a: 6^9=(6^3)^3=216^3>15^3

B: 6^36=(6^2)^18=36^18>35^18

c: 7^18=(7^2)^9=49^9>30^9

d: 3^500=243^100

7^300=343^100

=>3^500<7^300

a) 7^13 = 7.7^12 = 7.(7^2)^6 = 7. 49^6 > 39^6

b) 9^36 = 9^4.9^32 = 9^4. (9^2)^16 = 9^4.81^16 > 79^16

a) \(\sqrt{36-25}=\sqrt{11}\)

   \(\sqrt{36}-\sqrt{25}=6-5=1\)

 Suy ra \(\sqrt{36-25}>\sqrt{36}-\sqrt{25}\)

a,\(\sqrt{36-25}=-1\)

\(\sqrt{36}-\sqrt{25}=1\)

Vậy: \(\sqrt{36-25}< \sqrt{36}-\sqrt{25}\)

a. ta có: \(\sqrt{36-25}=\sqrt{11}\)   (1)

\(\sqrt{36}-\sqrt{25}=6-5=1\)(2)

từ (1) và (2) suy ra : \(\sqrt{36-25}>\sqrt{36}-\sqrt{25}\)

A < B

k cho mình nha

rồi minh k lại

TA có : A< 1/30x20 

=> A< 2/3=4/6 < 5/6

Vậy A< B 

số số hạng : (90 - 30) : 3 + 1 = 21

A = (1/90 + 1/30) x 21 : 2 = 7/15

vậy A < B

a: 6/7=1-1/7

5/6=1-1/6

mà -1/7>-1/6

nên 6/7>5/6

b: 11/10>1>10/11

c: 18/36=3/6<7/6

6/7 bé hơn 5/6

11/10 lớn hơn 10/11

18/36 bé hơn 7/6

Ta có: \(\dfrac{6}{7}=\dfrac{6\times6}{7\times6}=\dfrac{36}{42};\dfrac{5}{6}=\dfrac{5\times7}{6\times7}=\dfrac{35}{42}\)

\(\Rightarrow\dfrac{36}{42}>\dfrac{35}{42}\)

\(\Rightarrow\dfrac{6}{7}>\dfrac{5}{6}\)

Ta có: \(\dfrac{11}{10}=\dfrac{11\times11}{10\times11}=\dfrac{121}{110};\dfrac{10}{11}=\dfrac{10\times10}{11\times10}=\dfrac{100}{110}\)

\(\Rightarrow\dfrac{121}{110}>\dfrac{100}{110}\)

\(\Rightarrow\dfrac{11}{10}>\dfrac{10}{11}\)

Ta có: \(\dfrac{18}{36}\) giữ nguyên ; \(\dfrac{7}{6}=\dfrac{7\times6}{6\times6}=\dfrac{42}{36}\)

\(\Rightarrow\dfrac{18}{36}< \dfrac{42}{36}\)

\(\Rightarrow\dfrac{18}{36}< \dfrac{7}{6}\)

a: 58/63=3190/3465

36/55=2268/3465

=>58/63>36/55

b: 27/53=1998/3922

36/74=1908/3922

=>27/53>36/74

Ta có

2\(^{90}\)=\(\left(2^5\right)^{18}\)\(=32^{18}\)

\(5^{36}=\left(5^2\right)^{18}=25^{18}\)

Vì 32>25

=>\(32^{18}>25^{18}\)

=>\(2^{90}>5^{36}\)

Vậy...........

\(2^{90}=\left[2^{10}\right]^9=1024^9\)

\(5^{36}=\left[5^4\right]^9=625^9\)

Vì \(1024^9< 625^9\)

nên \(2^{90}< 5^{36}\)

2⁹⁰ = ( 2⁵ )¹⁸ = 32¹⁸

5³⁶ = ( 5² )¹⁸ = 25¹⁸

Vì 36¹⁸ > 25¹⁸

Nên 2⁹⁰ > 5³⁶

18/36 và 7/6

rút gọn phấn số 18/36 = 3/6

vậy 3/6 < 7/6 hoặc 18/36 < 7/6

18/26=1/2

1/2<1

7/6>1

1/2<7/6

HT

Ta có : \(\frac{18}{36}=\frac{3.6}{6.6}=\frac{3}{6}\)

\(\frac{3}{6}< \frac{7}{6}\)

\(\Rightarrow\frac{18}{36}< \frac{7}{6}\)

Hoặc 

\(\frac{18}{36}< 1\left(18< 36\right)\)

\(\frac{7}{6}>1\left(7>6\right)\)

\(\Rightarrow\frac{18}{36}< \frac{7}{6}\)

HT