a) (3^6 . 3^6) : 3^10 + 5 . 2^4 - 7^3 : 7 b) (7^2009 - 7^2008) : 7^2008 c) (8^2022 + 8^2021) : 8^2021 d) (7^6 + 7^8) . (5^3 + 5^3) . (3^3 . 3 - 9^2) e) 3^2 . [( 5^3 - 3) : 11] - 2^4 + 2 . 10^3 f) (5^7 + 7^5) . (6^8 + 8^6) . (2^4 - 4^2) g) [( 5^2 . 2^3) - 7^2 . 2) : 2] . 6 - 7 . 2^5 Giúp mình với mình đang cần gấp
Những câu hỏi liên quan
A=1-2+3+4-5-6+7+8-9-...+2007+2008-2009-2010
B=-1-2+3+4-5-6+7+8-9-10+11+12-...-2013-2014+2015+2016
C=(2+4+6+8+...+2014)-(3+5+7+9...+2011)
A = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + ... + 2005 + 2006 - 2007 - 2008 + 2009 + 2010 ( có 2010 số )
A = ( 1 + 2 - 3 - 4 ) + ( 5 + 6 - 7 - 8 ) + .... + ( 2005 + 2006 - 2007 - 2008 ) + ( 2009 + 2010 )
A = ( - 4 ) + ( - 4 ) + ... + ( - 4 ) + 4019 ( có 503 số )
A = ( - 4 ) . 502 + 4019
A = - 2008 + 4019
A = 2011.
CHÚC LÀM BÀI VUI VẺ
e.1-2+3-4+5-6+...+2021-2022
f.7-8+9-10+11-12+...+2009-2010
g.1-3-5+7-9-11+...+1000-1002-1004
h.a-b+c+a-b+c-a+b+c
Tính
A=1-2+3+4-5-6+7+8-9-.....+2007+2008-2009-2010
B=2^2005-2^2003-2^2001-......-2-1
C=2+4+4+8+10-12-14+16+......-2006+2008+2010-2012
D=1-2-3-4+5-6-7-8+9-10-11-......-2010
a.(3^5.3^7):3^10+5.2^4-7^3:7
b.3^2[(5^2-3):11]-2^4+2.10^3
c.(6^2007-6^2006):6^2006
d.(5^2001-5^2000):5^2000
e.(7^2005+7^2004):7^2004
f.(5^7+7^5).(6^8+8^6).(2^4-4^2)
g.(7^5+7^9).(5^4+5^6).(3^3.3-9^2)
h.[(5^2.2^3-7^2.2):2].6-7.2^5
mng giúp e vs e c.ơn
BT
a,,A=48+|48-174|+(-74)
b,,B=1-2+3-4+...+2009-2010
c,,C=0-2+4-6+...+2010-2012
d,,D=13-12+11+10-9+8-7-6+5-4+3+2-1
e,,E=1-2-3+4+5-6-7+8+...+2001-2002-2003+2004
f,,F=1+2-3-4+5-6-7+8+...+2002-2003-2004+2005+2006
S=1-3+5-7+9-11+....+2023-2025
S=1+2-3-4+5+6-7-8+....+2021+2022-2023-2024
a:
Sửa đề: \(S=1-3+5-7+...+2021-2023+2025\)
Từ 1 đến 2025 sẽ có:
\(\dfrac{2025-1}{2}+1=\dfrac{2024}{2}+1=1013\left(số\right)\)
Ta có: 1-3=5-7=...=2021-2023=-2
=>Sẽ có \(\dfrac{1013-1}{2}=\dfrac{1012}{2}=506\) cặp có tổng là -2 trong dãy số này
=>\(S=506\cdot\left(-2\right)+2025=2025-1012=1013\)
b: \(S=1+2-3-4+5+6-7-8+...+2021+2022-2023-2024\)
Từ 1 đến 2024 là: \(\dfrac{\left(2024-1\right)}{1}+1=2024\left(số\right)\)
Ta có: 1+2-3-4=5+6-7-8=...=2021+2022-2023-2024=-4
=>Sẽ có \(\dfrac{2024}{4}=506\) cặp có tổng là -4 trong dãy số này
=>\(S=506\cdot\left(-4\right)=-2024\)
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Tính tổng:E=1-3+5-7+...+2013-2015
F=1+2-3-4+5+6-7-8+9+10-....+2006-2007-2008+2009
E = 1 - 3 + 5 - 7 + ... + 2013 - 2015 (1008 số hạng)
= (1 - 3) + (5 - 7) + ... + (2013 - 2015) (504 cặp)
= -2 + (-2) + ... + (-2) (504 số hạng - 2)
= 504.(-2) = -1008
F = 1 + 2 - 3 - 4 + .... + 2006 - 2007 - 2008 + 2009 (2009 SỐ HẠNG)
= 1 + (2 - 3) + (-4 + 5) + .... + (2006 - 2007) + (-2008 + 2009) (1004 cặp số)
= 1 + [(-1) + 1 + .... + (-1) + 1] (1005 số hạng)
= 1
E = 1 - 3 + 5 - 7 + .. + 2013 - 2015
E= ( 1 - 3 ) + ( 5 - 7 ) + ... + ( 2013 - 2015 )
E = - 2 + ( -2 ) + ... + (-2 )
E = -2 x 504
E= -1008
F = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + 10 - ... + 2006 -2007 - 2008 + 2009
F = ( 1 - 3 ) + ( 2 - 4 ) + ( 5 - 7 ) + ( 6 - 8 ) + ... + (2005 - 2007 ) + ( 2006 - 2008 ) + 2009
F = -2 + ( -2 ) + ( - 2 ) + ( - 2 ) + ... + ( - 2 ) + ( - 2 ) +2009
F = ( - 2 ) x 1004 + 2009
F = -2008 + 2009
F = 1
a/A=\(-1+7-7^2+7^3-7^4+...+7^{2008}+7^{2008}\)
b/B=\(1-7^2+7^4-7^6+7^8-7^{10}+...+7^{2008}\)
c/C=\(1-7^3+7^5-7^7+7^9-7^{11}+...+7^{2009}\)
Ta có A= -1+7+(-72)+73+(-74)+....+72008 +72008
A.7=[-7+72+(-73)+74+....+72009 +72009] + [ -1+7+(-72)+73+(-74)+....+72008 +72008]
A.7=[72009.2+(-1) +72008] :7
b;c làm tương tự
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Tính 1) 4/5 +13/18 2) 3/7 -11/8 3) -7/10 - -4/5 4) 3/20 -1/25 5) 2/3 - 5/6 6) 1/4 + -3/8 - 19/10 7) -9/10 - -7/18 8) 3/10 - 11/18 9) 3/5 -5/6 + -7/12 10) -4/9 - (-5 )/6 - 3/8
1: =72/90+65/90=137/90
2: =24/56-77/56=-53/56
3: =-7/10+4/5=1/10
4: =15/100-4/100=11/100
5: =4/6-5/6=-1/6
6: =10/40-15/40-76/40=-81/40
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7: =-9/10+7/18
=-81/90+35/90=-46/90=-23/45
8: =27/90-55/90=-28/90=-14/45
9: =36/60-50/60-35/60=-49/60
10: =-4/9+5/6-3/8
=-32/72+60/72-27/72
=1/72
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\(1,\dfrac{4}{5}+\dfrac{13}{18}=\dfrac{72}{90}+\dfrac{65}{90}=\dfrac{137}{90}\)
\(2,\dfrac{3}{7}-\dfrac{11}{8}=\dfrac{24}{56}-\dfrac{77}{56}=\dfrac{-53}{56}\)
\(3,-\dfrac{7}{10}-\left(-\dfrac{4}{5}\right)=-\dfrac{7}{10}-\left(-\dfrac{8}{10}\right)=\dfrac{1}{10}\)
\(4,\dfrac{3}{20}-\dfrac{1}{25}=\dfrac{75}{500}-\dfrac{20}{500}=\dfrac{55}{500}=\dfrac{11}{100}\)
\(5,\dfrac{2}{3}-\dfrac{5}{6}=\dfrac{12}{18}-\dfrac{15}{18}=-\dfrac{3}{18}=-\dfrac{1}{6}\)
\(6,\dfrac{1}{4}+\left(-\dfrac{3}{8}\right)-\dfrac{19}{10}=\dfrac{8}{32}+\left(-\dfrac{12}{32}\right)-\dfrac{19}{10}=-\dfrac{4}{32}-\dfrac{19}{10}\)
\(=-\dfrac{1}{8}-\dfrac{19}{10}=-\dfrac{10}{80}-\dfrac{152}{80}=-\dfrac{162}{80}=-\dfrac{81}{40}\)
\(7,-\dfrac{9}{10}-\left(-\dfrac{7}{18}\right)=-\dfrac{162}{180}-\left(-\dfrac{70}{180}\right)=-\dfrac{92}{180}=-\dfrac{23}{45}\)
\(8,\dfrac{3}{10}-\dfrac{11}{18}=\dfrac{54}{180}-\dfrac{110}{180}=-\dfrac{56}{180}=-\dfrac{14}{45}\)
\(9,\dfrac{3}{5}-\dfrac{5}{6}+\left(-\dfrac{7}{12}\right)=\dfrac{18}{30}-\dfrac{25}{30}+\left(-\dfrac{7}{12}\right)=-\dfrac{7}{30}+\left(-\dfrac{7}{12}\right)\)
\(=-\dfrac{84}{360}+\left(-\dfrac{210}{360}\right)=-\dfrac{294}{360}=-\dfrac{49}{60}\)
\(10,-\dfrac{4}{9}-\dfrac{-5}{6}-\dfrac{3}{8}=-\dfrac{24}{54}-\dfrac{-45}{54}-\dfrac{3}{8}\)
\(=\dfrac{21}{54}-\dfrac{3}{8}=\dfrac{7}{18}-\dfrac{3}{8}=\dfrac{56}{144}-\dfrac{54}{144}=\dfrac{2}{144}=\dfrac{1}{72}\)
`@mt`
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1. Tính hợp lí:
a) B = 1/2 - [ 3/8 + ( -7/4 ) ]
b) -4/12 - ( -13/39 - 0,25 ) + 0,75
c) 1/2 - 1/3 + 1/23 + 1/6
d) ( -13/7 - 4/9) - ( -10/7 - 4/9 )
e) ( 7/8 - 5/2 + 4/7 ) - ( -3/7 + 1 - 13/8 )
f) -3/7 + ( 3 - 3/4 ) - ( 2,25 - 10/7)
g) ( 5/3 - 3/7 + 9 ) - ( 2 + 5/7 - 2/3 ) + ( 8/7 - 4/3 - 10 )