295—(31—22.5)2
a) 295 – (31 – 22.5)2
\(=295-\left(31-20\right)^2=295-11^2=295-121=174\)
\(=295-\left(31-20\right)^2=295-121=174\)
Thực hiện phép tính 295 − ( 31 − 2 2 .5 ) 2
295 - ( 31 - 2 2 . 5 ) 2 = 295 − 11 2 = 174
a) 311 : 39 – 147 : 72
b) 295 – (31 – 22.5)2
c) 718 : 716 +22.33
a)3\(^{11}\):3\(^9\)−147:7\(^2\)
=3\(^{11}\)\(^{-9}\)−147:49
=3\(^2\)−147:49
=9−3
=6
b)295−(31−22×5)w)295-(31-22×5)
=295−(31−2\(^2\).5)\(^2\)
=295−11\(^2\)
=295−121
=174
thực hiện các phép tính:
48:4+39:37+50
=
(519:517+3):7
=
295-(31-22.5)2
=
62:9+50.2-33.3
=
\(48\div4+3^9\div3^7+5^0\)
\(=12+9+1\)
\(=22\)
\(\left(5^{19}\div5^{17}+3\right)\div7\)
\(=\left(25+3\right)\div7\)
\(=28\div7\)
\(=4\)
\(295-\left(32-2^2\times5\right)^2\)
\(=295-144\)
\(=151\)
\(6^2\div9+50\times2-3^3\times3\)
\(=36\div9+100-27\)
\(=4+100-27\)
\(=100-27\)
\(=73\)
\(48:4+3^9:3^7+5^0\)
\(=12+3^{9-7}+1\)
\(=12+9+1\)
\(=22\)
\(\left(5^{19}:5^{17}+3\right):7\)
\(=\left(5^{19-17}+3\right):7\)
\(=\left(5^2+3\right):7\)
\(=\left(25+3\right):7\)
\(=28:7\)
\(=4\)
\(295-\left(31-2^2\cdot5\right)^2\)
\(=295-\left(31-4\cdot5\right)^2\)
\(=295-\left(31-20\right)^2\)
\(=295-11^2\)
\(=295-121\)
\(=174\)
\(6^2:9+50\cdot2-3^3\cdot3\)
\(=36:9+50\cdot2-3^4\)
\(=4+100-81\)
\(=23\)
\(48:4+3^9:3^7+5^0=12+3^2+1=12+9+1=22\)
\(\left(5^{19}:5^{17}+3\right):7=\left(5^2+3\right):7=\left(25+3\right):7=28:7=4\)
\(295-\left(31-2^2.5^2\right)=295-\left(31-10^2\right)=295-\left(31-100\right)=295-\left(-69\right)=364\)
\(6^2:9+50.2-3^3.3=36:9+100-3^2=4+100-9=95\)
Thực hiện phép tính (Tính nhanh nếu có thể)
a) 20 : 2 2 − 5 9 : 5 8
b) ( 5 19 : 5 17 − 4 ) : 7 0
c) 295 − ( 31 − 2 2 .5 ) 2
a) 20 : 2 2 − 5 9 : 5 8 = 5 − 5 = 0
b) ( 5 19 : 5 17 − 4 ) : 7 0 = ( 5 2 − 4 ) : 1 = 21
c) 295 − ( 31 − 2 2 .5 ) 2 = 295 − 11 2 = 174
a 20:2^2 -5^9:5^8
= 20:4 - 5^1
=5-5
=0
a) 20 : 2 2 − 5 9 : 5 8 = 5 − 5 = 0.
b) ( 5 19 : 5 17 − 4 ) : 7 0 = ( 5 2 − 4 ) : 1 = 21.
c) 295 − ( 31 − 2 2 .5 ) 2 = 295 − 11 2 = 174.
;)
a) 29 – [16 + 3.(51 – 49)]
b) 5.22 + 98:72
c) 311 : 39 – 147 : 72
d) 295 – (31 – 22.5)2
718 : 716 +22.33
b: =20+98:49
=20+2
=22
c: =9-147:49
=9-3
=6
a) 513 : 510 – 25.22
b) 20 : 22 + 59 : 58
c) 100 : 52 + 7.32
d) 84 : 4 + 39 : 37 + 50
e) 29 – [16 + 3.(51 – 49)]
f) 5.22 + 98:72
g) 311 : 39 – 147 : 72
h) 295 – (31 – 22.5)2
718 : 716 +22.33
\(a)\) \(5^{13}:5^{10}-25.2^2=5^3-25.4=125-100=25\)
\(b)\) \(20:2^2+5^9:5^8=20:4+5^1=5+5=10\)
\(c)\) \(100:5^2+7.3^2=100:25+7.9=4+36=40\)
\(d)\) \(84:4+3^9:3^7+5^0=84:4+3^2+1=21+9+1=31\)
\(e)\)
\(29-\left[16+3.\left(51-49\right)\right]=29-\left[16+3.2\right]=29-\left[16+6\right]=29-22=7\)
\(f)\) \(5.2^2+98:7^2=5.4+98:49=20+2=22\)
\(g)\) \(3^{11}:3^9-147:7^2=3^2-147:49=9-3=6\)
\(295-\left(31-2^2.5\right)^2=295-\left(31-4.5\right)^2=295-\left(31-20\right)^2=295-11^2=295-121=174\)
\(7^{18}:7^{16}+2^2.3^2=7^2+4.9=49+36=85\)
a: \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^3-25\cdot4\)
=125-100
=25
b: \(20:2^2+5^9:5^8\)
\(=20:4+5\)
=5+5
=10
295 - ( 31 - 22 . 5 )2
295 - ( 31 - 22 . 5 )2
= 295 - ( 31 - 4 . 5 )2
= 295 - 112
= 295 - 121
= 174
295 – (31 – 2 ngũ 2 .5)ngũ 2
295 - (31 - 22 x 5)2
= 295 - (31 - 4 x 5)2
= 295 - (31 - 20)2
=295 - 112
=295 - 121
=174
Chúc bạn học tốt nha!
=295 – (31 – 4 .5 ) ngũ 2
=295 – 11 ngũ 2
=295 – 121
=174
295-[31-2 mũ 2 . 3 mũ 3]