Bài 1:

\(a.\left(-356+57\right)-\left(27-356\right)=-356+57-27+356=\left(-356+356\right)+\left(57-27\right)=30\) \(b.125.\left(-24+24.225\right)=125.\left(-24+5400\right)=125.\left(-24\right)+125.5400=-3000+675000=672000\)

\(c.26.\left(-125\right)-125.\left(-36\right)=-125.\left(26-36\right)=-125.\left(-10\right)=1250\)

Bài 2:

\(a.\left(2x-4\right)^2=0\)

\(\Rightarrow2x-4=0\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)

\(b.\frac{x+5}{x+3}=\frac{x+3+2}{x+3}=\frac{x+3}{x+3}+\frac{2}{x+3}=1+\frac{2}{x+3}\)

Để (x+5) chia hết cho (x+3) thì 2 phải chia hết cho (x+3)

\(\Rightarrow x+3\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)

\(x+3=1\Rightarrow x=-2\)

\(x+3=-1\Rightarrow x=-4\)

\(x+3=2\Rightarrow x=-1\)

\(x+3=-2\Rightarrow x=-5\)

Vậy \(x\in\left\{-2;-4;-1;-5\right\}\)

Bài 2:

a)\(\left(2x-4\right)^2=0\)

\(\Leftrightarrow2x-4=0\)

\(\Leftrightarrow2x=4\Leftrightarrow x=2\)

b)\(\frac{x+5}{x+3}=\frac{x+3+2}{x+3}=\frac{x+3}{x+3}+\frac{2}{x+3}=1+\frac{2}{x+3}\in Z\)

Suy ra \(2⋮x+3\Rightarrow x+3\inƯ\left(2\right)=\left\{1;-1;2;-2\right\}\)

\(\Rightarrow x\in\left\{-2;-4;-1;-5\right\}\)

a) \(125\cdot\left(-24\right)+24\cdot225\)

\(=\left(225-125\right)\cdot24\)

\(=100\cdot24\)

\(=2400\)

b) \(26\cdot\left(-125\right)-125\cdot\left(-36\right)\)

\(=\left(36-26\right)\cdot125\)

\(=10\cdot125\)

\(=1250\)

a) 2400

b)1200

\(a,\frac{15^3.\left(-5\right)^4}{\left(-3\right)^5.5^6}\)\(=\frac{3^3.5^3}{\left(-3\right)^5.5^2}\)\(=-\frac{5}{\left(3\right)^2}=-\frac{5}{9}\)

\(b,\frac{6^3.2.\left(-3\right)^2}{\left(-2\right)^9.3^7}\)\(=-\frac{6^3}{2^8.3^5}\)\(=-\frac{2^3.3^3}{2^8.3^5}\)\(=-\frac{1}{2^5.3^2}=-\frac{1}{288}\)

\(c,\frac{3^6.7^2-3^7.7}{3^7.21}\)\(=\frac{3^6.7\left(7-3\right)}{3^7.21}\)\(=\frac{3^6.7.4}{3^7.7.3}\)\(=\frac{4}{3.3}=\frac{4}{9}\)

\(a,\left(x-1,2\right)^2=4\)

\(\Rightarrow x-1,2=2\)

\(\Rightarrow x=3,2\)

\(b,\left(x+1\right)^3=-125\)

\(\Rightarrow\left(x+1\right)^3=\left(-5\right)^3\)

\(\Rightarrow x+1=-5\Rightarrow x=-6\)

\(c,\left(x-5\right)^3=2^6\)

\(\Rightarrow\left(x-5\right)^3=4^3\)

\(\Rightarrow x-5=4\Rightarrow x=9\)

\(d,\left(2x+1\right)^{x+1}=5^{x+1}\)

\(\Rightarrow2x+1=5\Rightarrow x=2\)

\(e,\left(5-x\right)^2+\left(5-x\right)^5=0\)

\(\Rightarrow\left(5-x\right)^2\left(1+\left(5-x\right)^3\right)=0\)

\(\Rightarrow\orbr{\begin{cases}\left(5-x\right)^2=0\\1+\left(5-x\right)^3=0\end{cases}\Rightarrow}\orbr{\begin{cases}5-x=0\\5-x=-1\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=6\end{cases}}}\)

\(f,\left(1-2x\right)^4-\left(1-2x\right)^6=0\)

\(\Rightarrow\left(1-2x\right)^4\left(1-\left(1-2x\right)^2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}1-2x=0\\1-2x=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{1}{2}\\0\end{cases}}\)

\(g,3^{4-x}-1=26\)

\(\Rightarrow3^{4-x}=27\Rightarrow3^{4-x}=3^3\Rightarrow4-x=3\Rightarrow x=1\)

Bài 1:

\(A=26^2-24^2=\left(26-24\right)\left(26+24\right)=2\cdot50=100\)

\(B=27^2-25^2=\left(27-25\right)\left(27+25\right)=2\cdot52=104\)

=>A<B

Bài 2:

\(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)=11\)

=>\(4\left(x^2+2x+1\right)+4x^2-4x+1-8\left(x^2-1\right)=11\)

=>\(4x^2+8x+4+4x^2-4x+1-8x^2+8=11\)

=>4x+13=11

=>4x=-2

=>\(x=-\dfrac{1}{2}\)

a) \(\left(2.x+1\right)^3=125\)

\(\Leftrightarrow\left(2.x+1\right)^3=5^3\)

\(\Leftrightarrow2.x+1=5\)

               \(2.x=5-1\)

               \(2.x=4\)

                    \(x=4:2\)

                     \(x=2\)

b) \(\left(4.x-1\right)^2=25.9\)

     \(\left(4.x-1\right)^2=225\)

\(\Leftrightarrow\left(2.x-1\right)^2=15^2\)

\(\Leftrightarrow2.x-1=15\)

\(\Rightarrow2.x=15+1\)

\(\Rightarrow2.x=16\)

\(\Rightarrow x=16:2\)

\(\Rightarrow x=8\)

a,(2x+1)³=5³

2x+1=5

2x=4

x=2

b,(4x-1)²=225

(4x-1)²=15²

4x-1=15

4x=16

x=4

sai rồi 

a)

4 . 25 – 12 . 25 + 170 : 10 

= (4 . 25) – (12 . 25) + (170 : 10) 

= 100 - 300 + 17 

= -183

b)

(7 + 33 + 32) . 4 – 3 

= (7 + 27 + 9) .4 – 3

= 43 . 4 – 3

= (43 . 4) – 3

= 45

c)

12 : {400 : [500 – (125 + 25 . 7)}

= 12 : {400 : [500 – (125 + 175)}

= 12 : (400: 200)

= 12 : 2

= 6

d)

168 + {[2.(2⁴ + 3²) - 256⁰] : 72}.

= 168 + [2 . (16 + 9) – 1] : 49

= 168 + 49: 49

= 168 + 1 

= 167

a) 

4 . 25 – 12 . 25 + 170 : 10 

= (4 . 25) – (12 . 25) + (170 : 10) 

= 100 - 300 + 17 

= -183

b)

(7 + 33 + 32) . 4 – 3 

= (7 + 27 + 9) .4 – 3

= 43 . 4 – 3

= (43 . 4) – 3

= 45

c)

12 : {400 : [500 – (125 + 25 . 7)}

= 12 : {400 : [500 – (125 + 175)}

= 12 : (400: 200)

= 12 : 2

= 6

d)

168 + {[2.(2⁴ + 3²) - 256⁰] : 72}.

= 168 + [2 . (16 + 9) – 1] : 49

= 168 + 49: 49

= 168 + 1 

= 167

a)

4.25 -12.5 + 170 : 10=100−60+17=40+17=57.​

b)

 (3:3((7+33:32).4−3=(7+3).4−3=40−3=37.

c)

 {[({[(

2:

a: A(x)=0

=>5x-10-2x-6=0

=>3x-16=0

=>x=16/3

b: B(x)=0

=>5x^2-125=0

=>x^2-25=0

=>x=5 hoặc x=-5

c: C(x)=0

=>2x^2-x-3=0

=>2x^2-3x+2x-3=0

=>(2x-3)(x+1)=0

=>x=3/2 hoặc x=-1