phan tich da thuc thanh nhan tu: 5x2 - 8x - 4
8x^3-12x^2+6x-1
phan tich da thuc thanh nhan tu chung
cái này dễ mà
= (2x)^3-3(2x)^2*1+2*3x*1^2-1^3
= (2x-1)^3
phan tich da thuc thanh nhan tu d/ (x^2 +6x+8) (x^2+8x+15)-24
(x2 + 2.x.3 + 32 - 1).(x2 + 2.x.4 + 16 - 1) - 24
=[(x+3)2 - 1]. [(x+4)2-1] -24
=(x+3+1)(x+3-1)(x+4+1)(x+4-1) - 24
=(x+4)(x+2)(x+5)(x-3) - 24
(x2+6x+8)(x2+8x+15)-24
<=>(x2+4x+2x+8)(x2+5x+3x+15)-24
<=> [x(x+4)+2(x+4)][x(x+5)+3(x+5)]-24
<=> (x+4)(x+2)(x+5)(x+3)-24
<=> (x+4)(x+3)(x+2)(x+5)-24
<=>(x2+7x+12)(x2+7x+10)
đặt t=x2+7x+11 ta có:
(t-1)(t+1)-24
<=> t2-1-24
<=>t2-25
<=>(t-5)(t+5)
thay t=x2+7x+11 vào ta có:
(x2+7x+11-5)(x2+7x+11+5)
<=>(x2+7x+6)(x2+7x+16)
phan tich da thuc sau thanh nhan tu: 3(x+5)(x+6)(x+7)-8x(2 cach)
Phan tich da thuc thanh nhan tu
( x^2-6x+ 8)( x^2-8x +15) +1
phan tich da thuc thanh nhan tu
3x^4-48
x^4-8x
x^3-6x^2+9x
\(3x^4-48\)
\(=\left(3x^4-6x^3\right)+\left(6x^3-12x^2\right)+\left(12x^2-24x\right)+\left(24x-48\right)\)
\(=3x^3\left(x-2\right)+6x^2\left(x-2\right)+12x\left(x-2\right)+24\left(x-2\right)\)
\(=\left(x-2\right)\left[\left(3x^3+6x^2\right)+\left(12x+24\right)\right]\)
\(=\left(x-2\right)\left[3x^2\left(x+2\right)+12\left(x+2\right)\right]\)
\(=\left(x-2\right)\left(x+2\right)\left(3x^2+12\right)\)
\(x^4-8x\)
\(=x\left(x^3-8\right)\)
\(=x\left[\left(x^3-2x^2\right)+\left(2x^2-4x\right)+\left(4x-8\right)\right]\)
\(=x\left[x^2\left(x-2\right)+2x\left(x-2\right)+4\left(x-2\right)\right]\)
\(=x\left(x-2\right)\left(x^2+2x+4\right)\)
\(x^3-6x^2+9x\)
\(=\left(x^3-3x^2\right)-\left(3x^2-9x\right)\)
\(=x^2\left(x-3\right)-3x\left(x-3\right)\)
\(=\left(x-3\right)\left(x^2-3x\right)\)
\(=x\left(x-3\right)\left(x-3\right)\)
Phan tich da thuc thanh nhan tu
(X^2-6x+8)(x^2-8x+15)+1
phan tich da thuc thanh nhan tu:
x^8+8x+63
ai biet giup mk vs
x4-8x+63=x4+4x3+9x2-4x3-16x2-36x+7x2+28x+63
=x2.(x2+4x+9)-4x.(x2+4x+9)+7.(x2+4x+9)
=(x2+4x+9)(x2-4x+7)
Phan tich da thuc thanh nhan tu : x2 - 4x -y2+4
\(x^2-4x+4-y^2\)
\(=\left(x-2\right)^2-y^2\)
\(=\left(x-2-y\right)\left(x-2+y\right)\)
\(x^2-4x-y^2+4=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\)
Phan tich da thuc thanh nhan tu : x2 - 4x -y2+4
\(x^2-4x+4-y^2\)
\(=\left(x-2\right)^2-y^2\)
\(=\left(x-2-y\right)\left(x-2+y\right)\)
\(=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\)
phan tich da thuc thanh nhan tu 3x^4-48
\(3x^4-48=3\left(x^4-16\right)=3\left[\left(x^2\right)^2-4^2\right]\\ =3\left(x^2-4\right)\left(x^2+4\right)\\ =3\left(x-2\right)\left(x+2\right)\left(x^2+4\right)\)