\(\dfrac{4-x}{-5}=\dfrac{-5}{4-x}\)
\(\Leftrightarrow\left(4-x\right)\left(4-x\right)=-5\times-5\)
\(\Rightarrow\left(4-x\right)^2=25\)
\(\Rightarrow\left[{}\begin{matrix}4-x=5\\4-x=-5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=9\end{matrix}\right.\)

\(\dfrac{4-x}{-5}=\dfrac{-5}{4-x}\)

\(\Rightarrow\left(4-x\right).\left(4-x\right)=\left(-5\right).\left(-5\right)\)

\(\Rightarrow\left(4-x\right)^2=25\)

\(\Rightarrow\left(4-x\right)^2=5^2\)

\(\Rightarrow4-x=\pm5\)

\(\Rightarrow\left[{}\begin{matrix}4-x=5\\4-x=-5\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=4-5\\x=4-\left(-5\right)\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=9\end{matrix}\right.\)

=>(4-x)^2=25

=>(x-4)^2=25

=>x-4=5 hoặc x-4=-5

=>x=-1 hoặc x=9

\(4^x+4^{x+3}=4160\)

\(\Leftrightarrow4^x.\left(1+4^3\right)=4160\)

\(\Leftrightarrow4^x.65=4160\)

\(\Leftrightarrow4^x=4160:65=64\)

\(\Rightarrow x=3\)

4(x-12)-2=50

4(x-12)=50+2

4(x-12)=52

x-12=52÷4

x-12=13

x=25

4(x-12)-2=50

4(x-12)=50+2

4(x-12)=52

x-12=52÷4

x-12=13

x=25

x=9,16515139?

4 /x=y/21=28/49

vì 21.4/12=7 nên x=7

    28.21/49 =12 nên y=12 (công thức nhân chéo)

vậy ,x=7 ;y=12

a) x=3/7

b)x=8/7

c)x=6/7

a)\(x=\dfrac{2}{7}:\dfrac{2}{3}=\dfrac{3}{7}\)

b)\(x=\dfrac{13}{7}\times\dfrac{8}{13}=\dfrac{8}{7}\)

c)\(x=\dfrac{3}{2}:\dfrac{7}{4}=\dfrac{6}{7}\)

=3/7

=8/7

=6/7

1)\(3,5\cdot x+1,54\cdot3,5=15\)

    \(3,5\left(x+1,54\right)=15\)

                 \(x+1,54=\frac{15}{3,5}\)

                 \(x+1,54=\frac{30}{7}\)

                                \(x=\frac{30}{7}-1,54\)

                                 \(x=\frac{30}{7}-\frac{77}{50}\)

                               \(x=\frac{961}{350}\)

\(20+\frac{12}{x-2019}=32\)

             \(\frac{12}{x-2019}=32-20\)

              \(\frac{12}{x-2019}=12\)

               \(x-2019=\frac{12}{12}\)

              \(x-2019=1\)

                               \(x=1+2019\)

2)

\(\frac{3}{7}\cdot\frac{4}{13}+\frac{3}{7}\cdot\frac{9}{13}+5\frac{4}{7}\)

\(=\frac{3}{7}\cdot\frac{4}{13}+\frac{3}{7}\cdot\frac{9}{13}+13\cdot\frac{3}{7}\)

\(=\frac{3}{7}\left(\frac{4}{13}+\frac{9}{13}+13\right)\)

\(=\frac{3}{7}\cdot14\)

\(=6\)

3.5*(x-1.54)=15

x+1.54=15;3.5

x+1.54=4.28

x=4.28-1.54

x=2.74

chưa suy nghĩ

3,5×(x+1,54)=15

(x+1,54)=15:3,5

(x+1,54)=30/7

(x+77/50)=30/7

x=30/7-77/50

x=961/350

\(4-\left(7-x\right)=x-\left(13-4\right)\)

     \(4-7-x=x-9\)

          \(-x-x=-9-4+7\)

                \(-2x=-6\)

                       \(x=3\)

X + 5/9 = 4/3   

X = 4/3 - 5/9

X = 7/9 

X - 4/9 = 1/2       

X = 1/2 + 4/9

X =  17/18 

6/13 + X = 7/6 

X = 7/6 - 6/13

X = 55/78

13/5 - X = 5/6   
X = 13/5 - 5/6

X= 53/30

X + 5/9 = 4/3 

x           = 4/3 - 5/9

x           =   7/9

  X - 4/9 = 1/2   

  x          = 1/2 + 4/9 

  x          =   17/18        

6/13 + X = 7/6     

            x = 7/6 - 6/13 

            x -  55/78

13/5 - X = 5/6 

          x  = 13/5 - 5/6

          x  =   53/30   

hc ngiu thế eim anh lười giải lắm =))))

\(a,\dfrac{2}{3}.x=\dfrac{2}{7}\\ x=\dfrac{2}{7}:\dfrac{2}{3}=\dfrac{3}{7}\\ ---\\ b,x.\dfrac{3}{5}=\dfrac{2}{5}\\ x=\dfrac{2}{5}:\dfrac{3}{5}=\dfrac{2}{3}\\ ---\\ c,x:\dfrac{8}{13}=\dfrac{13}{7}\\x=\dfrac{13}{7}.\dfrac{8}{13}=\dfrac{8}{7}\\ ----\\ d,\dfrac{3}{2}:x=\dfrac{7}{4}\\ x=\dfrac{3}{2}:\dfrac{7}{4}=\dfrac{3}{2}.\dfrac{4}{7}=\dfrac{6}{7}\)