a) 927 – 10 x 2 = 927 – 20

                   = 907

b) 163 + 90 : 3 = 163 + 30

                   = 193

c) 90 + 10 x 2 = 90 + 20

                   = 110

d) 106 – 80 : 4 = 106 – 20

                   = 86

Cái này dễ mak bn, bấm máy tính là ra thôi chứ hỏi lm j cho tốn công ạ?

Kq = 24790

\(\left(x^2+3^2\right).10+90=220\\ \Rightarrow\left(x^2+9\right).10=130\\ \Rightarrow x^2+9=13\\ \Rightarrow x^2=4\\ \Rightarrow x^2=2^2\\ \Rightarrow x=2.\)

Cần ghi rõ dấu.

dấu ^ là mũ

a) 89 + 10 x 2 = 89 + 20

                   = 109

b) 25 x 2 + 78 = 50 + 78

                   = 128

c) 46 + 77 x 2 = 46 + 14

                   = 60

d) 35 x 2 + 90 = 70 + 90

                   = 160

1.

\(\Leftrightarrow2sinx.cosx+2cosx=0\)

\(\Leftrightarrow2cosx\left(sinx+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}cosx=0\\sinx=-1\end{matrix}\right.\)

\(\Leftrightarrow cosx=0\) (do \(cosx=0\Leftrightarrow sinx=\pm1\) bao hàm luôn cả pt \(sinx=-1\))

\(\Leftrightarrow x=\dfrac{\pi}{2}+k\pi\)

2.

\(\Leftrightarrow\left[{}\begin{matrix}2x-10^0=60^0+k360^0\\2x-10^0=120^0+n360^0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=35^0+k180^0\\x=65^0+n180^0\end{matrix}\right.\)

Do \(-120^0< x< 90^0\Rightarrow\left\{{}\begin{matrix}-120^0< 35^0+k180^0< 90^0\\-120^0< 65^0+n180^0< 90^0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}k=0\\n=\left\{-1;0\right\}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=35^0\\x=-115^0\\x=65^0\end{matrix}\right.\)

3. Làm tương tự câu 2

4.

\(\Leftrightarrow\dfrac{1}{2}-\dfrac{1}{2}cos\left(10x+\dfrac{4\pi}{5}\right)-\left(\dfrac{1}{2}+\dfrac{1}{2}cos\left(\dfrac{x}{2}-2\pi\right)\right)=0\)

\(\Leftrightarrow cos\left(10x+\dfrac{4\pi}{5}\right)+cos\left(\dfrac{x}{2}-2\pi\right)=0\)

\(\Leftrightarrow cos\left(10x+\dfrac{4\pi}{5}\right)+cos\left(\dfrac{x}{2}\right)=0\)

\(\Leftrightarrow cos\left(10x+\dfrac{4\pi}{5}\right)=-cos\left(\dfrac{x}{2}\right)=cos\left(\pi-\dfrac{x}{2}\right)\)

\(\Leftrightarrow\left[{}\begin{matrix}10x+\dfrac{4\pi}{5}=\pi-\dfrac{x}{2}+k2\pi\\10x+\dfrac{4\pi}{5}=\dfrac{x}{2}-\pi+k2\pi\end{matrix}\right.\)

\(\Leftrightarrow...\)

toán lớp 5

2 x X + 68 = 126

2 x X = 126 - 68

2 x X = 58

      x = 58 : 2

      x = 29

a) \(2\times x+68=126\)

\(\Rightarrow2\times x=58\)

\(\Rightarrow x=29\)

b) \(3\times x-24=90\)

\(\Rightarrow3\times x=123\)

\(\Rightarrow x=41\)

c) \(84-4\times x=16\)

\(\Rightarrow4\times x=84-16=68\)

\(\Rightarrow x=17\)

d) \(\left(5\times x+10\right)+35=70\)

\(\left(5\times x+10\right)=70-35\)

\(\Rightarrow5\times x+10=35\)

\(\Rightarrow5\times x=25\)

\(\Leftrightarrow x=5\)

e) Tương tự d

f) Thiếu kết quả của đề

g)  \(45-\left(3\times x-9\right)=15\)

\(\Rightarrow(3\times x-9)=45-15\)

\(\Rightarrow3\times x-9=30\)

\(\Rightarrow3\times x=39\)

\(\Rightarrow x=13\)

-- Các câu còn lại tương tự câu g

30 : 5 x 2 - 10 + 90

= 6 x 2 - 10 + 90

= 12 - 10 + 90

= 2 + 90

= 92

92 bạn nhé

k đúng nha

30 : 5 x 2 - 10 + 90

= 6 x 2 - 10 + 90

= 12 - 10 + 90

= 2 + 90 = 92

a)   6 + 2x = 12 +(-5)

     2x = 7 -6

    x = 1/2

b)  -90 - |x| -10 + 100 = 0

            - |x| =0

               x =0