Tìm x:
a,4872:3+x=3584
b,7565+3846-x=5555
Tìm X biết :
X + 7489 = 7565
......................................................................................................................................................
Đáp án:
X + 7489 = 7565
X = 7565 – 7489
X = 76
Tìm X biết: X + 7489 = 7565
Tìm X biết: X + 7489 = 7565
Tìm X biết :
X + 7489 = 7565
Tìm X biết :
a. X + 7489 = 7565
b. X - 2428 = 1266.
Tìm X biết :
a. X + 7489 = 7565
b. X - 2428 = 1266
a. X + 7489 = 7565
X = 7565 – 7489
X = 76
b. X - 2428 = 1266
X = 2428 + 1266
X = 3694
Tìm x:[2014:(x-1)]+1/4*[(5555/1212)+(5555/2020)+(5555/3030)+(5555/4242)]=76/21
Tìm x:
a) x * 2 + x * 3 = 60
b) x * 15 – x * 9 = 78
a) x * 2 + x * 3 = 60
x * ( 2 + 3 ) = 60
x = 60 : 5
x = 12
b) x * 15 - x * 9 = 78
x * ( 15 - 9 ) = 78
x = 78 : 6
x = 13
Tìm x:
a) (x-8)(x3+8)=0
b) (4x-3)-(x+5) =3(10-x)
a) `(x-8)(x^3+8)=0`
`<=>(x-8)(x+2)(x^2-2x+4)=0`
`<=>` \(\left[ \begin{array}{l}x=8\\x=-2\end{array} \right.\) (Vì `x^2-2x+4 \ne 0 forall x)`
Vậy `A={8;-2}`.
b) `(4x-3)-(x+5)=3(10-x)`
`,=>4x-3-x-5=30-3x`
`<=>3x-8=30-3x`
`<=>6x=38`
`<=>x=19/3`
Vậy `S={19/3}`.
Tìm x:
a) X x 3 x 5 = 2,7 b) 1,2 : X x 4 = 20
a: \(x\cdot3\cdot5=2,7\)
=>\(x\cdot15=2,7\)
=>\(x=\dfrac{2,7}{15}=0,18\)
b: \(1,2:x\cdot4=20\)
=>\(1,2:x=20:4=5\)
=>\(x=1,2:5=0,24\)