\(1\frac{1}{3}\cdot x+16\frac{3}{4}=13,25\)

\(\frac{4}{3}\cdot x=13,25-16\frac{3}{4}\)

\(\frac{4}{3}\cdot x=-3,5\)

\(x=-3,5:\frac{4}{3}\)

\(x=-2,625\)

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

<=> \(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)\(\frac{10}{3}x=-\frac{53}{4}-\frac{67}{4}\)=> \(\frac{10}{3}x=-\frac{120}{4}=-30\)

<=> X=(-3)*3  => X=-9

Đáp số: x=-9

\(3\frac{1}{3}y+16\frac{3}{4}=13,25\)

\(\Rightarrow\frac{10}{3}y+\frac{67}{4}=13\frac{1}{4}\)

\(\Rightarrow\frac{10}{3}y+\frac{67}{4}=\frac{53}{4}\)

\(\Rightarrow\frac{10}{3}y=\frac{53}{4}-\frac{67}{4}\)

\(\Rightarrow\frac{10}{3}y=\frac{-14}{4}\)

\(\Rightarrow y=-\frac{14}{4}:\frac{10}{3}\)

\(\Rightarrow y=-\frac{14}{4}.\frac{3}{10}\)

\(\Rightarrow y=\frac{-21}{20}\)

Chúc bạn học tốt !!! 

10/3 .y+ 67/4=1325/100

10/3.y=-7/2

y=-7/60

@tiến dũng bn lm sai r nhé!

nhanh giúp mk ạ

\(13,25:0,75+13,25:0,25+13,5:0,325\)

\(=13,25:\left(0,75+0,25+0,325\right)\)

\(=13,25:1,325\)

\(=10\)

\(\dfrac{1}{4}:0,25-\dfrac{1}{8}:0,125+\dfrac{1}{2}:0,5-\dfrac{1}{16}:0,0625\)

\(=\dfrac{1}{4}:\dfrac{1}{4}-\dfrac{1}{8}:\dfrac{1}{8}+\dfrac{1}{2}:\dfrac{1}{2}-\dfrac{1}{16}:\dfrac{1}{16}\)

\(=1-1+1-1\)

\(=0\)

\(a,13,25:0,75+13,75:0,25+13,75:0,325\\ =13,25:\left(0,75+0,25+0,325\right)\\ =13,25:1,325\\ =10\\ b,\dfrac{1}{4}:0,25-\dfrac{1}{8}:0,125+\dfrac{1}{2}:0,5-\dfrac{1}{16}:0,0625\\ =\dfrac{1}{4}:\dfrac{1}{4}-\dfrac{1}{8}:\dfrac{1}{8}+\dfrac{1}{2}:\dfrac{1}{2}-\dfrac{1}{16}:\dfrac{1}{16}\\ =1-1+1-1\\ =0\)

a) \(x-\dfrac{5}{6}=\dfrac{1}{2}\)

           \(x=\dfrac{1}{2}+\dfrac{5}{6}\)

           \(x=\dfrac{4}{3}\)

vậy x = ....

b) \(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)

    \(\dfrac{10}{3}\)\(x+\dfrac{67}{4}=-13,25\)

     \(\dfrac{10}{3}x=\left(-13,25\right)-\dfrac{67}{4}\)

      \(\dfrac{10}{3}x=-30\)

          \(x=\left(-30\right):\dfrac{10}{3}\)

         \(x=-9\)

vậy x =...

sai mog bn thông cảm!!!

Lời giải:

a. $y+30\text{%}y=-1,3$

$y+0,3y=-1,3$

$y(1+0,3)=-1,3$

$y.1,3=-1,3$

$y=(-1,3):1,3=-1$

b.

$y-25\text{%}y=\frac{1}{2}$

$y-0,25y=0,5$

$y(1-0,25)=0,5$

$y.0,75=0,5$

$y=0,5:0,75=\frac{2}{3}$

c.

\(3+\frac{1}{3}y+16+\frac{3}{4}=-13,25\)

$\frac{1}{3}y+19,75=-13,25$
$\frac{1}{3}y=-13,25-19,75=-33$
$y=-33:\frac{1}{3}=-99$

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

\(\Leftrightarrow\frac{3\times3+1}{3}x+\frac{16\times4+3}{4}=-13,25\)

\(\Leftrightarrow\frac{9+1}{3}x+\frac{64+3}{4}=-13,25\)

\(\Leftrightarrow\frac{10}{3}x+\frac{67}{4}=-13,25\)

\(\Leftrightarrow\frac{10}{3}x+16,75=-13,25\)

\(\Leftrightarrow\frac{10}{3}x=-13,25-16,75\)

\(\Leftrightarrow\frac{10}{3}x=-30\)

\(\Leftrightarrow x=-30\div\frac{10}{3}\)

\(\Leftrightarrow x=\frac{-30}{1}\times\frac{3}{10}\)

\(\Leftrightarrow x=\frac{-90}{10}\)

\(\Leftrightarrow x=-9\)