\(a,81\cdot2022+25\cdot2022-6\cdot2022=2022\cdot\left(81+25-6\right)=2022\cdot100=202200\)

\(b,\left(x-1\right)\cdot\frac{2}{3}-\frac{1}{5}=\frac{2}{5}\)

\(\left(x-1\right)\cdot\frac{2}{3}=\frac{3}{5}\)

\(x-1=\frac{9}{10}\)

\(x=\frac{19}{10}\)

Vậy \(x=\frac{19}{10}\)

( Nếu phần b là hỗn số thì mình làm thế kia , còn nếu là nhân thì bạn tham khảo Câu hỏi của lương bảo ngọc - Toán lớp 5 - Học trực tuyến OLM nhé )

81 x 2022 + 25 x 2022 - 6 x 2022

= ( 81 + 25 - 6 ) x 2022

= 100 x 2022

= 202 200

b) \(\left(\text{x - 1}\right)\frac{\text{2}}{\text{3}}-\frac{\text{1}}{\text{5}}=\frac{\text{2}}{\text{5}}\)

\(\frac{\text{3 x }\text{( x - 1 ) }+\text{2}}{\text{3}}=\frac{\text{1}}{\text{5}}+\frac{\text{2}}{\text{5}}=\frac{\text{3}}{\text{5}}\)

=> \(\text{3 x ( x - 1 ) }+\text{2}=\frac{\text{3}}{\text{5}}\text{ x 3 = }\frac{\text{9}}{\text{5}}\)

=> \(\text{3 x ( x - 1 ) }=\frac{\text{9}}{\text{5}}-\text{2}=\frac{\text{-1}}{\text{5}}\)

=> \(\text{ x-1}=\frac{\text{-1}}{\text{5}}:3=\frac{\text{-1}}{\text{15}}\)

=> \(\text{x}=\frac{\text{-1}}{\text{15}}+\text{1 = }\frac{\text{14}}{\text{15}}\)

dạ vâng a off

\(=2022\times\left(1+1+1+1+1+5-7\right)\)

= 2022 x 3

= 6066

2022 + 2022 + 2022 + 2022 + 2022 + 2022 x 5 - 2022 x 7

= 2022 x 1 + 2022 x 1 + 2022 x 1 + 2022 x 1 + 2022 x 1 + 2022 x 5 - 2022 x 7

= 2022 x ( 1 + 1 + 1 + 1 + 1 + 5 - 7 )

= 2022 x 3 

= 6066

\(a,50\%+\dfrac{7}{12}-\dfrac{1}{2}\\ =\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}\\ =\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}\\ =\dfrac{7}{12}\\ b,2022\times67+2022\times43-2022\times10\\ =2022\times\left(67+43-10\right)\\ =2022\times100\\ =202200.\\ c,125-25:3\times12\)

\(=25\times5-25:3\times12\\ =25\times\left(5-\dfrac{1}{3}\right)\times12\\ =25\times\dfrac{14}{3}\times12\\ =1400\)

a,50%+127​−21​=21​+127​−21​=(21​−21​)+127​=127​b,2022×67+2022×43−2022×10=2022×(67+43−10)=2022×100=202200.c,125−25:3×12

=25×5−25:3×12=25×(5−13)×12=25×143×12=1400=25×5−25:3×12=25×(5−31​)×12=25×314​×12=1400

a) 7/12

b) 202200

c) 1400

d) mình ko bt

B

B

`a, A = 3020 xx 3110 - 5 = 3020 xx 3109 + 3020 - 5`

`= 3020 xx 3109 + 3015 = B`.

`b, B = (2022-2)(2022+2) = 2022^2-4 < 2022^2 = A.`

\(\left|x+\dfrac{4}{5}\right|=\dfrac{2022}{2023}\)

\(\Rightarrow x+\dfrac{4}{5}=\dfrac{2022}{2023}\) hoặc \(x+\dfrac{4}{5}=\dfrac{-2022}{2023}\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{4}{5}=\dfrac{2022}{2023}\\x+\dfrac{4}{5}=\dfrac{-2022}{2023}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{2022}{2023}-\dfrac{4}{5}\\x=\dfrac{-2022}{2023}-\dfrac{4}{5}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{10110}{10115}-\dfrac{8092}{10115}\\x=\dfrac{-10110}{10115}-\dfrac{8092}{10115}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{2018}{10115}\\x=-1,799505685\end{matrix}\right.\)

mình đã làm r?

`| x + 4/5 | = 2022/2023`

`@ TH1`

` x + 4/5= 2022/2023`

`=> x= 2022/2023-4/5`

`=>x=2018/10115`

`@ TH2`

` x + 4/5=- 2022/2023`

`=>x=- 2022/2023-4/5`

`=>x=-1,799505685`

\(\left(-67\right)+125+\left(-33\right)+75\)

\(=\left[\left(-67\right)+\left(-33\right)\right]+\left(125+75\right)\)

\(=100+200=300\)

_______

\(86.\left(-108\right)+86.9-86\)

\(=86.\left[\left(-108\right)+9-1\right]\)

\(=86.\left(-100\right)=-8600\)

_______

\(23.\left(-16\right)-23.84+300\)

\(=23.\left[\left(-16\right)-84\right]+300\)

\(=23.\left(-100\right)+300\)

\(=-2300+300\)

\(=-2000\)

______

\(235-5\left[\left(5^3-3^3\right):14\right]\)

\(=235-5\left[\left(125-27\right):14\right]\)

\(=235-5\left[98:14\right]\)

\(=235-5.7\)

\(=235-35\)

\(=200\)

_______

\(95-\left(129-74\right):5+2022^0\)

\(=95-55:5+1\)

\(=95-11+1\)

\(=84+1=85\)

\(#NqHahh\)