Ta có : \(11^{1979}< 11^{1980}=\left(11^3\right)^{660}=1331^{660}\)

            \(37^{1320}=\left(37^2\right)^{660}=1329^{660}\)

Vì \(1329^{660}>1331^{660}\) nên \(11^{1979}< 37^{1320}\)

11¹⁹⁷⁹<11¹⁹⁸⁰=1331⁶⁶⁰

37¹³²⁰=1369⁶⁶⁰

Vì 1369⁶⁶⁰>1331⁶⁶⁰ nên 37¹³²⁰>11¹⁹⁷⁹

a)  − 3 11 = − 39 143 ; − 4 13 = − 44 143 ; − 39 143 > − 44 143 ⇒ − 3 11 > − 4 13

b)  − 63 70 = − 9 10

− 9 10 = − 27 30 ; − 5 6 = − 25 30 ⇒ − 5 6 > − 63 70

\(a=\left[\left(-\dfrac{1}{2}\right)^5\right]^{107}=\left(-\dfrac{1}{32}\right)^{107}\)

\(b=\left[\left(-\dfrac{1}{3}\right)^3\right]^{107}=\left(-\dfrac{1}{27}\right)^{107}\)

mà -1/32>-1/27

nên a>b

a>b

`#3107.101107`

`a)`

Ta có:

\(\dfrac{2727}{3131}=\dfrac{2727\div27}{3131\div31}=\dfrac{27}{31}\)

Vì \(\dfrac{27}{31}=\dfrac{27}{31}\)

\(\Rightarrow\dfrac{27}{31}=\dfrac{2727}{3131}\)

`b)`

Ta có:

\(\dfrac{11}{31}=1-\dfrac{20}{31}=1-\dfrac{200}{310}\)

\(\dfrac{111}{311}=1-\dfrac{200}{311}\)

Vì \(\dfrac{200}{310}>\dfrac{200}{311}\)

\(\Rightarrow1-\dfrac{200}{310}< 1-\dfrac{200}{311}\)

\(\Rightarrow\dfrac{11}{31}< \dfrac{111}{311}.\)

27/31 = 2727/3131

11/31 bé hơn 111/311

a: \(2^{300}=8^{100}\)

\(3^{200}=9^{100}\)

mà 8<9

nên \(2^{300}< 3^{200}\)

b: \(3^{500}=243^{100}\)

\(7^{300}=343^{100}\)

mà 243<243

nên \(3^{500}< 7^{300}\)

\(\dfrac{11}{31}\) và \(\dfrac{111}{311}\)

\(\dfrac{11}{31}\) = \(\dfrac{11\times10}{31\times10}\) = \(\dfrac{110}{310}\) = 1 - \(\dfrac{200}{310}\) 

\(\dfrac{111}{311}\) = 1 - \(\dfrac{200}{311}\)  

Vì \(\dfrac{200}{310}\) > \(\dfrac{200}{311}\)

Nên \(\dfrac{11}{31}\)  < \(\dfrac{111}{311}\)

\(\dfrac{11}{31}=\dfrac{11x311}{31x311}=\dfrac{3421}{31x311}\)

\(\dfrac{111}{311}=\dfrac{111x31}{31x311}=\dfrac{3441}{31x311}\)

mà \(\dfrac{3421}{31x311}< \dfrac{3441}{31x311}\)

\(\Rightarrow\dfrac{11}{31}< \dfrac{111}{311}\)

\(Cảmơncácbạn\)☺

\(\frac{72}{167}>\frac{71}{169}\)

\(\frac{63}{314}< \frac{65}{321}\)

\(\frac{25}{101}< \frac{46}{180}\)

\(a,\\ Ta.có:\dfrac{16}{-19}< 0;\dfrac{15}{17}>0\\ \Rightarrow\dfrac{16}{-19}< \dfrac{15}{17}\\ b,\\ Ta.có:\dfrac{419}{-723}< 0;\dfrac{-697}{-313}>0\\ \Rightarrow\dfrac{419}{-723}< \dfrac{-697}{-313}\\ c,\dfrac{311}{256}>\dfrac{256}{256}=1;\dfrac{199}{293}< \dfrac{203}{203}=1\\ \Rightarrow\dfrac{311}{256}>\dfrac{199}{203}\)