(SO_4\right)_3\)
g) 1. Fe2O3 + 6HCl → 2FeCl3 + 3H2O
2. FeCl3 + 3NaOH → 3NaCl + Fe(OH)3↓
3. 2Fe(OH)3 \(\underrightarrow{to}\) Fe2O3 + 3H2O
4. Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O
h) 1. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2↓
2. Zn(OH)2 + 2HCl → ZnCl2 + 2H2O
3. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2↓
4. NaCl + AgNO3 → NaNO3 + AgCl↓
m) 1. CuO + 2HCl → CuCl2 + H2O
2. CuCl2 + 2NaOH → 2NaCl + Cu(OH)2↓
3. Cu(OH)2 \(\underrightarrow{to}\) CuO + H2O
4. CuO + H2SO4 → CuSO4 + H2O
O\(_2\)\(\underrightarrow{ }\)Fe\(_3\)O\(_4\)\(\underrightarrow{ }\)Fe\(\underrightarrow{ }\)FeCl\(_2\)
\(\downarrow\)
H\(_2\)
(1)O\(_2\)+ \(\rightarrow\)Fe\(_3\)O\(_4\)
2O2+3Fe-to>Fe3O4
Fe3O4+4H2-to>3Fe+4H2O
2Fe+3Cl2-to>2Fecl3
Fe+2HCl->Fecl2+H2
\(3Fe+2O_2\rightarrow\left(t^o\right)Fe_3O_4\)
\(Fe_3O_4+4H_2\rightarrow\left(t^o\right)3Fe+4H_2O\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
Viết PTHH cho mỗi chuyển đổi sau:
S\(\underrightarrow{\left(1\right)}\)SO\(_2\)\(\underrightarrow{\left(2\right)}\)Na\(_2\)SO\(_3\)\(\underrightarrow{\left(3\right)}\)SO\(_2\)\(\underrightarrow{\left(4\right)}\)H\(_2\)SO\(_3\)
\(S+O_2\underrightarrow{t^o}SO_2\uparrow\\ Na_2O+SO_2\underrightarrow{t^o}Na_2SO_3\\ 2HCl+Na_SSO_3\rightarrow H_2O+2NaCl+SO_2\uparrow\\ H_2O+SO_2\rightarrow H_2SO_3\)
S + O2 → SO2↑ (1)
SO2 + Na2O → Na2SO3 (2)
H2SO4 + Na2SO3 → H2O + Na2SO4 + SO2↑ (3)
SO2 + H2O → H2SO3 (4)
Chúc bạn học tốt !!!
Viết PTHH thực hiện sơ đồ sau:
a) \(KMnO_4\underrightarrow{\left(1\right)}O_2\underrightarrow{\left(2\right)}SO_2\underrightarrow{\left(3\right)}SO_3\underrightarrow{\left(4\right)}H_2SO_4\underrightarrow{\left(5\right)}Al_{2_{ }}\left(SO_4\right)_3\)
b) \(Ca\underrightarrow{\left(1\right)}CaO\underrightarrow{\left(2\right)}Ca\left(OH\right)_2\underrightarrow{\left(3\right)}CaCo_3\underrightarrow{\left(4\right)}H_2\)
Cảm ơn ạ.
a) (1) 2 KMnO4 -to-> K2MnO4 + MnO2 + O2
(2) S + O2 -to-> SO2
(3) 2 SO2 + O2 -450 độ C, xúc tác -> 2 SO3
(4) SO3 + H2O -> H2SO4
(5) 2 Al + 3 H2SO4 -> Al2(SO4)3 +3 H2
b) Các PTHH:
(1) 2 Ca + O2 -to-> 2 CaO
(2) CaO + H2O -> Ca(OH)2
(3) Ca(OH)2 + CO2 -> CaCO3+ H2O
(4) CaCO3 thì không ra H2 được
2KMnO4-to>K2MnO4+MnO2+O2
O2+S-to>SO2
2SO2+O2-to>2SO3
SO3+H2O->H2SO4
3H2SO4+2Al->Al2(SO4)3+3H2
2>
Ca+O2-to>CaO
CaO+H2O->Ca(OH)2+H2
Ca(OH)2+CO2->CaCO3
CaCO3-->H2??
Viết PTHH hoàn thành chuỗi chuyển hóa sau:
\(Fe\underrightarrow{\left(1\right)}FeCl_3\underrightarrow{\left(2\right)}Fe\left(OH\right)_3\underrightarrow{\left(3\right)}Fe_2O_3\underrightarrow{\left(4\right)}Fe_2\left(SO_4\right)_3\underrightarrow{\left(5\right)}FeCl_3\)
(1) 2Fe + 3Cl2 -t0-> 2FeCl3
(2) FeCl3 + 3NaOH - > Fe(OH)3 + 3NaCl
(3) 2Fe(OH)3 -t0-> Fe2O3 + 3H2O
(4) Fe2O3 + 3H2SO4(l) - > Fe2(SO4)3 + 3H2O
(5) Fe2(SO4)3 + 3BaCl2 - > 2FeCl3 + 3BaSO4
1. 2Fe + 3Cl2 \(\rightarrow\)2 FeCl3
2. FeCl3 + 3NaOH \(\rightarrow\) Fe(OH)3 + 3NaCl
3. 2Fe(OH)3 \(\rightarrow\) Fe2O3 + 3H2O
4. Fe2O3 + 3H2SO4 \(\rightarrow\) Fe2(SO4)3 + 3H2O
5. Fe2(SO4)3 + 3BaCl2 \(\rightarrow\) 2FeCl3 + 3BaSO4
Viết PTHH cho mỗi chuyển đổi sau:
CaO\(\underrightarrow{\left(1\right)}\)CaCO\(_3\)\(\underrightarrow{\left(2\right)}\)CaO\(\underrightarrow{\left(3\right)}\)Ca(OH)\(_2\)\(\underrightarrow{\left(4\right)}\)CaCl\(_2\)
( 1) \(CaO+CO_2\rightarrow CaCO_3\)
( 2 ) \(CaCO_3\underrightarrow{t^0}CaO+CO_2\uparrow\)
( 3) \(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)
( 4 ) \(Ca\left(OH\right)_2+MgCl_2\rightarrow CaCl_2+Mg\left(OH\right)_2\downarrow\)
1) CaO + CO2 → CaCO3
2) CaCO3 → CaO + CO2 (to)
3) CaO + H2O → Ca(OH)2
4) Ca(OH)2 + 2HCl → CaCl2 + 2H2O
1) CaO + CO2 → CaCO3
2) CaCO3 \(\underrightarrow{t^o}\) CaO + CO2
3) CaO + H2O → Ca(OH)2
4) Ca(OH)2 + 2HCl → CaCl2 + 2H2O