tìm x thuộc Z biết :
a) ( x - 5 ) . ( 8 - x ) > 0
b) ( x2 - 15 ) . ( x2 - 21 ) > 0
Bài 1 : Tìm x thuộc Z, sao cho :
a) ( x - 1 ) ( x - 3 ) > = 0
b) ( x - 5 ) ( x - 7 ) < 0
c) ( x2 - 1 ) ( x2 - 4 ) < 0
Bài 2 : Cho a là số nguyên âm. So sánh :
( -7 ) a và ( -22 ) a
So sánh :
15 ( a - 5 ) và 14 ( a - 5 )
Bài 3 : Tìm x,y thuộc Z, biết :
a) x . y = -21
b) ( 2x - 1 ) ( 2y+ 1 ) = -25
Hơi nhiều nên các bạn cố gắng giúp mình xíu, Thanks !!!
Tìm x biết: x thuộc Z và ( x 2 - 5 ) . ( x 2 - 24 ) < 0
Bài 7. Tìm x,biết:
a) x-3x2=0 e) 5x(3x-1)+x(3x-1)-2(3x-1)=0
b) (x+3)2-x(x-2)=13 c) (x-4)2-36=0
d) x2-7x+12=0 g) x2-2018x-2019=0
Bài 8. Tìm x, biết
a) (2x-1)2=(x+5)2 b) x2-x+1/4
c) 4x4-101x2+25=0 d) x3-3x2+9x-91=0
Tìm x thuộc Z biết (x - 13)( x 2 + 8) = 0
Tìm x :
a, (–31) . (x +7)=0 b, (8 – x) . (x + 13) = 0 c,(x2– 25) . (3– x )=0 d, ( x - 3 ) (x2+4) =0 |
\(a,\left(-31\right).\left(x+7\right)=0\\ \Rightarrow x+7=0\\ \Rightarrow x=-7\\ b,\left(8-x\right).\left(x+13\right)=0\\ \Rightarrow\left[{}\begin{matrix}8-x=0\\x+13=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=8\\x=-13\end{matrix}\right.\\ c,\left(x^2-25\right)\left(3-x\right)=0\\ \Rightarrow\left(x-5\right)\left(x+5\right)\left(3-x\right)=0\\\Rightarrow \left[{}\begin{matrix}x-5=0\\x+5=0\\3-x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=-5\\x=3\end{matrix}\right.\\ d,\left(x-3\right)\left(x^2+4\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-3=0\\x^2+4=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x^2=-4\left(loại\right)\end{matrix}\right.\\ \Rightarrow x=3\)
a, (–31) . (x +7)=0
<=> x +7 = 0
<=> x = -7
Vậy x \(\in\left\{-7\right\}\)
b, (8 – x) . (x + 13) = 0
<=> \(\left[{}\begin{matrix}8-x=0\\x+13=0\end{matrix}\right.\) <=> \(\left[{}\begin{matrix}x=8\\x=-13\end{matrix}\right.\)
Vậy x \(\in\left\{8;-13\right\}\)
c,(x2– 25) . (3– x )=0
<=> (x - 5) (x + 5) (3 - x) = 0
<=> \(\left[{}\begin{matrix}x-5=0\\x+5=0\\3-x=0\end{matrix}\right.\) <=> \(\left[{}\begin{matrix}x=5\\x=-5\\x=3\end{matrix}\right.\)
Vậy x \(\in\left\{5;-5;3\right\}\)
d, ( x - 3 ) (x2 + 4) = 0
<=> \(\left[{}\begin{matrix}x-3=0\\x^2+4=0\end{matrix}\right.\) <=> \(\left[{}\begin{matrix}x=3\\x^2=-4\end{matrix}\right.\)(vô lý)
Vậy x \(\in\left\{3\right\}\)
Tìm x thuộc Z biết a) x ( x - 3) = 0; b) x ( x + 9) = 0 c) ( x + 1) ( x - 1) = 0 d) ( x - 13) ( x 2 + 8) = 0
Tìm x thuộc Z biết: a) x (x - 7) = 0; b) x (x + 11) = 0; c) (x + 8) (x - 12) = 0; d) (x - 3) ( x 2 + 3) = 0;
Bài 2: Tìm x, biết:
a) 4x(x + 1) = 8( x + 1) c) x2 – 6x + 8 = 0
b) x3 + x2 + x + 1 = 0 d) x3 – 7x – 6 = 0
\(a,\Leftrightarrow\left(4x-8\right)\left(x+1\right)=0\\ \Leftrightarrow4\left(x-2\right)\left(x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\\ b,\Leftrightarrow\left(x+1\right)\left(x^2+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-1\\x^2=-1\left(vô.lí\right)\end{matrix}\right.\Leftrightarrow x=-1\\ c,\Leftrightarrow x^2-2x-4x+8=0\\ \Leftrightarrow\left(x-2\right)\left(x-4\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=4\end{matrix}\right.\\ d,\Leftrightarrow x^3-3x^2+3x-9x+2x-6=0\\ \Leftrightarrow\left(x-3\right)\left(x^2+3x+2\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x^2+x+2x+2\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x+1\right)\left(x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\\x=-2\end{matrix}\right.\)
a) \(\Rightarrow4\left(x+1\right)\left(x-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)
b) \(\Rightarrow x^2\left(x+1\right)+\left(x+1\right)=0\)
\(\Rightarrow\left(x+1\right)\left(x^2+1\right)=0\)
\(\Rightarrow x=-1\left(do.x^2+1\ge1>0\right)\)
c) \(\Rightarrow x\left(x-4\right)-2\left(x-4\right)=0\)
\(\Rightarrow\left(x-4\right)\left(x-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\)
d) \(\Rightarrow x^2\left(x-3\right)+3x\left(x-3\right)+2\left(x-3\right)\)
\(\Rightarrow\left(x-3\right)\left(x^2+3x+2\right)=0\)
\(\Rightarrow\left(x-3\right)\left(x+1\right)\left(x+2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-2\\x=-1\end{matrix}\right.\)
Tìm x thuộc Z biết
a) 11+(15-2x)=0
b)-129-(35-x)=55
c)27-2.5^x-2=5^8:5^6
cíu mik zới , mai mik phải nộp bài r
1: =>15-2x=-11
=>2x=26
hay x=13