\(bx^2=ay^2\Leftrightarrow\dfrac{x^2}{a}=\dfrac{y^2}{b}\Leftrightarrow\left(\dfrac{x^2}{a}\right)^{1010}=\left(\dfrac{y^2}{b}\right)^{1010}\\ \Leftrightarrow\dfrac{x^{2020}}{a^{1010}}=\dfrac{y^{2020}}{a^{1010}}\)

Áp dụng t/c dtsbn:

\(\dfrac{x^{2020}}{a^{1010}}=\dfrac{y^{2020}}{b^{1010}}=\dfrac{x^{2020}+y^{2020}}{a^{1010}+b^{1010}}\left(3\right)\)

Đặt \(\dfrac{x^2}{a}=\dfrac{y^2}{b}=k\Leftrightarrow x^2=ak;y^2=bk\)

\(x^2+y^2=1\Leftrightarrow ak+bk=1\Leftrightarrow k\left(a+b\right)=1\Leftrightarrow a+b=\dfrac{1}{k}\)

\(\Leftrightarrow\dfrac{2}{\left(a+b\right)^{1010}}=\dfrac{2}{\left(\dfrac{1}{k}\right)^{1010}}=2:\dfrac{1}{k^{1010}}=k^{1010}\left(1\right)\)

Mà \(\dfrac{x^{2020}}{a^{1010}}=\dfrac{\left(x^2\right)^{1010}}{a^{1010}}=\dfrac{a^{1010}k^{1010}}{a^{1010}}=k^{1010}\left(2\right)\)

Từ \(\left(1\right)\left(2\right)\left(3\right)\) ta được đpcm

Hướng dẫn giải:

a) 71 x 5 x 4 = 71 x (5 x 4) = 71 x 20 = 1420

b) 123 x 50 x 2 = 123 x (50 x 2) = 123 x 100 = 12300

c) 4 x 138 x 25 = (4 x 25) x 138 = 100 x 138 = 13800

d) 25 x 96 x 4 = (25 x 4) x 96 = 100 x 96 = 9600

e) 5 x 81 x 2 = (5 x 2) x 81 = 10 x 81 = 810

g) 50 x 104 x 2 = (50 x 2) x 104 = 100 x 104 = 10400

tự làm đi

dễ lắm hải ơi

em vừa hỏi cô Huyền xong , đơn giản cực