a) \(\left(5x+3^4\right).6^8=6^9.3^4\)

\(=>6x+3^4=3^4.6^9:6^8\)

\(=>6x+3^4=3^4.6\)

\(=>6x=6.3^4-3^4\)

\(=>6x=0\)

\(=>x=0:6\)

\(=>x=0\)

a/(5x + 3⁴).6⁸=6⁹.3⁴

   (5x + 3⁴) = 6⁹:6⁸.3⁴

   5x + 81 = 6.81

   5x = 6.81 - 81

   5x = 486 - 81

   5x = 425

   x = 425:5

   x = 85

b/92 - 2x = 2.4²- 3.4 + 120:15
   92 - 2x = 2.16 - 12 + 8

   92 - 2x = 32 - 12 + 8

   92 - 2x = 28

   2x = 92 - 28

   2x = 64

   x = 64:2

   x = 32

c/5³.(3x + 2) : 13 = 10³: (13⁵:13⁴)

  125.(3x + 2) : 13 = 1000:13 

  125.(3x+2) = 1000:13.13

  125.(3x+2) = 1000

   3x + 2 = 1000:125

   3x + 2 = 8

   3x = 8 - 2

   3x = 6

   x = 6:3

   x = 2

Bạn nhớ tick cho mình nhé!

a/(5x + 34).68=69.34

   (5x + 34) = 69:68.34

   5x + 81 = 6.81

   5x = 6.81 - 81

   5x = 486 - 81

   5x = 405

   x = 405:5

   x = 81

b/92 - 2x = 2.42- 3.4 + 120:15
   92 - 2x = 2.16 - 12 + 8

   92 - 2x = 32 - 12 + 8

   92 - 2x = 28

   2x = 92 - 28

   2x = 64

   x = 64:2

   x = 32

c/53.(3x + 2) : 13 = 103: (135:134)

  125.(3x + 2) : 13 = 1000:13 

  125.(3x+2) = 1000:13.13

  125.(3x+2) = 1000

   3x + 2 = 1000:125

   3x + 2 = 8

   3x = 8 - 2

   3x = 6

   x = 6:3

   x = 2

Cái này mới đúng

Bạn nhớ tick cho mình nhé!

\(2^x+3\cdot2^x=9\cdot2^9\)

\(\Rightarrow2^x\cdot\left(1+3\right)=9\cdot2^9\)

\(\Rightarrow2^x\cdot4=9\cdot2^9\)

\(\Rightarrow2^x=\dfrac{9\cdot2^9}{4}\)

\(\Rightarrow2^x=9\cdot2^7\)

Xem lại đề ! 

\(\frac{2}{5}.\frac{1}{x}+\frac{1}{x}.2+\frac{2}{5}=0,5\)

\(\Rightarrow\frac{2}{5x}+\frac{2}{x}+\frac{2}{5}=\frac{1}{2}\)

\(\Rightarrow2.\left(\frac{1}{5x}+\frac{1}{x}+\frac{1}{5}\right)=\frac{1}{2}\)

\(\Rightarrow\frac{1}{5x}+\frac{5}{5x}+\frac{x}{5x}=\frac{1}{2}:2=\frac{1}{4}\)

\(\Rightarrow\frac{1+5+x}{5x}=\frac{1}{4}\)

\(\Rightarrow4.\left(1+5+x\right)=5x\)

\(\Rightarrow4+20+4x=5x\)

\(\Rightarrow24+4x=5x\)

\(\Rightarrow5x-4x=24\)

\(\Rightarrow x=24\)

Trả lời

2/5.1/x+1/x.2+2/5=0,5

1/x.(2/5+2)+2/5   =1/2

1/x.12/5+2/5        =1/2

1/x.12/5               =1/2-2/5

1/x.12/5               =1/10

1/x                       =1/10:12/5

1/x                       =1/24.

Hình như mk làm sai !

\(\frac{2}{5}.\frac{1}{x}+\frac{1}{x}.2+\frac{2}{5}=0,5\)

\(\Rightarrow\frac{1}{x}\left(\frac{2}{5}+\frac{4}{2}\right)=\frac{1}{2}-\frac{2}{5}\)

\(\Rightarrow\frac{1}{x}.\frac{12}{5}=\frac{1}{10}\)

\(\Rightarrow\frac{1}{x}=\frac{1}{24}\)

\(\Rightarrow x=24\)

~Study well~

em ko biết

Có bị lạc đề ko dzậy?!

Phần e, 17-{-x-[-x-(-x)]}=-16 nha mn, chỗ này thiếu:))

1,25.x-0,75.x=2.25-1

0.5.x=1.25

x=2,5

2.5 bàn nha

a) x - (-3) + 5 = -8                        c) |x| - 5 = 0

=> x + 3 + 5 = -8                        => |x| = 5

=> x + 8 = -8                              => \(\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)

=> x = -8 - 8                    Vậy ...

=> x = -16

b) 20 - (3 - x) = 2x - 4             d) |5 - x| + (-4) = 8

=> 20 - 3 + x = 2x - 4             => |5 - x| = 8 + 4

=> 17 + x = 2x - 4                  => |5 - x| = 12

=> 17 + 4 = 2x - x                  => \(\orbr{\begin{cases}5-x=12\\5-x=-12\end{cases}}\)

=> x = 21                              => \(\orbr{\begin{cases}x=-7\\x=17\end{cases}}\)

\(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+.......+\dfrac{1}{x\cdot\left(x+1\right)}=\dfrac{122}{123}\)

\(\Leftrightarrow1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......+\dfrac{1}{x}-\dfrac{1}{x+1}=\dfrac{122}{123}\)

\(\Leftrightarrow1-\dfrac{1}{x+1}=\dfrac{122}{123}\)

\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{123}\)

\(\Leftrightarrow x=122\)

I don't know

Trả lời

A.12:(x+4).3=6

    12:(x+4)   =6:3

    12:(x+4)   =2

         x+4     =12:2

         x+4     =6

         x         =6-4

         x         =2

a) 12 : (x + 4).3 = 6

\(\frac{12}{\left(x+4\right)}.3=6\)

\(\frac{36}{\left(x+4\right)}=6\)

x + 4 = 36 : 6

x + 4 = 6

x = 6 - 4

x = 2

b) 12 : (x + 4).3 = 5

\(\frac{12}{\left(x+4\right)}.3=5\)

\(\frac{36}{\left(x+4\right)}=5\)

x + 4 = 36 : 5

x + 4 = \(\frac{36}{5}\)

x = \(\frac{36}{5}\) - 4

x = \(\frac{16}{5}\)

c) 12 : (x + 4).3 + 18 = 24

\(\frac{12}{\left(x+4\right)}.3+18=24\)

\(\frac{18x+108}{x+4}=24\)

18x + 108 = 24x + 96

18x + 108 - 24x = 96

-6x + 108 = 96

-6x = 96 - 108

-6x = -12

x = -12 : -6

x = 2

a) 12 : (x + 4) . 3 = 6

=>(x + 4) . 3 = 12 : 6

=> (x + 4) . 3 = 2

=> x + 4         = 2 . 3

=> x + 4         = 6

=> x               = 2

b) 12 : (x + 4) . 2 = 5 

    12 : (x + 4)      = 5 : 2

     12 : (x + 4)     = 2,5

             x + 4      = 12 : 2,5

             x + 4      = 4,8

             x             = 0,8

c) 12 : (x + 4) . 3 + 18 = 24

=>12 : (x + 4) . 3          = 42

=> 12 : (x + 4)              = 42 : 3

=> 12 : (x + 4)              = 14

=>         x + 4                = 12 : 14

=>         x + 4                 = 6/7

=>          x                       = 6/7 - 4

=>          x                       = -22/7

a) \(215+x=400\)

\(\Rightarrow x=400-215\)

\(\Rightarrow x=185\)

b) \(12,5-2x=\dfrac{1}{5}\)

\(\Rightarrow2x=12,5-\dfrac{1}{5}\)

\(\Rightarrow2x=\dfrac{123}{10}\)

\(\Rightarrow x=\dfrac{123}{10}:2\)

\(\Rightarrow x=\dfrac{123}{20}\)

còn câu c d nhanh cậu ơi

Bạn xem lại đề phần e nha .

\(c)x.0,25-\dfrac{3}{25}:x=2\dfrac{1}{4}\)

\(x.0,25-\dfrac{25}{3}.x=\dfrac{9}{4}\)

\(x.\left(0,25-\dfrac{25}{3}\right)=\dfrac{9}{4}\)

\(x.\dfrac{-97}{12}=\dfrac{9}{4}\)

\(x=\dfrac{-27}{97}\)

\(d)\left(x-\dfrac{1}{3}\right).\left(x-\dfrac{1}{4}\right)=0\)

Do : 2 số đó nhân với nhau bằng 0 nên một trong 2 số là số 0.

Do đó :

\(Th1:x-\dfrac{1}{3}=0\)

\(x=\dfrac{1}{3}\)

\(Th2:x-\dfrac{1}{4}=0\)

\(x=\dfrac{1}{4}\)